What is 3.25 with the 5 repeating as a rational number

Answers

Answer 1

Answer: So,

$3.2\overline{5}$

Multiply it by 100.

$3.2\overline{5}--\ \textgreater \ 325.5\overline{5}$ .

We now know that $325.5\overline{5}$ is 100 times of $3.2\overline{5}$ . If we subtract the first from the second, we will get 99 of the number. Then, we can simply divide by 99 and we will have it in fraction form.

$325.5\overline{5}-3.2\overline{5}=322.3$

Now, we put it over 99.

$(322.3)/(99)$

Of course, we cannot have decimals in fraction form, so we will just fix that.

$(3223)/(990)= (11*293)/(2*3*3*5*11)=(293)/(2*3*3*5)=(293)/(90)\ or\ 3 (23)/(90)$

Answer 2

Answer: 322 over 99 is your answer. Hope this helps!

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Answers

Any parallelogram that's not a rectangle meets those qualifications.

Start with a rectangle made out of popsicle sticks or stiff wire.
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How do you write this equation in y=ax^2+bx+c ?

Answers

Step-by-step explanation:

y = (x-1)(2x-1)

= x(2x-1) -1(2x-1)

= 2x^2 - x - 2x + 1

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Give a number you can cube to give an answer bigger than 600 but smaller than 800.Please give the correct answer and it needs to be easy to understand.
thx :D

Answers

Any number between 8.434 and 9.283 will do the job.

The only whole number that can do it is 9 .

8 cubed = 512 too small
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A metal rod is placed in a rectangular box as shown in the figure. How long is the rod? Round your answer to the nearest tenth of an inch, if necessary. A. 5.0 in. B. 12.1 in. C. 13.4 in. D. 14.2 in.

Answers

fist we find the legnth of the diagonal
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
c=5

now the other diagonal
11^2+5^2=c^2
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sqrt both sides12.083
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If n = 8 and 16 · 2^m = 4^(n – 8), then m = ?F. –4
G. –2
H. 0
J. 1
K. 8

Answers

$n = 8 , \n \n 16 \cdot 2^m = 4 ^(n - 8) \n \n 16 \cdot 2^m = 4 ^(8-8)\n \n 2^4 \cdot 2^m =(2^2 )^(0) \n \n2^(4+m)=2^0\n \n4+m=0 \n \nm=-4 \n \nAnswer : \ F. \ \ - 4$

Four runners competed in a 10 kilometer relay race. Each runner ran the same distance. What was the distance?

Answers

Ok i think they ran their own race so here goes nothing. Four runners so you need four in your problem so 4x now. Lets add the ten four ten kilometers i each race. So you final awnsere is 4x10=40 kilometers

this question doesn't make sense. are you asking how far did all 4 runners run together ??

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