Solve:-

7^5

Thanks!!!!!!!!!!!!!

Answers

Answer 1
Answer: These are exponents. To solve an exponent you need to multiply the base it self how many times its says in the power.

a² 

a = base
2 = power

7^5 = 7 × 7 × 7 × 7 × 7 = 16807
7^5 = 
16807
Answer 2
Answer: Solutions 

7^5

=7 x 7 x 7 x 7 x 7

=16807

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Answers

use the equations 300x + 225y= 217500 and x + y= 850 to solve

What is the surface area of this cylinder?Use a * 3.14 and round your answer to the nearest hundredth.
28 ft
-----------
15 ft
square feet
Submit

Answers

the answer is 2550 square feet

The minimum monthly payment for anita's credit card is 2% of her balance or $10, whichever is higher. if anita's balance at the end of her last billing cycle was $360, what is her minimum monthly payment? show your work.

Answers

Answer:


  1. Step-by-step explanation:

⇒minimum payment is 2% of her balance or 10 bucks...whichever is greater...

her balance is 360

2% of 360 =

0.02(360) = 7.20

$ 10 is greater then 7.20 so ur answer is $ 10

pls mark as brainlesttttt


Answer:

Her minimum payment would be $10.

Step-by-step explanation:

To find this, first find 2% of her statement. We can do this by multiplying the amount by the percentage.

$360 * 2% = $7.20

Now, since this is less than the given minimum, she pays the $10 minimum.

Can someone help me??

Answers

I'm not sure if this is what you mean by 'inverse', but here goes:

y = ∛(x+2)

Cube each side of the equation:

y³ = x + 2

Subtract 2 from each side:

x = y³ - 2

What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

Answers

The slope of a line that is perpendicular to a line whose equation is −2y = 3x + 7 is (2)/(3)

Solution:

Given that we have to find the slope of the line that is perpendicular to a line whose equation is −2y = 3x + 7

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y - intercept

Given equation is:

-2y = 3x + 7\n\n-y = (3)/(2)x + (7)/(2)\n\ny = (-3)/(2)x - (7)/(2)

On comparing the above equation with slope intercept form,

m = (-3)/(2)

We know that product of slope of a line and slope of line perpendicular to it is -1

Therefore,

(-3)/(2) * \text{ slope of line perpendicular to it } = -1\n\n \text{ slope of line perpendicular to it } = (2)/(3)

Thus slope of line that is perpendicular to given line is (2)/(3)

Graph y = 5x and y = log5x on a sheet of paper using the same set of axes. Use the graph to describe the domain and range of each function. Then identify the y-intercept of each function and any asymptotes of each function. Explain also.

Answers

Answer:

1) For  y=5x

A)  Domain=(-\infty,\infty) [ \left.\begin{matrix}x\end{matrix}\right|x\varepsilon \mathbb{R}]

B) Range= (-\infty,\infty) [ \left.\begin{matrix}y\end{matrix}\right|y\varepsilon \mathbb{R}]

C) y-intercept = 0

D) Asymptote= No asymptote

2) For   y=log_5x

A)  Domain=Domain=  (0,\infty) [ \left.\begin{matrix}x\end{matrix}\right|x>0]

B) Range= (-\infty,\infty) [ \left.\begin{matrix}y\end{matrix}\right|y\varepsilon \mathbb{R}]

C) y-intercept =  None

D) Vertical Asymptote:   x=0

Step-by-step explanation:

Given : y=5x and y=log_5x

Refer the graph attached.

1)  In equation (1)  y=5x

The domain is the set of all possible values in which function is defined.  

y=5x is a linear polynomial defined on all real numbers.

Domain=(-\infty,\infty) [ \left.\begin{matrix}x\end{matrix}\right|x\varepsilon \mathbb{R}]

Range is the set of all values that function takes.

It also include all real numbers.

Range= (-\infty,\infty) [ \left.\begin{matrix}y\end{matrix}\right|y\varepsilon \mathbb{R}]

→y-intercept- Value of y at the point where the line crosses the y axis.

put x=0 in equation y=5x we get, y=0

Therefore, y-intercept = 0 (We can see in the graph also)

→An asymptote is a line that a curve approaches, but never touches.

Asymptote= No asymptote

2) Now in equation (2) y=log_5x

Domain=  (0,\infty) [ \left.\begin{matrix}x\end{matrix}\right|x>0]

because log function is not defined in negative.

Range=  (-\infty,\infty) [ \left.\begin{matrix}y\end{matrix}\right|y\varepsilon \mathbb{R}]

y-intercept - None

Vertical Asymptote:   x=0

1)

A)  Domain= (-∞, ∞) for all x

B) Range= (-∞, ∞) for all y

C) y-intercept = 0

D) Asymptote= No asymptote

2)

A)  Domain=(0, ∞) for all x > 0

B) Range= (-∞, ∞) for all y

C) y-intercept =  None

D) Vertical Asymptote:   x=0

Here, we have,

Function 1: y = 5x

Domain: The domain of this function is all real numbers because there are no restrictions on the values that x can take.

Range: The range of this function is also all real numbers because for every value of x, we can find a corresponding y value by multiplying it by 5.

Y-intercept: To find the y-intercept, we set x = 0 and solve for y. Substituting x = 0 into the equation, we get y = 5(0) = 0. Therefore, the y-intercept is (0, 0).

Asymptotes: There are no asymptotes in this linear function.

Function 2: y = log₅x

Domain: The domain of this function is all positive real numbers because the logarithm function is only defined for positive values of x.

Range: The range of this function is all real numbers because the logarithm function can produce any real number output.

Y-intercept: To find the y-intercept, we set x = 1 and solve for y. Substituting x = 1 into the equation, we get y = log₅(1) = 0. Therefore, the y-intercept is (0, 0).

Asymptotes: The logarithmic function has a vertical asymptote at x = 0 because the logarithm is undefined for x ≤ 0. Additionally, there is no horizontal asymptote.

When plotting these functions on the same set of axes, we will observe that the graph of y = 5x is a straight line passing through the origin (0, 0) with a slope of 5.

The graph of y = log₅x will appear as a curve that starts at the point (1, 0) and approaches the vertical asymptote x = 0 as x approaches zero.

The two graphs will intersect at the point (1, 0) because log₅1 = 0.

To learn more on function click:

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