What is the greatest common factor of 12 and 90?

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Answer 1

Answer: The first step to find the gcf of 12 and 90 is to list the factors of each number. The factors of 12 are 1, 2, 3, 4, 6 and 12. The factors of 90 are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45 and 90. So the greatest common factor is 90 Buddy.

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Gary took 7 hours to mow 4 lawns, then at that rate, how many lawns could be mowed in 35 hours. using a double number line

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Answer: 20 lawns

Step-by-step explanation:

35÷7=5

5×4=20

Consider the following hypothesis test. The following data are from matched samples taken from two populations. Population Element 1 2 1 21 20 2 28 26 3 18 18 4 20 20 5 26 24 Compute the difference value for each element. If your answer is "0", enter 0.a. Compose the difference valuefor each element.b. Compute d.c.Compute the standard deviation sd.d.Conduct a hypothesis test using α=.05.What is yourconclusion?

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Answer:

a) d: 1 2 0 0 2

b) $\bar d= (\sum_(i=1)^n d_i)/(n)= (5)/(5)=1$

c) $s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =1$

d) $p_v =P(t_((4))>2.236) =0.0445$

So the p value is lower than the significance level provided, so then we can conclude that we reject the null hypothesis that the difference mean between population 1 and 2 is less than 0. And we can say that the mean difference is higher than 0 at 5% of significance.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=Population 1 , y = population 2

x: 21 28 18 20 26

y: 20 26 18 20 24

a. Compose the difference valuefor each element

Let d =x-y, so the values for the difference are:

d: 1 2 0 0 2

b. Compute d.

We need the mean for the difference. If we use the following formula we got:

$\bar d= (\sum_(i=1)^n d_i)/(n)= (5)/(5)=1$

c.Compute the standard deviation sd.

For the standard deviation we can use the following formula:

$s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =1$

d.Conduct a hypothesis test using α=.05.What is yourconclusion?

If we assume that the system of hypothesis for this case are:

Null hypothesis: $\mu_x- \mu_y \leq 0$

Alternative hypothesis: $\mu_x -\mu_y > 0$

We can calculate the statistic given by :

$t=(\bar d -0)/((s_d)/(√(n)))=(1 -0)/((1)/(√(5)))=2.236$

The next step is calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_((4))>2.236) =0.0445$

Final answer:

To complete this hypothesis test, calculate the difference value for each element, compute the sample mean difference (d), calculate the standard deviation (sd), and then conduct the hypothesis test using a significance level of α = 0.05.

Explanation:

To compute the difference value for each element, subtract the second value from the first value for each pair. For example, the difference for the first pair is 1-2 = -1. Repeat this for each pair of elements in the data set.

To compute the sample mean difference (d), add up all the difference values and divide by the total number of pairs. In this case, d = (-1 + 1 + 2 + 0 + 2)/5 = 0.8.

To compute the standard deviation (sd), first calculate the squared difference value for each pair and sum them up. Then divide the sum by (n-1), where n is the total number of pairs. Finally, take the square root of the result. In this case, sd = sqrt(((1-0.8)^2 + (2-0.8)^2 + (0-0.8)^2 + (2-0.8)^2)/4) = 1.32.

For the hypothesis test, we compare the sample mean difference (d) to the population mean difference (μd) under the null hypothesis. The null hypothesis states that there is no difference between the two populations. If the difference between d and μd is statistically significant at a significance level of α = 0.05, we reject the null hypothesis and conclude that there is a significant difference between the two populations. Otherwise, we fail to reject the null hypothesis.

Without information about the population mean difference (μd), we cannot perform the hypothesis test or draw a conclusion.

Learn more about Hypothesis Testing here:

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In order to buy the microscope, we plan to walk dogs after school, charging $3 per dog. To reward the dogs, we will buy a box of treats for $5 as we start the business. The price of the microscope is $254. How many dogs do the friends need to walk in order to have enough money to buy the microscope?

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Answer:

85 dogs they need to walk to have a 254

Exercisea. I choose the correct option from Contain Questions
i Which of the following is a group set ?
(b) A happy person in the Village
(c) Simple Ex in the book (d) school age student
(Weekly

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Answer:

happy person in the village

Please help me on my homework

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the correct answer is $948

HELP!!!!! I do not understand how to do this! Could someone please explain to me how I would solve this problem? A computer manufacturer built a new facility for assembling computers. There were construction and new equipment costs. The company paid for these costs and made combined profits of $10 million after 4 years, as shown in the graph:

There is a graph of a line with Years on the x axis and Profits in millions on the y axis that passes through 0, negative 20 and 4, 10.

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Yeah man nearly there

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