PLEASE HELP ***What is the length of AC??? Please help me understand how to find this
PLEASE HELP ***What is the length of AC??? Please help - 1

Answers

Answer 1
Answer: The answer is 144.

AC and CE have the same ratio as BA and DE. So you can get the answer by getting their proportions. 

  84   =   7 
156-x     x 

Cross multiply, transpose, and simplify to get the variable x.

84x = 1092-7x
84x + 7x = 1092
91x = 1092
x = 12

To get AC, substitute. 

AC = 156 - x
AC = 156 - 12
AC = 144


Related Questions

I feel nice today, Here is 100 points
HELP WILL MARK BRAINLIEST
brainiest and 50 points. Diana usually drives at an average rate of 30 mph. Today, she is going to drive 12 miles to her friend Tony's house. How many minutes will it take her to get there?
Someone help pls!!! Thanks
PLEASE PLEASE PLEEEASE HURRY! ILL GIVE 20 POINTS!!! WILL GIVE BRAINLIEST!

Find the slope of the line that contains the points (4,2) and (7,-4)*

Answers

Answer:

-2

Step-by-step explanation:

To find the slope of the line you have to use the equation,

(y2-y1)/(x2-x1)

In this case it is, (-4-2)/7-4)

This simplifies to -2 and this is the slope of the line

Answer:

-8/5

hope this help!

Verify the linear approximation at (0, 0) forf(x, y) = 7x + 4
5y + 1
â 4 + 7x â 20y

Let f(x, y) = 7x + 4 5y + 1 . Then fx(x, y) = ________

Answers

You need to plug in the (0,0) that’s it

Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of μ=22.5 in. and a standard deviation of σ=1.1 in. These data are often used in the design of different​ seats, including aircraft​ seats, train​ seats, theater​ seats, and classroom seats. Instead of using 0.05 for identifying significant​ values, use the criteria that a value x is significantly high if​ P(x or ​greater) ≤0.01 and a value is significantly low if​ P(x or ​less) ≤0.01.Find the​ back-to-knee lengths separating significant values from those that are not significant.

Answers

Answer:

Measures equal or lower than 19.94 inches are significantly low.

Measures equal or higher than 25.06 inches are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 22.5, \sigma = 1.1

Find the​ back-to-knee lengths separating significant values from those that are not significant.

Significantly low

In this exercise, a value is going to be to significantly low if it has a pvalue of 0.01 or less. So we have to find X when Z has a pvalue of 0.01. This is between Z = -2.32 and Z = -2.33, so we use Z = -2.325

Z = (X - \mu)/(\sigma)

-2.325 = (X - 22.5)/(1.1)

X - 22.5 = -2.325*1.1

X = 19.94

Measures equal or lower than 19.94 inches are significantly low.

Significantly high

In this exercise, a value is going to be to significantly high if it has a pvalue of 0.99 or more. So we have to find X when Z has a pvalue of 0.99. This is Z = 2.325. So:

Z = (X - \mu)/(\sigma)

2.325 = (X - 22.5)/(1.1)

X - 22.5 = 2.325*1.1

X = 25.06

Measures equal or higher than 25.06 inches are significantly high.

Final answer:

To find the separating back-to-knee lengths, we calculate the corresponding z-scores for the given probabilities. Using the standard normal distribution table, we find that the separating values are 24.78 inches for significantly high lengths and 20.22 inches for significantly low lengths.

Explanation:

To find the back-to-knee lengths separating significant values from those that are not significant, we need to calculate the z-scores corresponding to the given probabilities. For a value to be significantly high, we look for a z-score such that the area to its right is 0.01. Using the standard normal distribution table, we find that z = 2.33. Similarly, for a value to be significantly low, we look for a z-score such that the area to its left is 0.01. Again using the table, we find that z = -2.33. Converting these z-scores back to actual back-to-knee lengths, we can calculate the separating values as: 22.5 + (2.33 * 1.1) = 24.78 inches for significantly high lengths, and 22.5 - (2.33 * 1.1) = 20.22 inches for significantly low lengths.

Learn more about Back-to-knee lengths here:

brainly.com/question/32753759

#SPJ3

Can someone help me on my last problem? #10

Answers

ok but what did i do wrong and if you never studied the subject how did you know i was wrong
Based on my small expertise in this subject,

the answer should be 1/(20)^22


the logic is the same as a coin flip
1st flip: call for heads, 1/2 chance
2nd: call for heads, (multiply by self) 1/2 x 1/2= 1/4 chance
3rd: heads, 1/4 x 1/2= 1/8
and so on...

Consider the following model:E(y) = βo + β1x1 + β2x2 + β3x3 + β4x1x2

where y represents exam score (0 to 100 points), x1 represents the amount paid to a tutor (in dollars) in the week before the exam, x2 represents the number of hours of sleep in the week before the exam, and as represents number of study hours in the week before the exam. How many independent variables are included in this model?

a. 3
b. 2
c. 1
d. 4

Answers

Answer:

a. 3

Step-by-step explanation:

An independent variable is the variable that is changed in an experiment to test its effects on the dependent variable. i.e. inputs

A dependent variable is the variable being tested, measured or predicted in an experiment. I.e a outcome

In this case, the the effects of the amount tutors are paid a week before exam, the amount of sleep before exam and the number of study hours are input variables to determine or predict a students score in exam

The independent variables are;

x1 =represents the amount paid to a tutor (in dollars) in the week before the exam

x2 = represents the number of hours of sleep in the week before the exam

x3 = number of study hours in the week before the exam

The dependent variable is the exam score

B0, B1, B2,B3, B4 are coefficients

Assume that, on average, healthy young adult’s dream 90 minutes each night, as inferred from a number of measures, including rapid eye movement (REM) sleep. An investigator wishes to determine whether drinking coffee just before going to sleep affects the amount of dream time. After drinking a standard amount of coffee, dream time is monitored for each of 28 healthy young adults in a random sample. Results show a sample mean, X, of 88 minutes and a sample standard deviation, s, of 9 minutes. (a) Use t to test the null hypothesis at the .05 level of significance (b) If appropriate (because the null hypothesis has been rejected), construct a 95 per-cent confidence interval and interpret this interval

Answers

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 90

For the alternative hypothesis,

µ < 90

If drinking coffee just before going to sleep affects the amount of dream time, then the amount of dream time would be less than 90 minutes. It means that it is left tailed.

Since the number of samples is 28 and no population standard deviation is given, the distribution is a student's t.

Since n = 28,

Degrees of freedom, df = n - 1 = 28 - 1 = 27

t = (x - µ)/(s/√n)

Where

x = sample mean = 88

µ = population mean = 90

s = samples standard deviation = 9

t = (88 - 90)/(9/√28) = - 1.176

We would determine the p value using the t test calculator. It becomes

p = 0.124

Since alpha, 0.05 < than the p value, 0.124, then we would not reject the null hypothesis. Therefore, At a 5% level of significance, the sample data did

not show significant evidence that drinking coffee just before going to sleep affects the amount of dream time.