Three boxes contain 50 parts each. one part in each box is defective. one part is selected at random from each of the three boxes.a.) what is the probability that all three parts are non-defective?
b.) what is the probability that the part selected from box 1 is defective, and the parts selected from box 2 and 3 are non-defective?
c.) what is the probability that two parts are non-defective and one part is defective?
Answers
48:3
B.) The probability that the part selected from box 1 is defective :-
1:1
The probability of the parts selected from box 2 and 3 are non defective :-
49:2
C.) The probability that two parts are non-defective and one part is defective :-
48:2 / 1:1
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Answers
Answer:
D
Step-by-step explanation:
if AB is congruent to AC that means both are 76 degrees so subtract that from the total degrees of a whole triangle which is 180 that gives you A which is 28.
Hope it helps :)
Answers
Answer:
The volume of the cone is 63.3m³
Step-by-step explanation:
First of all to solve this problem we need to know the formula to calculate the volume of a cone
v = volume
r = radius = 2.2m
h = height = 12.5m
π = 3.14
v = 1/3 * π * r² * h
we replace with the known values
v = 1/3 * 3.14 * (2.2m)² * 12.5m
v = 1/3 * 3.14 * 4.84m² * 12.5m
v = 63.32m³
rount to the neares tenth
v = 63.32m³ = 63.3m³
The volume of the cone is 63.3m³
Answer: 63.4
Step-by-step explanation:
You round to the tenths giving you 63.4
Use the table of values to find the function's values.
If x = 0, then f(0) =
If f(x) = 27, then x =
33
-3 -2
17
0
-15
N
-7
3
27
Answers
For our particular data set, the value of the function f(x) is -2 when x = 0 (or f(0) = -2), and the value of x is 3 when f(x) = 27.
From the provided data, we see that we have specific values of x that correspond to certain values of the function f(x). Therefore, our goal is to find the value of f(x) when x = 0, and to find the value of x when f(x) = 27.
We start by finding the function value f(0). Looking at our data, we find an entry where x = 0, we observe that its corresponding f(x) value is -2. Thus, the value of the function f(x) is -2 when x = 0, so we have f(0) = -2.
Next, we're tasked with finding the value of x when f(x) = 27. To do this, we flip our perspective and look for entries in our data where f(x) = 27. After searching, we see an entry where f(x) equals to 27, and in this entry, the corresponding x value is 3. Therefore, when f(x) = 27, the value of x is 3.
In conclusion, for our particular data set, the value of the function f(x) is -2 when x = 0 (or f(0) = -2), and the value of x is 3 when f(x) = 27.
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Answer:
If x = 0, then f(0) = -15
If f(x) = 27, then x = 3
Answers
Answer:
$45.79 multiplied by .50 equals 22.895
Answer:
686.85
Step-by-step explanation:
Answers
Answer:
The error bound is 3.125%.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
A sample of 506 California adults.. This means that .
76% of California adults (385 out of 506 surveyed) feel that education is one of the top issues facing California. This means that
We wish to construct a 90% confidence interval
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The error bound of the confidence interval is the division by 2 of the subtraction of the upper limit by the lower limit. So:
The error bound is 3.125%.
90 like broccoli,
59 like cauliflower,
28 like both Brussels sprouts and broccoli,
20 like both Brussels sprouts and cauliflower,
24 like both broccoli and cauliflower, and
10 of the students like all three vegetables.
a) How many of the 269 college students do not like any of these three vegetables?
b) How many like broccoli only?
c) How many like broccoli AND cauliflower but not Brussels sprouts?
d) How many like neither Brussels sprouts nor cauliflower?
Answers
Answer: a) 83, b) 28, c) 14, d) 28.
Step-by-step explanation:
Since we have given that
n(B) = 69
n(Br)=90
n(C)=59
n(B∩Br)=28
n(B∩C)=20
n(Br∩C)=24
n(B∩Br∩C)=10
a) How many of the 269 college students do not like any of these three vegetables?
n(B∪Br∪C)=n(B)+n(Br)+n(C)-n(B∩Br)-n(B∩C)-n(Br∩C)+n(B∩Br∩C)
n(B∪Br∪C)=
So, n(B∪Br∪C)'=269-n(B∪Br∪C)=269-156=83
b) How many like broccoli only?
n(only Br)=n(Br) -(n(B∩Br)+n(Br∩C)+n(B∩Br∩C))
n(only Br)=
c) How many like broccoli AND cauliflower but not Brussels sprouts?
n(Br∩C-B)=n(Br∩C)-n(B∩Br∩C)
n(Br∩C-B)=
d) How many like neither Brussels sprouts nor cauliflower?
n(B'∪C')=n(only Br)= 28
Hence, a) 83, b) 28, c) 14, d) 28.