1.) Find the first six terms of the sequence.a1 = -6, an = 4 • an-1

A.)0, 4, -24, -20, -16, -12
B.)-24, -96, -384, -1536, -6144, -24,576
C.)-6, -24, -20, -16, -12, -8
D.)-6, -24, -96, -384, -1536, -6144

2. Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...

A.)an = -15 + 9(n + 1)
B.)an = -15 x 9(n - 1)
C.)an = -15 + 9(n + 2)
D.)an = -15 + 9(n - 1)

3. Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9

A.)an = -579 + 42(n + 1)
B.)an = -579 + 42(n - 1)
C.)an = -579 - 42(n + 1)
D.)an = -579 - 42(n - 1)

4. Determine whether the sequence converges or diverges. If it converges, give the limit.
48, 8, four divided by three , two divided by nine , ...

A.)Converges; two hundred and eighty eight divided by five
B.)Converges; 0
C.)Diverges
D.)Converges; -12432

5. Find an equation for the nth term of the sequence.
-3, -12, -48, -192, ...

A.)an = 4 • -3n + 1
B.)an = -3 • 4n - 1
C.)an = -3 • 4n
D.)an = 4 • -3n

8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81


A.)summation of the quantity negative nine plus six n from n equals zero to fifteen
B.)summation of negative fifty four times n from n equals zero to fifteen
C.)summation of negative fifty four times n from n equals zero to infinity
D.)summation of the quantity negative nine plus six n from n equals zero to infinity

Answers

Answer 1
Answer: try a,b,d,a,then b
sorry if its wrong

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3 days after the start of an experiment there were 484 bacteria in a culture. After 5 days there were 1135. Use a system of equations to determine the initial number of bacteria in the culture (c) and the k value for the growth

Answers

Answer:

  • c = 135
  • k = 0.42615

Step-by-step explanation:

We assume you want your model to be ...

  p = c·e^(kt)

Filling in (t, p) values of (3, 484) and (5, 1135), we have two equations in the two unknowns:

  484 = c·e^(3k)

  1135 = c·e^(5k)

Taking logs makes these linear equations:

  ln(484) = ln(c) +3k

  ln(1135) = ln(c) +5k

Subtracting the first equation from the second, we have ...

  ln(1135) -ln(484) = 2k

  k = ln(1135/484)/2 ≈ 0.42615

Using that value in the first equation, we find ...

  ln(484) = ln(c) +3(ln(1135/484)/2)

  ln(c) = ln(484) -(3/2)ln(1135/484)

  c = e^(ln(484) -(3/2)ln(1135/484)) ≈ 134.8

The initial number in the culture was 135, and the k-value is about 0.42615.

_____

I prefer to start with the model ...

  p = 484·(1135/484)^((t-3)/2)

Then the initial value is that obtained when t=0:

  c = 484·(1135/484)^(-3/2) = 134.778 ≈ 135

The value of k the log of the base for exponent t. It is ...

  ln((1135/484)^(1/2)) = 0.426152

This starting model matches the given numbers exactly. The transformation to c·e^(kt) requires approximations that make it difficult to match the given numbers.

__

For this model, the base of the exponent is the ratio of the two given population values. The exponent is horizontally offset by the number of days for the first count, and scaled by the number of days between counts. The multiplier of the exponential term is the first count. The model can be written directly from the given data, with no computation required.

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Answers

Answer:

a. f^-^1(x)=(x)/(4) +3

b. f(-9)=-48

c. f^-^1(-9)=(3)/(4)

Step-by-step explanation:

In a, the -1 means inverse of f(x). To find the inverse, you rewrite the equation in terms of x and y. You replace the x with y and y with x. Then you solve for y.

f^-^1(x)=4x-12

y=4x-12

x=4y-12

x+12=4y

(x)/(4) +3=y

f^-^1(x)=(x)/(4) +3

In b, all you have to do is plug in -9 into f(x).

f(9)=4(9)-12

f(9)=-48

In c, you plug in -9 into inverse function f.

f^-^1(-9)=(3)/(4)

Factor each perfect square trinomial. Then, solve the equation by taking the square root of each side.Q1) x^2+14x+49=9



Q2) x^2-16x+64=144



3Q) x^2-2x+1=81

Answers

Answer:

Q2 :) hope this helps!

Step-by-step explanation:

Question 3 (1 point) If the following is a rhombus, find the missing measures. Find PQ. PQ=​

Answers

Answer:

Step-by-step explanation:

PQ*PQ=PQ²=(5x+16)²=25x²+160x+256

Consider the statement “Worldwide, there are more than $2.5 trillion in credit card transactions annually.”What is the daily average dollar amount of transactions? Round to the nearest hundred million dollars.

Answers

The daily average dollar amount of transactions where there are 2.5 trillion in credit card transactions annually is 6.8 billion.

Given data:

To calculate the daily average dollar amount of transactions, we'll divide the annual total by the number of days in a year.

Annual credit card transactions: $2.5 trillion

Number of days in a year: 365

Daily average dollar amount of transactions = Annual transactions / Number of days

= $2.5 trillion / 365

Now let's perform the calculation:

Daily average dollar amount = $2.5 trillion / 365

On simplifying the equation:

Daily average dollar amount ≈ $6.849 billion

Rounded to the nearest hundred million dollars, the daily average dollar amount of credit card transactions is approximately $6.8 billion.

Hence, the daily average dollar amount of credit card transactions is approximately $6.8 billion.

To learn more about equations, refer:

brainly.com/question/19297665

#SPJ3

Answer:

3 trillion

Step-by-step explanation:

because just do the math bu bl I really dk

Which is true about the solution to the system of inequalities shown

Answers

pls provide the problem

Answer:

look below for question

Step-by-step explanation:

Which is true about the solution to the system of inequalities shown?

y > 3x + 1

y < 3x – 3  

Only values that satisfy y > 3x + 1 are solutions.

Only values that satisfy y < 3x – 3 are solutions.

Values that satisfy either y > 3x + 1 or y < 3x – 3  are solutions.

There are no solutions.