A women does 80.0 joules of work when she slides a book 4.0 meters on the floor. How much force does she apply to the book

Answers

Answer 1
Answer: It would be 80/4 = 20 Newtons??? I think

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How do frequency relate to energy

Answers

The more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave.

The magnitude of the gravitational field on the surface of a particular planet is 2g. The planet’s mass is half the mass of the Earth. What is the planet’s radius in terms of the radius Rg of Earth?

Answers

Final answer:

To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.

Explanation:

To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:

2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg

Learn more about Gravitational field here:

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Final answer:

To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.

Explanation:

The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.

Learn more about gravitational field strength here:

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Explain why buildings are wired using parallel circuits rather than series circuits

Answers

In a series circuit . . .

       There is only one path for current to take. 

All the way from one terminal of the power supply, through all of
the lights, computers, vending machines, air conditioners and
everything else in the building, to the other terminal of the electric
supply.  One path ! 

So the current for EVERY device has to flow through ALL of them,
because that's the only path there is.

If any ONE device in the building was turned off, burned out, or
unplugged from the outlet, then there would be NO PATH for the
current, and everything in the building would lose power !      

Not a very convenient way to operate a house or a building.

When a wave enters a medium and changes into another form of energy, usually TE, This is called:a. absorption
b. transmission
c. reflection
d. refraction

Answers

Answer:

transmission hope this helps

The answer is b. Transmission

What tends to exist in periodic table?

Answers

The arrangement of the chemical elements, ordered by their atomic number, electron configuration , and recurring chemical properties.

Which of the following has the lowest U value?a. plywood
b. poured concrete
c. expanded polyurethane
d. asbestos shingles

Answers

Answer:

c. expanded polyurethane

Explanation:

Thermal performance of a building fabric is measured in terms of heat loss and is expressed as U-value or R-value. U-value is the rate of heat transferred through a structure divided by the difference in temperature across the structure with a unit of measurement of W/m²K.You can calculate the U-value of a by getting the reciprocal of the sum of thermal resistances , R, making the building material.

If you have the value of R, then U=1/R

Material                         size            R                      U

plywood                          1"              1.25                0.8

Poured concrete            2"              0.99               1.010

Expanded polyurethane  1"            6.5                   0.1538

Asbestos shingles            1"             0.03                33.33

The material with lowest U-value is expanded polyurethane