How many days are there in 7 weeks

Answers

Answer 1

Answer: 49 Day is 7 Weeks.You would do 7 Times 7So you add 7 to 7 seven timesHope this helps!

Answer 2

Answer: Okay let's see: So there are 7 days in each week correct?
Okay now let's do 7 times 7=49

ANSWER= 49

Related Questions

Hailey records the weights of five dogs of one breed and five dogs of another breed.What can she infer about the weights of Breed 1 dogs and Breed 2 dogs?Breed 1: {45, 38, 49, 52, 51}Breed 2: {36, 35, 44, 50, 40}Breed 1 dogs and Breed 2 dogs have similar weight distributions.Breed 1 dogs and Breed 2 dogs have no overlap in their weight distributions.Breed 1 dogs and Breed 2 dogs have somewhat similar weight distributions.Breed 1 dogs and Breed 2 dogs have identical weight distributions.
Explain how you would decide which unit is best for measuring your math book?
tom keeps sticky notes in a box that is the shape of a cube. each side of the box is 4 inches. what is the volume of the box
Line A has a slope of 4. Line B has a slope of 1/4.
What is 4/9 times 2/3

Simplify the expression 7v + 2w-12v

Answers

7v + 2w-12v

= 7v-12v+2w
= 5v+2w

Nothing else we can to to this

Answer:

-5v+2w or 2w-5v

Step-by-step explanation:

We just simplifying so it isn't to hard to do, just combine like terms bro :)

Please explain #2 for me please!
The question deals with proportions.

Answers

We claim that the ratio of the areas is (3/2)^3=27/8, not just for these lengths, but also for every possible set of side-lengths x, y, and z.

To find the volume of the area of the original suitcase, multiply together x, y, and z to get xyz. The modified suitcase will have all these dimensions multiplied by 1 1/2, or 3/2, for a result of 3x/2*3y/x*3z/2=27xyz/8. The ratio is (27xyz/8)/(xyz)=27/8, as desired.

Note that we made no assumptions about the value of x, y, and z throughout the whole solution! Therefore, we can plug ANY side-lengths, including the problem's set (28, 16, 8) into this problem to achieve the same ratio.

Question 1: The Millers have hired an interior designer to decorate their family room. they want to have a 22" by 30" oil painting frame and incorporated in the design plan. if the designer chooses molding that is 4" Wide and is priced at $1.45 per inch, how much will the molding cost (Before Tax)

Answers

Answer:Total molding cost is $197.20.

Step-by-step explanation:

Since we have given that

Length of oil painting frame = 22 inch

Width of oil painting frame = 30 inch

Width for molding = 4 inches

So, Length after molding would be

4+22+4 = 30 inches

Width after molding would be

4+30+4 = 38 inches

So, Perimeter of molding would be

$2(L+B)\n\n=2(30+38)\n\n=2* 68\n\n=136\ inches$

Cost per inch = $1.45

So, Total molding cost would be

$1.45* 136\n\n=\$197.20$

Hence, Total molding cost is $197.20.

Final answer:

The Millers would need to purchase 104" of molding for their 22" by 30" painting frame. At $1.45 per inch, the cost for the molding would be $150.80 before tax.

Explanation:

The cost of the molding can be calculated by first determining the total length of the molding needed and then multiplying it by the price per inch. To find the total length of the molding, we need to add the lengths of all sides of the painting frame. Since the frame is a rectangle, it will have two sides that are 22" long and two sides that are 30" long. So the total length of the molding is: 2*(22" + 30") = 104". Now, we multiply this length by the cost of the molding per inch. So, the total cost of the molding is: 104" * $1.45 = $150.80. Thus, the cost of the molding for the 22" by 30" oil painting frame using 4" Wide molding will be $150.80 before tax.

Learn more about Cost of Molding here:

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during the 2008 - 2009 season there were 801372 people who attended the home hockey games in Philadelphia there were 609907 people who attended the home hockey games in Phoenix how much greater was the home attendance in Philadelphia than in Phoenix that season?

Answers

there is a difference of 191'465 people.

you simply subtract 609907 from 801372 and you get 191465

Andrew has a grid in the shape of an isosceles trapezoid. He has right triangles. Each right triangle has an area of 45 square millimeters and each right triangle fits on the grid. If the length of the bases of the grid are 30 centimeters and 15 centimeters and the height is 16 centimeters, how many right triangles can Andrew fit on the grid?