When you turned 8, a family member put $470 in a savings account to help save for college or another big life goal. If your savings account continuously earns 2.1% interest per year, how much will you have in your savings account when you turn 18? (Show your work)

Answers

Answer 1

Answer: The answer is $578.57.

To answer this, we will use the future value of lump sum deposit (refer to the attached picture). Substitute the following given to the formula.
PV = 470
r = 2.1%
t = 10 years

FV = 470 (1 + 0.021)^10
FV = 470 (1.021)^10
FV = 470 (1.2309...)
FV = 578.57

Your savings account will contain $578.57 when you turn 18.

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Which expression is equivalent to 27x3 + 125?-)
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(3x - 5)(9x2 – 15x + 25)
B)
(3x - 5)(9x2 + 15x – 25)
0
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(3x + 5)(9x2 + 15x – 25)
I need help solving this please

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Write the 4th degree polynomial function shown by the graph. The factors of the polynomial functions are

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(x+3)(x+1)(x-2)(x-3) was the answer - second choice in my options.

Answer to the second question - A=2

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7 to the 3rd power as a multiplication of factors is

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Answer:

7*7*7

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Answer:

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Step-by-step explanation:

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Use your completed 24-hour circle to calculate how much time you spend on each activity listed in the Activities Breakdown below each week. The blank lines are for any additional situations that take up your time. After you have totaled up all the items you can think of, figure out how much free time you have. ACTIVITIES BREAKDOWN - Hours per week 2. Study Time, reviewing, projects, papers 3 11. ____ 12.___ 13. Wasted hours ___ A. Sleep B. Work C. Leisure D. Wasted hours

Answers

Answer:

To calculate how much time you spend on each activity, you need to fill in the circle with everything you do in a day, using 24-hour format1. For example, if you sleep for 8 hours, work for 4 hours, and study for 3 hours, you can write these numbers in the circle. Then, you can add up the hours for each activity and write them in the table below.

Here is an example of how to fill in the circle and the table:

|-----------------|

| |

| 8 4 |

| / \ / \ |

| / \/ \ |

| / /\ \ |

|/ / \ \ |

| / \ \ |

| / \ \|

| / \ /|

|/ \ / |

| X |

| / \ |

| / \|

| / |

| 3 |

| |

|-----------------|

ACTIVITIES BREAKDOWN - Hours per week

1. Class Time: 0

2. Study Time, reviewing, projects, papers: 3 x 7 = 21

3. Commuting: 0

4. Dressing and eating: 1 x 7 = 7

5. Hours of employment: 4 x 5 = 20

6. Responsibilities at home: 1 x 7 = 7

7. Athletics requirements: 0

8. Telephone and computer: 2 x 7 = 14

9. Television: 1 x 7 = 7

10. Sleeping: 8 x 7 = 56

11.

12.

13. Wasted hours:

Total: (21 + 7 + 20 + 7 + 14 + 7 +56) =132

Total number of hours per week =168

Subtract your Total (132)

Total free hours per week = (168 -132) =36

Step-by-step explanation:

Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together?5x + 13y = 232
12x + 7y = 218
The first equation can be multiplied by –13 and the second equation by 7 to eliminate y.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

Answers

The THIRD sentence is correct.
The first equation can be multiplied by -12 and the second equation by 5, to eliminate x.
Let's do this:
(1st equation) 5*x + 13*y = 232 / *(-12)
(2nd equation) 12*x + 7*y = 218 / *(5)
---------------------------------
When multiplied, we get:
(1st equation) -60*x - 156*y = -2784
(2nd equation) 60*x + 35*y = 1090
---------------------------------
Further, first equation now will be obtained when ADDING 1st and 2nd equation together:
(1st equation) -60x+60x-156y+35y=-2784+1090
2nd equation we get from just writing any equation from the beginning, for example, the second one:
(2nd equation) 12*x + 7*y = 218
-----------------------------------------
(1st equation) 0*x - 121*y = -1694
(2nd equation) 12*x + 7*y = 218
------------------------------------------
(1st equation) -121*y = -1694 [x variable is in this step eliminated]
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 1694/121
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 7*14 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 98 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 218 - 98
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 120
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 120/12
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 10
----------------------------------------------
So, solution of the system of this two equations is obtained, and it is:
(x,y)=(10,14)

Answer:

The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

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