what is the force on a hockey puck when shot with a stick? the pucks mass is 0.155 kg and it leaves the stick at 40 m/s. the contact time between the puck and the stick is 1.1 millisecond

Answers

Answer 1
Answer:

According to the  Newton's second law of motion:

Force = mass × acceleration

Acceleration = change in speed ÷ time

Therefore,

Force =mass × (change in speed/time)

Acceleration = 40 m/s ÷ 1.1 millisecond

Acceleration = 40 m/s ÷ 0.001 seconds

Acceleration = 40,000 m/s²

Hence,

F = m × a

F = 0.155 kg × 40,000 m/s²

F = 4,600 kg·m/s² (Newtons)


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Answers

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Answers

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Answers

Answer:

A disadvantage of getting involved in activities outside the school can be lack of time to other important activities.

Explanation:

For example, the time used for others activities, can be used to make homeworks, study, spent time with the family and friend, sleep the recommended amount of time.

But it´s important to have a balance in the use of time a take profit of every moment, balancing our likes with our responsibilities.

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Answers

Hello!

The answer is: 960 East feet.

Why?

We need to apply the following formula:

xf=xi+v*t

and  

displacement=xf-xi

So, by substituting we have:

xf-xi=(8ft)/(min) *120min\nd=960ft

Have a nice day!