Which statement describes this system of equations?
9x – 6y = 15,
3x – 2y = 5

Answers

Answer 1
Answer:

This system of equation has an infinite number of solutions.

You can tell this because multiplying one equation by a constant gives you exactly the other equation. You can multiply the second equation by 3.

9x - 6y = 15

5(3x - 2y = 5) = 9x - 6y = 15

When this happens, you can assume that there are an infinite number of solutions.

Answer 2
Answer:

Answer:

1) The equations in the system are equivalent equations.

2) There is no solution to the system of equations.

3) The system of equations has one solution at (3, 2).

4) The system of equations has one solution at (5, 5).

Answer = 1

Step-by-step explanation:

I just did the assignment


Related Questions

Autos arrive at a toll plaza located at the entrance to a bridge at a rate of 50 per minute during the​ 5:00-to-6:00 P.M. hour. Determine the following probabilities assuming that an auto has just arrived. a. What is the probability that the next auto will arrive within 6 seconds ​(0.1 ​minute)? b. What is the probability that the next auto will arrive within 3 seconds ​(0.05 ​minute)? c. What are the answers to​ (a) and​ (b) if the rate of arrival of autos is 60 per​ minute? d. What are the answers to​ (a) and​ (b) if the rate of arrival of autos is 30 per​ minute?
Write 3.274 x 10^3 as an ordinary number
Ty stacked some large wooden blocks. Each block is 1/3 ft tall. His stack of blocks measures 5 ft. How many blocks are in Ty's stack?
Find the next three numbers 1, 0.6, 0.36, 0.216
The daily high temperature in Chicago for the month of August is approximately normal with mean 78 degrees F, and standard deviation 9 degrees F. a. What is the probability that a randomly selected day in August will have a high temperature greater than the mean daily high temperature of 78 degrees F?b. What is the percentile for a day in August with a high temperature of 75 degrees F? c. What is the 75th percentile for the daily high temperature for the month of August? d. What is the interquartile range for the daily high temperature for the month of August?

We must use substitution to do this second integral. We can use the substitution t = 7x, which will give dx = Correct: Your answer is correct. dt. Ignoring the constant of integration, we have sin(7x) dx =

Answers

Answer:

Therefore, the solution is:

\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}

Step-by-step explanation:

We calculate the given integral.  We use the substitution t = 7x.

\int \sin 7x\, dx=\begin{vmatrix} 7x=t\n 7\, dx=dt\n dx=(dt)/(7) \end{vmatrix}\n\n=\int \sin t \cdot (1)/(7)\, dt\n\n=(1)/(7)\cdot (-\cos t)\n\n=-(\cos 7x)/(7)

Therefore, the solution is:

\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}

use the function rule, y=2x +5, to find the values of y when x=1,2,3,and 4. write the answers as ordered pairs that would be used to graph the function please show work

Answers

y = 2x + 5

x = 1

Replace x with 1, and evaluate the right side.

y = 2 * 1 + 5 = 2 + 5 = 7

Ordered pair: (1, 7)

x = 2

Replace x with 2, and evaluate the right side.

y = 2 * 2 + 5 = 4 + 5 = 9

Ordered pair: (2, 9)

x = 3

Replace x with 3, and evaluate the right side.

y = 2 * 3 + 5 = 6 + 5 = 11

Ordered pair: (3, 11)

x = 4

Replace x with 4, and evaluate the right side.

y = 2 * 4 + 5 = 8 + 5 = 13

Ordered pair: (4, 13)

The 4 ordered pairs are: (1, 7), (2, 9), (3, 11), (4, 13)

y = 2(1) + 5
y=2+5=7. (1,7)

2(3) + 5
y=6+5= 11. (3,11)

2(2) + 5
y=4+5=9. (2,9)

2(4) + 5
y=8+5=13. (4,13)

Please answer asap...........

Answers

Answer:

A. distributive property

Line l passes through the points (- 4, 3) and (2, 1) What is the slope of a line that is perpendicular l

Answers

Answer:

m=1

Step-by-step explanation:

The plots (-4,3) and (2,1) have a slope of -1. Perpendicular lines would mirror that, making it a positive 1

2.) What amount presently must be invested earning 5.25% compounded continuouslyso that it will grow up to be worth $25,000 12 years from now?

Answers

The amount A resulting from a principal amount P being invested at rate r compounded continuously for time t is given by

... A = P·e^(rt)


FIll in your given values and solve for P.

... 25000 = P·e^(0.0525·12) = P·e^0.63

... P = 25000/e^0.63 ≈ 13314.80 . . . . . divide by the coefficient of P


The amount that must be invested is $13,314.80.

An initial investment (P) compounded continuously with a rate of interest (r) in time (t) will grow to amount (Q) is given by:

Q = P * e^(rt)

Q=25000, r=0.0525, t=12

25000 = P * e^(0.0525*12)

1.8776P = 25000

P = 13314.8

R = {(-3, -2), (-3, 0), (-1, 2), (1, 2)}

Select all numbers that are in the domain.

Answers

Answer:

-3 -3 -1 1

Step-by-step explanation:

give me five stars and ill tell you

Answer: Answer: -3,-1, and 1.

Step-by-step explanation: You are given the relation R = {(-3, -2), (-3, 0), (-1, 2), (1, 2)} The domain of the relation are all possible inputs and the range of the relation are all possible outputs. So, the inputs are : -3,-1,1; and the outputs are : -2,0,2. As a result, the domain is : -3,-1,1; and the range is : -2,0,2.