Simplify the expression given below.

Answers

Answer 1

Answer: For this case, what we should do is follow the following steps:
1) Factor the third degree polynomial
2) Factor the second degree polynomial
3) Rewrite the division of fractions
4) Cancel similar terms
Answer:
option 1
See attached image for the solution

Answer 2

Answer: the answer is 1/ 3x+1 (the first one)

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Which ordered pairs are in the solution set of the system is liner inequalities y>-1/3x+2 y<2x+3

Answers

Answer:

Option (1)

Step-by-step explanation:

Given linear inequalities in the graph are,

$y\geq -(1)/(3)x+2$

y < 2x + 3

Here shaded area above the solid line represents the inequality,

$y\geq -(1)/(3)x+2$

And shaded area on the right side of the dotted line represents the solution set of the inequality,

y < 2x + 3

And the solution set of the system of linear inequalities will be represented by the common area of these inequalities.

Therefore, ordered pairs (2, 2), (3, 1) and (4, 2) will lie in the common shaded area.

Option (1) will be the answer.

Evaluate.

[42 ÷ (2 + 3 • 2)] + [4 • (36 – 52)]

I really need help!!!

Answers

Ok so first we do 2 + 3 = 5 * 2 = 10 / by 42 = 4.2

other side 36 - 52 = 16 * 4 = 64 now add 4.2 + 64 = 68.2

The probability of drawing a quarter from a bag of coins is 1/10. What is the probability of drawing a coin that is not a quarter from the bag?A.
10%

B.
100%

C.
20%

D.
90%

Answers

1-1/10 = 9/10
9/10 x 100 = 90

So the answer is D, or 90%.

A diagram of a hockey rink is shown below. The diameter of the middle circle is 30 Feet. What is the area of the middle circle? Use 3.4 for

Answers

The formula of the area of the circle is
Area = pi * (d/2)^2

So using the formula,
Area = 3.14 * (30/2)^2
Area = 3.14 * 15^2
Area = 706.5 ft^2

So the area of the hockey rink is 706.5 ft^2

Help me with this question please thank you A ball is thrown downward from a window from a tall building. Its position at time t in seconds is s = 16t^2 + 32t, where s is in feet. How long (to the nearest tenth) will it take the ball to fall 161 feet.

Answers

$s=16t^2+32t;\ s=161\n\n16t^2+32t=161\n\n16t^2+32t-161=0\n\na=16;\ b=32;\ c=-161\n\n\Delta=b^2-4ac\to\Delta=32^2-4\cdot16\cdot(-161)=1024+10304=11328\n\nx_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n√(11328)=√(64\cdot177)=8√(177)\approx106.4\n\nx_1=(-32-106.4)/(2\cdot16)< 0;\ x_2=(-32+106.4)/(2\cdot16)=(74.4)/(32)=2.325\approx2.3\ (ft)$

if I understood correctly:
s = 16t^2 + 32t, s=161
16t^2 + 32t=161
16t^2 + 32t-161=0
t=(-32+8√177)/32=-1+√177/4≈2,326≈2,3

Solve the inequalities:
3(m-5) - 6 > -36
What do I do?

Answers

3(m - 5) - 6 > -36

First, add 6 to both sides. / Your problem should look like: $3(m - 5) \ \textgreater \ -36 + 6$
Second, simplify -36 + 6 to get -30. / Your problem should look like: $3(m - 5) \ \textgreater \ -30$
Third, divide both sides by 3. / Your problem should look like: $m - 5 \ \textgreater \ -(30)/(3)$
Fourth, since 10 × 3 is 30, simplify the fraction by 10. / Your problem should look like: $m - 5 \ \textgreater \ -10$
Fifth, add 5 to both sides. / Your problem should look like: $m \ \textgreater \ -10 + 5$
Sixth, simplify -10 + 5 to get -5. / Your problem should look like: $m \ \textgreater \ -5$

Answer: m > -5

3(m−5)−6>−36

3m−21>−36

Step 2: Add 21 to both sides.

3m−21+21>−36+21

3m>−15

Divide both sides by 3.

3m/3>−15/3

m>−5

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