15x+1200=y what is the change in the total cost for each book printed? What is the cost to get started before any books are printed

Answers

Answer 1

Answer: The total cost before books are printed is $1200 (the constant).

The change to the total cost is the x, which is a variable, and can change depending on the amount of books printed.

hope this helps

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Simplify 3p^2q+3p(2pq-4)+5p^3

Answers

distribute
a(b+c)=ab+ac
3p(3pq-4)=9p^2q-12p

we have

3p^2q+9p^2q-12p+5p^3
add like terms
4p^3+12p^2q-12p

Step by Step
3p^2q+3p(2pq−4)+5p^3

Distribute:

=3p^2q+(3p)(2pq)+(3p)(−4)+5p^3=3p2q+6p2q+−12p+5p3

Combine Like Terms:

=3p^2q+6p^2q+−12p+5p^3=(5p^3)+(3p^2q+6p^2q)+(−12p)=5p^3+9p^2q+−12p
=5p^3+9p^2q−12p

Which statement about solving inequalities is true?Adding the same value to both sides of an inequality does not change the solution set.
Subtracting the same value from both sides of an inequality changes the solution set.
When dividing both sides of an inequality by the same positive value, it is necessary to reverse the inequality sign.
When multiplying both sides of an inequality by the same negative value, it is not necessary to reverse the inequality sign.

Answers

The statement which is true about solving inequalities is; Adding the same value to both sides of an inequality does not change the solution set.

Discussion:

Similar to equations, when solving inequalities; adding or subtracting the same value to both sides of an inequality does not change the solution set of the inequality.

In essence, the statement which is true about solving inequalities is; Adding the same value to bothsides of an inequality does not change the solution set.

Answers

Answer:

$(2x(5x+1))/(4x-1)$

Step-by-step explanation:

Given expression:

$((4x^3-12x^2)/(4x^2+7x-2))/((2x^2-6x)/(5x^2+11x+2))$

Consider the numerator and the denominator separately.

Numerator:

$(4x^3-12x^2)/(4x^2+7x-2)\n \n=(4x^2(x-3))/(4x^2+8x-x-2)\n \n=(4x^2(x-3))/(4x(x+2)-(x+2))\n \n=(4x^2(x-3))/((x+2)(4x-1))$

Denominator:

$(2x^2-6x)/(5x^2+11x+2)\n \n=(2x(x-3))/(5x^2+10x+x+2)\n \n=(2x(x-3))/(5x(x+2)+(x+2))\n \n=(2x(x-3))/((x+2)(5x+1))$

The whole expression:

$((4x^3-12x^2)/(4x^2+7x-2))/((2x^2-6x)/(5x^2+11x+2))\n \n \n=((4x^2(x-3))/((x+2)(4x-1)))/((2x(x-3))/((x+2)(5x+1)))\n \n \n=(4x^2(x-3))/((x+2)(4x-1))\cdot ((x+2)(5x+1))/(2x(x-3))\n \n \n=(2x(5x+1))/(4x-1)$

The product of 16 and 4 less than a number is 208. Find the number

Answers

16(x-4)=208
x-4=13
x=17
Hope that helps!

Help PleAsE??What is the point-slope form of the equation of a line that passes through the point (6, −8) and has a slope of −2?
A.y+8=2(x-6)

B.y+8=-2(x-6)

C.y-6=-2(x-8)

D.y-8=-2(x+6)

Answers

y - y1 = m(x - x1)

Where 'y1' is the y-value of the point, 'x1' is the x-value of the point, and 'm' is the slope.

So in this case:

y1 = -8
x1 = 6
m = -2

Plug them in:

y - (-8) = -2(x - 6)

or

y + 8 = -2(x - 6)

Point slope form is:
$\sf {y - y_1 = m(x - x_1)}$

Where $\sf{(x_1,y_1)}$ is the point and $\sf{m}$ is the slope.

So from your question:

$\sf{ x_1 = 6}$
$\sf{y_1 = -8}$
$\sf{m = -2}$

Plug them into the equation for point slope form:

$\sf {y - y_1 = m(x - x_1)}$

Becomes when you plug it in:

$\sf{y-(-8) = -2(x - 6)}$

And when you subtract a negative that becomes addition so:

$\sf{y+ 8 = -2(x - 6)}$

And that would correlate to answer choice $\sf{\boxed{B}}$

PLEASE HELP ME! I DONT UNDERSTAND THIS AND I NEED THE ANSWER CAUSE ITS OVERDUEEE

Answers

Answer:

7mn

Step-by-step explanation:

because 7 goes into both. but there is only one letter in each if you took more you would be in debt which you can't do with gcf

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