Suppose P(A) = 0.9, P(B) = 0.3, and P(B|A) = 0.2. What is P(A|B) ?

Answers

Answer 1
Answer:

By definition of conditional probability,

P(B\mid A)=(P(B\cap A))/(P(A))\implies P(B\cap A)=0.2\cdot0.9=0.18

Similarly,

P(A\mid B)=(P(A\cap B))/(P(B))=(0.18)/(0.3)=0.6


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What percent of the June budget was for babysitting and movies (to the nearest tenth)?

Answers

The monthly expenses are found below:


Mortgage - $752 Tim's Chevron - $23Johnny's Allowance - $8Electric - $176Jenny-babysitting - $12Movie - $14Dry Cleaning - $41Tithe - $85,Credit Card - $150Food - $101Phone - $45Water - $16 Car - $272 


Adding all the expenses, will give us a total of $1695.
 
To get the percent which is allocated for movie and the baby sitting:


Add the amount for the two then divide that to the total then multiply it by 100%
= 12 + 14 / 1695 x 100%
= 26 / 1695 x 100%
= 0.015339233 x 100%

=1.5%
The answer is 1.5%



F(x)=(3x-1)/(2) find f^(-1)(2)

Answers

Answer:

f^(-1) (2)=(5)/(3)

Step-by-step explanation:

To find the inverse of a function, we must replace y for x and then solve for y.

y=(3x-1)/(2) \nx=(3y-1)/(2) \n2x=3y-1\n3y=2x+1\ny=(2x+1)/(3) \nf^(-1) (x)=(2x+1)/(3)

Now we can substitute x=2 into our inverse function

f^(-1) (2)=(2(2)+1)/(3) \nf^(-1) (2)=(5)/(3)

a photograph that measures 20 cm by 15 cm is enlarged so that its length becomes 28 cm. what does the width become?

Answers

(width)/(distance) = (15)/(20) = (3)/(4)

This means that ,assumining the dimensions stay the same, the width will be equal to three quaters of the length

∴ When length=28cm 
   width = 0.75 × 28 = 21cm

the width becomes 21 centimeters hope this helps:)

What is z?
5z+8=4z+20
Once again im struggling and need help fast..=)

Answers

5z+8=4z+20
-8 -8
5z=4z+12
-4z -4z
z=12
z= 12 hope this helps

Given that the volume of a cube is 2744 cm3 find the length of its edge

Answers

the answer is 14 mm 
hope it helps :)

Jesse takes his dog and cat for their annual vet visit. Jesse's dog weighs 23 pounds. The vet tells him his cats weight is 5/8 as his dogs weight. How much does his cat weigh?

Answers

14³/₈ or 14.375 pounds.

Further explanation

Given:

  • Jesse takes his dog and cat for their annual vet visit.
  • Jesse's dog weighs 23 pounds.

The vet tells him his cat's weight is ⁵/₈ as his dog's weight.

Question:

How much does his cat weigh?

The Process:

Since the vet tells him his cat's weight is part of his dog's weight by ⁵/₈ part, let us create an 8-unit pattern that represents the dog's weight.

  • Jesse's dog weight in the pattern: \boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot } \rightarrow 23 \ pounds  
  • Jesse's cat weight in the pattern: \boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot } \rightarrow (5)/(8) \ of \ 23 \ pounds

And now, let us find out the cat's weight. As we know, the cats' weight is ⁵/₈ the dog's weight.

The cat's weight:  

\boxed{ \ = (5)/(8) * 23 \ }

\boxed{ \ = (5 * 23)/(8) \ }

Recall this \boxed{ \ 5 * (20 + 3) = (5 * 20) + (5 * 3) = 100 + 15 = 115 \ }

\boxed{ \ = (115)/(8) \ }

Recall this \boxed{ \ 115 / 8 = (14 * 8) + 3 \ }

\boxed{ \ = 14(3)/(8) \ }  as a mixed fraction

\boxed{ \ = 14(3 * 125)/(8 * 125) = 14(375)/(1,000) = 14.375 \ }  as a decimal fraction

Thus, his cat weigh is\boxed{ \ 14(3)/(8) \ or \ 14.375 \ pounds \ }

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Keywords: Jesse takes his dog and cat, annual vet visit, Jesse's dog weighs 23 pounds, the vet, his cats weight is 5/8, how much does his cat weigh, mixed fraction, decimal, part, pattern