PHYSICS HIGH SCHOOL

A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? assume that the sphere starts from rest and rolls without slipping.

Answers

Answer 1

Answer:

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

$KE = (1)/(2)Iw^2 +(1)/(2) mv^2$

also we know that

$I = (2)/(5)mR^2$

$w= (v)/(R)$

Now kinetic energy is given by

$KE = (1)/(2)((2)/(5)mR^2)w^2 +(1)/(2) m(Rw)^2$

$KE = (1)/(5)mR^2w^2 +(1)/(2) mR^2w^2$

$KE = (7)/(10)mR^2w^2$

$KE = (7)/(10)*150*(0.200)^2(50)^2$

$KE = 10500 J$

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

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Answers

An increase in the velocity of an object will increase the momentum of the object.

What is momentum?

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P = mv

where

m is the mass of the object
v is the velocity of the object

Thus, an increase in the velocity of an object will increase the momentum of the object.

Learn more about momentum here: brainly.com/question/7538238

Answer:

a. velocity. PLATO USERS

Explanation:

Once you have carried out your experiment and have some results, you shouldA. make a new hypothesis that fits your results
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C. design a new experiment to test your results
D. analyze your results and draw a conclusion

Answers

Answer:

I think the answer is D

Explanation:

not sure

but if its correct can i get brainliest??

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