Two cars leave towns 680 kilometers apart at the same time and travel toward each other. one car's rate is 10 kilometers per hour less than the other's. if they meet in 4 hours, what is the rate of the slower car?

Answers

Answer 1
Answer:

D = distance between the cars at the start of time = 680 km

v₁ = speed of one car

v₂ = speed of other car = v₁ - 10

t = time taken to meet = 4 h

distance traveled by one car in time "t" + distance traveled by other car in time "t" = D

v₁ t + v₂ t = D

(v₁ + v₂) t = D

inserting the values

(v₁ + v₁ - 10) (4) = 680

v₁ = 90 km/h

rate of slower car is given as

v₂ = v₁ - 10

v₂ = 90 - 10 = 80 km/h

Answer 2
Answer:

Final answer:

The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

Explanation:

The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:

  1. Begin by understanding that it is not two separate trips but merely one trip where they are traveling towards each other. This means collectively they've traveled 680 kilometers.
  2. Denote the slower car's rate as 'r'. The faster car would then have a rate of 'r + 10' km/hr.
  3. Since they are traveling towards each other for the same duration, you can set up the formula 'distance = rate * time' for BOTH cars, i.e.:
    4r (slower car's distance covered) + 4(r + 10) (faster car's distance covered) = 680km.
  4. Solve the equation for 'r'.

The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

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B.
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Answers

The Coriolis effect causes air circulation when Air from the equator moves toward the poles slower than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator faster than the ground below it, so friction causes it to veer to the west. The answer is letter A

Answer:

The answer to your question is A. Hope this helped

If an object is NOT accelerating, then one knows for sure that it is ___.A. at rest
B. moving with a constant speed
C. slowing down
D. maintaining a constant velocity

Answers


"Zero acceleration" means "velocity" that's not changing.

Sadly, it seems that both of these words are almost always
misinterpreted and misunderstood. "Acceleration" does NOT
mean "speeding up", and "velocity" does NOT mean speed.

"Velocity" is the speed AND direction of motion.  So, for example,
'30 miles per hour north' and '30 miles per hour west' are the same
speed but different velocities.

"Acceleration" is ANY change in speed OR direction.  Consider three
different families in three different cars.  One car is speeding up, one is
slowing down, and the third is driving around a curve at a steady speed.
ALL three of the cars are accelerating.

Answer:

Zero acceleration means velocity that's not changing.

Explanation:

At the local grocery store, you push a 14.5-kg shopping cart. You stop for a moment to add a bag of dog food to your cart. With a force of 12.0 N you now accelerate the cart from rest through a distance of 2.29 m in 3.00 s. What was the mass of the dog food?

Answers

Answer:

The mass of the dog food added is 9.03 kg

Explanation:

Given;

mass of the shopping cart, m₁ = 14.5 kg

let the mass of the bag added = m₂

the force applied, F = 12 N

initial velocity of the cart-bag system, u = 0

distance traveled by the system, d = 2.29 m

time of motion of the system, t = 3.0 s

The acceleration of the system is calculated as;

d = ut + (1)/(2) at^2\n\n2.29 = 0 + ((1)/(2) * 3^2)a\n\n2.29 = 4.5 a\n\na = (2.29)/(4.5) \n\na = 0.51 \ m/s^2

The total mass of the system (M) is calculated as follows;

F = Ma

M = F/a

M = (12)/(0.51)

M = 23.53 kg

The mass of the dog food added is calculated as;

m₂ = M - m₁

m₂ = 23.53 kg - 14.5 kg

m₂ = 9.03 kg

An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v sin θ / g 1. The same object is then raised again to the same height h but this time is thrown downward with velocity υ1 It now reaches the ground with a new velocity υ2. How is v2 related to v1?

Answers

Answer:

v^(2)_(2)=v^(2)_(1)+(v^(2)Sin^(2)\theta )/(g^(2))

Explanation:

Case I:

initial velocity, u = 0 m/s

Final velocity, v' = v Sinθ /g

Height = h

acceleration = g

Use third equation of motion, we get

v'^(2)=u^(2)+2as

\left ( (vSin\theta )/(g) \right )^(2)=0^(2)+2gh

h = (v^(2)Sin^(2)\theta )/(2g^(3))      . ... (1)

Case II:

initial velocity, u = v1

Final velocity, v = v2

height = h

acceleration due to gravity = g

Use third equation of motion, we get

v^(2)=u^(2)+2as

v^(2)_(2)=v^(2)_(1)+2gh

Substitute the value of h from equation (1) ,we get

v^(2)_(2)=v^(2)_(1)+2g(v^(2)Sin^(2)\theta )/(2g^(3))

v^(2)_(2)=v^(2)_(1)+(v^(2)Sin^(2)\theta )/(g^(2))

While watching a recent science fiction movie, one Klingon spaceship blows up a Droid spaceship with a laser gun. The Klingon crew watches out the port window and covers their ears to muffle the noise from the explosion. Scientifically, this scene is inaccurate becauseA) light can not reflect off objects in the vacuum of space.
B) they would not be able to see anything outside the window.
C) lasers can not be transmitted through the vacuum of space.
D) the sound of the explosion would not be transmitted back to their ship.

Answers

Scientifically this scene is inaccurate because the sound of the explosion would not be transmitted back to their ship. The correct option among all the options that are given in the question is the last option or option "D". As sound cannot travel through a vacuum, so it is not possible for the crew to hear the sound of explosion.

Answer:

D. the sound of the explosion would not be transmitted back to their ship.

Explanation:

Sound is a type of mechanical wave so it needs a solid to move through. Since space is a vacuum, the Klingon crew would not be able to hear the explosion.

A student throws a 5.0-newton ball straight up.What is the net force on the ball at its maximum
height?
(1) 0.0 N (3) 5.0 N, down
(2) 5.0 N, up (4) 9.8 N, down

Answers


If the ball weighs 5 newtons, then that's the force of gravity that
attracts it to the center of the Earth.  The force only depends on
the mass of the ball and its distance from the center of the Earth. 
The force of gravity doesn't care whether the ball is moving or at
rest. It doesn't change significantly until the ball moves to some
significant distance off the Earth's surface, which isn't happening
if it's tossed by a human being. 

So we have a downward force of 5 newtons on the ball at all times.
In order to find the net force on it, we have to identify any other
forces besides gravity that are also acting on it.

If the ball were moving through the air, then there would be a force
of air resistance on it, acting opposite to its motion. But when it's
at its maximum height, in the process of turning around from rising
to falling, there's an instant when it's not moving through the air at all,
so gravity is the only force acting on it. At that moment, the net force
on the ball is 5.0 newtons downward.