MATHEMATICS COLLEGE

Rewrite 4+8lnx=2 without logarithms

Answers

Answer 1

Answer:

4 + 8 ln(x) = 2

8 ln(x) = $(1)/(2) [/tex</p><p>ln (x) = [tex] (1)/(16)$

$e^(ln(x)) = e^{(1)/(16)$ by exponentiating both sides.

x = $= e^{(1)/(16)$

The six trigonometric functions, $\sin (\pi)/(4) =(1)/(√(2))$ , $\cos (\pi)/(4) =(1)/(√(2))$ , $\tan (\pi)/(4) =1$ , $\cot (\pi)/(4) =1$ , $\sec (\pi)/(4) =√(2)$ and $\csc (\pi)/(4) =√(2)$ .

Step-by-step explanation:

We have,

$(\pi)/(4)$

To write the six trigonometric functions = ?

$\sin (\pi)/(4) =(1)/(√(2))$

$\cos (\pi)/(4) =(1)/(√(2))$

$\tan (\pi)/(4) =1$

$\cot (\pi)/(4) =1$

$\sec (\pi)/(4) =√(2)$

$\csc (\pi)/(4) =√(2)$

∴ The six trigonometric functions, $\sin (\pi)/(4) =(1)/(√(2))$ , $\cos (\pi)/(4) =(1)/(√(2))$ , $\tan (\pi)/(4) =1$ , $\cot (\pi)/(4) =1$ , $\sec (\pi)/(4) =√(2)$ and $\csc (\pi)/(4) =√(2)$ .

Use the steps to determine the exact value of sin(−135)°.

Identify the reference angle, θ.

θ =
°

Answers

To solve for sin(-135), the reference angle will be obtained as follow:
sin(-135)
=-sin(135)
=-sin(180-135)
=-sin 45
hence
the reference angle θ=45°

Answer:

The reference angle will be ${\theta}=45^(\circ)$

Step-by-step explanation:

To solve for $sin(-135)$ , the reference angle can be obtained as follows:

= $sin(-135)$

= $- sin(135)$ (Because $sin(-{\theta})=-sin{\theta}$ )

Thus, the above equation can be written as:

= $-sin(180-135)$

= $-sin45$

Hence, the reference angle will be ${\theta}=45^(\circ)$

The linear function passes through the points (7,-19) and (-3,7). which statement must be true

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what are the statements ?

Let U be the set of natural numbers, A be the set positive odd integers and B be thepositive even integers. Determine
i. A U B
ii. A - B

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Answer:

Hope it helped u

Step-by-step explanation:

Help a brother out please

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Answer:

Bethlehem has temperatures ranging from 33.8 Fahrenheit to 55.4 Fahrenheit.

Step-by-step explanation:

Hope you got it.

Determine which consecutive integers do not have a real zero of f(x) = x^3 + 9x^2 + 8x – 5 between them.A.) (–8, –7)

B.) (4, 5)

C.) (0, 1)

D.) (–2, –1)

Answers

The integers (4, 5) do not have real zero.

What is zero of a function?

Knowing what zeros represent can assist us in determining when and how to locate the zeros of functions given their expressions and a function's graph. The value of x when the function itself reaches zero is typically referred to as a function's zero.

A function's zero can take many different forms, but as long as they have a y-value of zero, we will consider them to be the function's zero.

Given Expression

f(x) = x³ + 9x² + 8x - 5

to find which is not a real zero,

condition of real zero is for any function f(a , b) if f(a).f(b) < 0 the function have at least a zero.

1: (-8, -7)

f(-8).f(-7) = [(-8)³ + 9(-8)² + 8(-8) - 5][(-7³) + 9(-7)² + 8(-7) - 5]

f(-8).f(-7) = (-5)(37)

f(-8).f(-7) = -185 < 0 points have at least a zero

2: (4, 5)

f(4).f(5) = [(4)³ + 9(4)² + 8(4) - 5][(5³) + 9(5)² + 8(5) - 5]

f(4).f(5) = 235 x 385

f(4).f(5) = 94,475 > 0

points do not have any zeros

3: (0, 1)

f(0).f(1) = [(0)³ + 9(0)² + 8(0) - 5][(1³) + 9(1)² + 8(1) - 5]

f(0).f(1) = -5 x 13

f(0).f(1) = -65 < 0

points have a zero

4: (–2, –1)

f(-2).f(-1) = [(-2)³ + 9(-2)² + 8(-2) - 5][(-1³) + 9(-1)² + 8(-1) - 5]

f(-2).f(-1) = 7 x (-5)

f(-2).f(-1) = -35 < 0

points have a zero

Hence only point (4, 5) do not have a zero.

Learn more about zero of a function;

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Answer:

Option B (4,5)

Step-by-step explanation:

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Rewrite 4+8lnx=2 without logarithms

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What is zero of a function?

The six trigonometric functions, $\sin (\pi)/(4) =(1)/(√(2))$ , $\cos (\pi)/(4) =(1)/(√(2))$ , $\tan (\pi)/(4) =1$ , $\cot (\pi)/(4) =1$ , $\sec (\pi)/(4) =√(2)$ and $\csc (\pi)/(4) =√(2)$ .