A square has sides 10x. write and simplify an expression for the perimeter of that square

Answers

Answer 1

Answer: One side = 10x and a square has 4 equal sides.
10x * 4=40x

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If log 6=a, then log 600= ?

Answers

$\log 600 = \log (100 \cdot 6)= \log 100 + \log 6 = \log 10^2 + \log 6 = \n 2 \log 10 +\log 6 =2+\log 6 = \boxed{a+2} \n \hbox{From formulas:} \n \log a + \log b = \log (ab) \n \log a^b = b\log a$

One weekday, the ticket sales person at a bus station asks every 10th ticket buyer if they had planned to use a laptop computer while traveling. Of the 145 travelers questioned, 54 said yes.Based on this sample, predict how many people out of 3100 weekday bus travelers will use a laptop while traveling. Round to the nearest whole number.

Answers

From the 3100 weekday bus traveler, 310 travelers will be asked by the sales person. And for every 2.685 traveler questioned, a traveler will say yes. So there will be 115 bus travelers that will use a laptop computer while travelling.

What is 1 half subtract 1 tenth

Answers

To solve for $(1)/(2)- (1)/(10)$ You first need to find a common denominator.

To do so, you need to make both denominators 10 by multiplying the top and bottom of $(1)/(2)$ by 5

$(5)/(10)- (1)/(10)$ = $(4)/(10)$ Reduce by dividing both the top and bottom by 2

Your answer is $(2)/(5)$

The answer is 0.4 that is what i got

How do you factor 80y^2-4y-4? or is it prime?

Answers

$80y^2-4y-4\n\na=80;\ b=-4;\ c=-4\n\n\Delta=b^2-4ac\n\n\Delta=(-4)^2-4\cdot80\cdot(-4)=16+1280=1296 > 0\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(1296)=36\n\ny_1=(4-36)/(2\cdot80)=(-32)/(160)=-(1)/(5);\ y_2=(4+36)/(2\cdot80)=(40)/(160)=(1)/(4)$

$80y^2-4y-4=80(y+(1)/(5))(y-(1)/(4))\n\n\n80(y+(1)/(5))(y-(1)/(4))=4\cdot5\cdot4\cdot(y+(1)/(5))(y-(1)/(4))=4(5y+1)(4y-1)$

$80y^2-4y-4=80y^2-4y-16y+16y-4=80y^2-20y+16y-4\n\n=20y(4y-1)+4(4y-1)=(4y-1)(20y+4)$

$80y^2-4y-4=4(20y^2-5y+4y-1)=4[5y(4y-1)-(4y-1)]=\n \n=4(4y-1)(5y-1)$

A container contains balls numbered from 1 through 55. A ball is drawn randomly and replaced. Then a second ball is drawn randomly. What is the probability that the first ball is number 9 and the second ball is number 41?

Answers

Answer:

1/3025

Step-by-step explanation:

Prob. of getting a 9 is 1/55; likewise for 41. multiply the 2 probs. together. (1/55)^2=1/3025≈0.00033057851

Final answer:

The probability of drawing ball number 9 first and then drawing ball number 41 from a container of balls numbered 1 to 55, with replacement is 1/3025.

Explanation:

The question pertains to the field of probability in Mathematics. It is asking for the probability of first drawing ball number 9 and then drawing ball number 41 from a container that contains balls numbered from 1 to 55. Since the ball is replaced after the first draw, the total number of possibilities remains the same for both draws. Therefore, the individual probability of drawing either one of those balls at a certain draw is 1/55.

Given that these are independent events, we multiply the probabilities. Hence, the probability of drawing ball number 9 first and then drawing ball number 41 is: P(9 and 41) = P(9) x P(41) = (1/55) x (1/55) = 1/3025.

Learn more about Probability here:

brainly.com/question/32117953

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Simplify sin(180-x)°-sin x°

Answers

Answer:

Step-by-step explanation:

sin(180-x) - sin(x)

= sin(180) × cos(x) - cos(180) × sin(x) - sin(x)

= 0 × cos(x) - (-1) × sin(x) - sin(x)

= 0 + sin(x) - sin(x)

= 0

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