PHYSICS HIGH SCHOOL

You are running late to meet a friend at the movies. She calls to ask where you are. What would you be describing if you told her you were 20 meters away from the movie theatre at that moment?A. your length
B. your vector
C. your position
D. your displacement

Answers

Answer 1

Answer:

The correct answer is actually C. your position

JUST TOOK THE QUIZ AND GOT IT CORRECT

Answer 2

Answer: you would be describing your length

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A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally away from and below the point of release. What is the speed of the ball just before it strikes the ground?

Answers

The speed of the ball just before it strikes the ground is equal to 46.55 m/s.

Given the following data:

Horizontal distance = 65 meters

Height of building = 0.10 km = 100 meters

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 $m/s^2$ .

To determine the speed of the ball just before it strikes the ground:

First of all, we would determine the time it took the ball to strike the ground by using the formula for maximum height.

$H = (1)/(2) gt^2\n\n100 = (1)/(2) * 9.8 * t^2\n\n200 = 9.8t^2\n\nt^2 = (200)/(9.8) \n\nt^2=20.41\n\nt=√(20.41)$

Time, t = 4.52 seconds

Next, we would find the horizontal velocity:

$Horizontal\;velocity = (horizontal\;distance)/(time) \n\nHorizontal\;velocity = (65)/(4.52)$

Horizontal velocity, V1 = 14.38 m/s

Also, we would find the velocity of the ball in the horizontal direction:

$V_2^2 = U^2 + 2aS\n\nV_2^2 = 0^2 + 2(9.8)(100)\n\nV_2^2 = 1960\n\nV_2 = √(1960) \n\nV_2 = 44.27 \;m/s$

Now, we would calculate the speed of the ball just before it strikes the ground by finding the resultant speed:

$V = √(V_1^2 + V_2^2) \n\nV = √(14.38^2 + 44.27^2)\n\nV = √(206.7844‬ + 1959.8329‬)\n\nV =√(2166.6173)$

Speed, V = 46.55 m/s

Answer:

v = 46.55 m/s

Explanation:

It is given that,

A ball is thrown horizontally from the top of a building 0.10 km high, d = 0.1 km = 100 m

The ball strikes the ground at a point 65 m horizontally away from and below the point of release, h = 65 m

At maximum height, velocity of the ball is 0. So, using the equation of motion as :

$d=ut+(1)/(2)at^2$

Here, a = g

$100=0+(1)/(2)* 9.8t^2$

$t=4.51\ s$

Let $v_x$ is the horizontal velocity of the ball. It is calculated as :

$v_x=(65\ m)/(4.51\ s)=14.41\ m/s$

Let $v_y$ is the final speed of the ball in y direction. It can be calculated as :

$v_y^2+u_y^2=2as$

$u_y=0$

$v_y^2=2gd$

$v_y^2=2* 9.8* 100$

$v_y=44.27\ m/s$

Let v is the speed of the ball just before it strikes the ground. It is given by :

$v=√(v_x^2+v_y^2)$

$v=√(14.41^2+44.27^2)$

v = 46.55 m/s

So, the speed of the ball just before it strikes the ground is 46.55 m/s. Hence, this is the required solution.

Which kind of force do you exert on an object when you pull it toward you?

Answers

You should expect applied force.

Hope this helps love!

It's gravity I believe? I'm not entirely sure.

A spider is crawling on a wall. First it crawls 1 meter up, then 1 meter to the left, and then 1 meter down. what is its total displacement

Answers

1 meter up, 1 meter to the left and then 1 metter down.
It goes 1 meter up and 1 meter down, so its in the same place. The only displacement is 1 meter to the left.

Look at picture:

(hope this helps)

1 meter up and then 1 meter left, and then 1 meter down. The total displacement would be 1 meter. See Ayah's pic to help you understand more better:)

A ____________ reaction occurs when a substance is broken down into two or more simpler substances in a chemical reaction.

Answers

Answer: Decomposition

Explanation:

A chemical break down of a reactant into two or more products is known as Decomposition reaction. A substance decomposes to simpler substances.

It can be represented as:

AB → A + B

Example, water breaks down into oxygen and hydrogen

2 H₂O → 2 H₂ + O₂

Thus, the correct answer is:

A Decomposition reaction occurs when a substance is broken down into two or more simpler substances in a chemical reaction.

The reaction is called decomposition reaction in which substance(reactant) breaks down into 2 or more substances (products).

How could you compare the energy carried in two different longitudinal waves

Answers

U could compare them using the intensity technique when bending waves are negligible in comparison with quasi-longitudinal waves.

Energy carried in two ways can be campared by using the intensity technique when bending waves are negligible in comparison with quasi-longitudinal waves.

Why does light change path when it changes mediums