the vertex of the parabola below is the point (-3,-5). Which of these equations below could be one for this parabola?
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The answer is choice (B).
A standard quadratic written in vertex form is:
y = (x - h)^2 + k, where h and k are the x and y coordinates of the vertex.
So, if h is negative (in this case, -3), then it becomes x + 3.
If k is negative, though, (in this case, -5) then it becomes (x + 3)^2 - 5.
Therefore, the answer is (B).
Answer:
B
Step-by-step explanation:
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We can see that the lines intersect at (-5,3) on the graph, so that eliminates choices B and D. Both A and C say that the first line is y=x+8, which is true. A says that the second line is y+x=-2, and after isolating y, we get y=-x+2, which seems correct. Do the same for C, and you will find that it says the other equation is y=x-2, which is not true because it must have a negative slope. So your answer will be choice A.
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Hope its right!!!!!
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Answer: -8
Step-by-step explanation:
We must remember that, in geometric sequences, the ratio between the consecutive terms is constant.This is called "Common ratio" and is represented with "r".
We need to find the common ratio of this geometric sequence:
Divide one term by the previous term:
Then, the next term asked in the exercise can be found by multiplying -4 by 2.
Therefore, this is:
Answer:
-8
Step-by-step explanation:
r=2
so multiply third term by 2
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53=12(m-3/4)-16
First we have to multiply 12 times every argument from the parethesis.
53=12*m*-3/4*12-16
53=12m-9-16
53=12m-25 /+25 (add 25 both sides)
53+25=12m
78=12m /:12 (divide both sides by 12)
78:12=m
6.5=m - its the answer
First,
You must multiply 12 by m and 12 by -3/4(0.75) which is 12m and -9
Second,
12m - 9 - 16 ~~Combine Like Terms And It Will Become 12m + 25
53 = 12m + 25 ~~ You Must Subtract 25 From Both Sides Of The Equation And It Becomes 28 = 12m
Third,
28 = 12m ~~divide both sides by 12
12 12 ~~ 12m/12 cancels out and 28/12 is 2
Therefore Your Answer is 2