The midpoint of a segment is (−6,−5) and one endpoint is (1,3). Find the coordinates of the other endpoint.A. (8, 11)
B. (8, -13)
C. (-13, -13)
D. (-13, 11)

Answers

Answer 1
Answer:

Answer: C. (-13, -13)

Step-by-step explanation:

The midpoint (x,y) of a line segment having two end points (a,b) and (c,d) is given by :-

x=(a+c)/(2)\ ;\ y=(b+d)/(2)

Given : The midpoint of a segment is (-6,-5) and one endpoint is (1,3).

Let the coordinates of other end point be (a,b) then , we have

-6=(a+1)/(2)\ ;\ -5=(b+3)/(2)\n\n\Rightarrow\ a+1=2*-6\ ;\ b+3=2*-5\n\n\Rightharrow\  a+1=-12\ ;\ b+3=-10\n\n\Rightarrow\ a=-12-1\ ;\ b=-10-3\n\n\Rightarrow\ a=-13,\ ;\ b=-13

Hence, the coordinates of the other endpoint = (-13,-13)

Answer 2
Answer: C. (-13,-13)
You take the x of the midpoint and equal it to the formula of the midpoint so it will be -6 = 1+x/2 so 1st you times 2 by 6 because you wanna get rid of 2 so it will -12 Then when you move 1 so x is alone it will be -1 so -12-1= -13
Same thing for y

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Answers

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RShas endpoints R(1,7) and S(13,14). Point T divides
RS
into two parts with lengths in a ratio of 2:1.
What are the two possible locations of T?

Answers