What technology is involved in gathering or using this resource?

Answers

Answer 1

Answer: The answer is there are three primary technologies by which solar energy is commonly harnessed:photovoltaics (PV), which directly convert light to energy; concentration solar power (CSP).

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What is the acceleration due to gravity at a location where a 15 kilogram mass weighs 45 newtons?
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The metric unit of force is _____. kg kg/cm3 kg/cm2 N
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What is the energy of work done lifting 2kg mass rocket to a height of 130 m

Answers

Work done to lift the mass is given by

W = mgH

here we know that

m = mass = 2 kg

g = acceleration due to gravity = 9.8

H = height = 130 m

now using the above equation we can write

$U = 2* 9.8 * 130$

$U = 2548 J$

so the energy required to do the work is 2548 J

work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm

A string is wrapped around a pulley with a radius of 2.0 cm. The pulley is initially at rest. A constant force of 50 N is applied to the string, causing the pulley to rotate and the string to unwind. If the string unwinds 1.2 m in 4.9 s, what is the moment of inertia of the pulley

Answers

Answer:

0.20kg-m^2

Explanation:

Let the linear velocity of the rope(=of pulley) is v m/s

Using kinematic equation

=> v = u + at

=>v = 0 + 4.9a

=>v = 4.9a ------------ eq1

By v^2 = u^2 + 2as

=>v^2 = 0 + 2 x v/4.9 x 1.2

=>4.9v^2 - 2.4v = 0

=>v(4.9v - 2.4) = 0

=>v = 2.4/4.9 = 0.49 m/s

Thus by v = r x omega

=>omega = v/r = 0.49/0.02 = 24.49 rad/sec

BY W = F x s = 50 x 1.2 = 60 J

=>KE(rotational) = W = 1/2 x I x omega^2

=>60 = 1/2 x I x (24.49)^2

=>I = 0.20 kg-m^2

A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for the projectile to hit the ground, to the nearest tenth of a second. Record your answer in the boxes below. Be sure to use the correct place value.

Answers

Answer:

0.6 seconds

Explanation:

The time to fall from height h is ...

t = √(2h/g)

t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

Answer:

0.6seconds

isuranswer:)

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Magma that cools and crystallizes on Earth's surface forms A. quartz.
B. marble.
C. intrusive rocks.
D. extrusive rocks.

Answers

The correct answer is:

D. Extrusive rocks.

The explanation:

when extrusive igneous rocks form when magma reaches the Earth's surface a volcano and cools quickly. Most extrusive (volcanic) rocks have small crystals. Examples include basalt, rhyolite, andesite, and obsidian.

The answer is D. Extrusive igneous rocks form when magma reaches the Earth's surface a volcano and cools down very quickly. This forms many small crystal on the rock.

What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.Select one:

a. 10N

b. 100N

c. 200N

d. 98N

Answers

The smallest value of the force that will make the block not to slide down is 10 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

Mass (m) = 8 Kg

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) =?

N = mg

N = 8 × 10

N = 80 N

Finally, we shall determine the frictional force.

Coefficient of friction (μ) = 0.4

Normal reaction (N) = 80 N

Frictional Force (F) =?

F = μN

F = 0.4 × 80

F = 32 N

Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the blocknot to slide down.

From the options given above, only option A has a force that is lesserthan the frictional force.

Therefore, the correct answer to the question is Option A. 10 N

Learn more about frictional force:

brainly.com/question/20049999

Final answer:

The smallest value of the force that will not slide the 8.0 kg block down the wall is 31.36 N.

Explanation:

To determine the smallest value of the force such that the 8.0 kg block will not slide down the wall, we need to consider the static friction between the block and the wall. The formula for static friction is fs = μs * N, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is mg = 8.0 kg * 9.8 m/s^2 = 78.4 N. Therefore, the smallest value of the force is equal to the maximum static friction force, which can be calculated as fs = 0.4 * 78.4 N = 31.36 N. So the correct answer is 31.36 N.

Learn more about Static Friction here:

brainly.com/question/13000653

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Use the Pythagorean theorem to answer this question. A paper airplane is thrown westward at a rate of 6 m/s. The wind is blowing at 8 m/s toward the north. What is the actual velocity of the airplane?2 m/s, northwest
10 m/s, northwest
14 m/s, northwest
48 m/s, northwest