What is base 1 of a trapezoid in which A=(48x+68) in^2, height =8, and base 2 = (9x + 12)

Answers

Answer 1
Answer: A=(1/2)(b1+b2)h = 

=(48x+68)in² = (1/2)( b1+(9x+12))8 


the answer is = b1= 3x+5

i hope that helped =D

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Factor completely 6x^4y^3 + 21x^3y^2 − 9x^2y.3xy(2x^3y^2 + 7xy − 3x) 3x^2y(2x^2y^2 + 7xy − 3) 3x^2y3&(2x^2 + 7xy − 3) 3x^2y(2x^2y + 7xy − 3y)
There are 6 red marbles, 3 blue marbles, and 7 yellow marbles, find the probability of selecting a blue marble
Please help me solve my problem!!!
If you are supposed to take pills at half-hour intervals, how many minutes would 5 pills last? A) 120 minutes B) 125 minutes C) 130 minutes D) 135 minutes
How do you graph and work problem x+4y=16??

Fill in the common equivalents. 1.) 66 2/3% 2.)3/4 =_____%

Answers

3/4 = 75/100 = 75%
3/4 = 75%
think of quarters 3 quarters is 75 cents so it is 75% 

Suppose that the functions f and g are defined for all real numbers x as follows.f(x) = 3x+3
g(x) = 5x
Write the expressions for (f times g)(x) and (f+g)(x) and evaluate (f-g)(2)

Answers

Answer:

Step-by-step explanation:

a) fg(x)

--> f(5x)

--> 3(5x)+3

--> 15x+3

b) f+g(x)

--> 3x+3+ 5x

c) (f-g)(2)

3x+3- 5x

--> 3(2)+3-5(2)

--> -1

Answer:

solution given:

f(x) = 3x+3

g(x) = 5x

now

(f times g)(x)=?

(f+g)=?

(f-g)=?

we have

(f times g)(x)=f(g(x))

substituting value of g(x)

f(g(x))=f(5x)

now replacing value of x in f(x)

f(5x)=3(5x)+3

solving it

f(5x)=15x+3

so (f times g)(x) =15x+3

Step-by-step explanation:

again,

(f+g)(x)=f(x)+g(x)=3x+3+5x=8x+3

so

(f+g)(x) =8x+3

again

we need to find (f-g)(x) first so

(f-g)(x)=f(x)-g(x)=3x+3-5x=-2x+3

now

(f-g)(2)=-2*2+3=-1

(f-g)(2)=-1

On Tuesday morning, the temperature was recordedat 5°C. Over the course of the day, the temperature
dropped 7º. After this drop, what temperature will be
recorded?
A 12° C
B 2°C
C -2°C
D -12° C

Answers

C. -2° :) hope this helps lmk!

Brian invested his savings in two investment funds. The $8000 that he invested in Fund A returned a 4% profit. The amount that he invested in Fund B returned a 1% profit. How much did he invest in Fund B, if both funds together returned a 2% profit?

Answers

Answer: Brian invested $16000 in Fund B .

Step-by-step explanation:

Let x be the amount Brian invested in Fund B.

Given, The $8000 that he invested in Fund A returned a 4% profit. The amount that he invested in Fund B returned a 1% profit.

i.e. profit on Fund A = 4% of 8000 = 0.04 ×8000 = $320

Profit on Fund B = 1% of x = 0.01x

Together they earn 1% profit, i.e. Combined profit = 2% of (8000+x)

= 0.02(8000+x)

As per question,

Combined profit=Profit on Fund A+Profit on Fund B

\Rightarrow\ 0.02(8000+x) =320+0.01x\n\n\Rightarrow\  0.02(8000) +0.02x=320+0.01x\n\n\Rightarrow\  160+0.02x=320+0.01x\n\n\Rightarrow\  0.02x-0.01x=320-160\n\n\Rightarrow\  0.01x=160\n\n\Rightarrow\  x=(160)/(0.01)\n\n\Rightarrow\ x=16000

Hence, Brian invested $16000 in Fund B .

Each Friday, the school prints 400 copies of the school newsletter. The equation c = 400w models the relationship between the number of weeks and the total number of copies of the newsletters printed. What is true of the graph of this scenario

Answers

A viable point on the graph is ( 8, 3200 )

The values of w must be... Any WHOLE number.

C=400w can be written as y=400x. This is the equation of a line with slope 400 and y-intercept of 0.
The slope of positive 400 represents the number of copies printed each week. Since the slope is positive, the number of copies increases each week.

Find the common ratio for the following sequence. 0.1, 0.01, 0.001, ... 1 0.1 0.01 0.001

Answers

Answer:

common ratio for the given sequence is 0.1

Step-by-step explanation:

Common ratio(r) defined as the ratio of term to the previous term.

Given the sequence:

0.1, 0.01, 0.001, ...

a_1 = 0.1

a_2 = 0.01

a_3 = 0.001 ......

by definition of common difference;

r = (a_2)/(a_1)=(a_3)/(a_2).....

Substitute the given values we have;

r = (0.01)/(0.1)=(0.001)/(0.01).....

Simplify:

r = 0.1

Therefore, the common ratio for the given sequence is 0.1

The common ratio is 0.10

0.1   x 0.1 = 0.01
0.01 x 0.1 = 0.001

common ratio is the ratio of a term to the previous term.

0.1 is the previous term of 0.01

common ratio = 0.01/0.1 = 0.10
common ratio = 0.001/0.01 = 0.10