Answer:
Added 19 to each side
Step-by-step explanation:
15x-19=4x+11
Add 19 to each side
5x-19+19=4x+11+19
5x = 4x+30
Answer:
added 19 and 11
To solve the quadratic equation 4x^2 + 20x = -29 using the quadratic formula, we can first rearrange the equation to bring all terms to one side:
4x^2 + 20x + 29 = 0
Now we can identify the coefficients a = 4, b = 20, and c = 29 in the general quadratic equation ax^2 + bx + c = 0. Applying the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values for a, b, and c into the quadratic formula:
x = (-(20) ± √((20)^2 - 4(4)(29))) / (2(4))
Simplifying further:
x = (-20 ± √(400 - 464)) / 8
x = (-20 ± √(-64)) / 8
x = (-20 ± 8i) / 8
Now, we can simplify the expression:
x = -20/8 ± (8i)/8
x = -5/2 ± i
Therefore, the roots of the given quadratic equation are:
x = -5/2 + i
x = -5/2 - i