Question 2 Unsaved
A square has a side length of 2x+1. If the perimeter is 28, what is x?

Answers

Answer 1

Answer:

bearing in mind that a square has 4 equal sides, and the perimeter is the sum of all sides.

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there are 650 students in a school if the number of girls is 106 more than the boys how many boys are in the school
What is the value of r if the line that passes through (4,3) and ( -5, r ) has a slope of -1 ?
Help my please thanks
The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively. The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively. a. Determine the probability of high ink viscosity given poor print quality. b. Given poor print quality, what problem is most likely?
Which Polygons are similar to A? PLEASE ANSWER QUICKLY

A rocket is launched upward so that its distance, in feet, above the ground after t seconds is represented by the function below. What is its maximum height? h(t)=−16t2+320t

Answers

Answer: 1600 feet.

Step-by-step explanation:

Given : A rocket is launched upward so that its distance, in feet, above the ground after t seconds is represented by the function $h(t)=-16t^2+320t$

To find : its maximum height.

First we differentiate the given function , we get

$h'(t)=(2)(-16)t+320=-32t+320$

Put $h'(t)=0$ , we get

$-32t+320=0\n\n\Rightarrow\ t=(-320)/(-32)=10$

Hence, at t=10 , rocket achieves its maximum height.

$\text{Maximum Height =}h(t)=-16\left(10\right)^(2)+320\left(10\right)\n\n=-1600+3200=1600$

Hence, its maximum height = 1600 feet.

Answer:

1600 ft

Step-by-step explanation:

We are given that a rocket is a launched upward so that its distance(feet) above the ground after t seconds is represented by the function

$h(t)=-16t^2+320t$

We have to find the maximum height.

Substitute h(t)=0

$-16t(t-20)=0$

$t=0,t-20=0\implies t=20$

When t=0 it means the rocket is at ground launch.

When t= 20 s.

Total time taken by rocket=20 s.

Half of the time taken to reach maximum height and half of the time taken to reach ground back.

Therefore, time taken by rocket to reach maximum height= $(20)/(2)=10s$

Substitute t=10 in given function

Then we get

h(10)=-16(10)^2+320(10)=-1600+3200=1600 ft[/tex]

Hence, the maximum height=1600 ft

Given the following function , find f(-2) ,f (0) and f(2) F(X)=-3x-3 F(-2) = help me please i don't understand

Answers

Answer:

$\large{f(-2)=3\n\nf(0)=-3\n\nf(2)=-9}$

Step-by-step explanation:

$f(x)=-3x-3\n\nf(-2)\to\text{put x = -2 to the equation of the function}\ f(x):\n\nf(-2)=-3(-2)-3=6-3=3\n-------------------------\nf(0)\to\text{put x = 0 to the equation of the function}\ f(x):\n\nf(0)=-3(0)-3=0-3=-3\n------------------------\nf(2)\to\text{put x = 2 to the equation of the function}\ f(x):\n\nf(2)=-3(2)-3=-6-3=-9$

True or False
100% of any number must greater than or
equal to 100

Answers

False
For example 100% of 2 is 2

It takes andre 4 minutes to swim 5 laps. At this rate heswims how many laps per minute.

Answers

Answer: It takes him 1 minute and 25 seconds

Step-by-step explanation:

5 divided 4

4 times 1 = 4

5-4=1

put the decimal and make 1=10 Ans.: 1.25

4 times 2 = 8

10-8=2

put the 0 = 20

4 times 5 =20

20-20=100

Events A and B are mutually exclusive. Suppose event A occurs with probability 0.02 and event B occurs with probability 0.73. Compute the probability that B occurs or A does not occur (or both). Compute the probability that either B occurs without A occurring or A and B both occur

Answers

Answer:

1. The probability that B occurs or A does not occur (or both) is 0.73.

2. The probability that either B occurs without A occurring or A and B both occur is 0.73.

Step-by-step explanation:

It is given that the events A and B are mutually exclusive. It means the intersection of A and B is 0.

$P(A\cap B)=0$

Given information:

$P(A)=0.02$

$P(B)=0.73$

We get,

$P(A')=1-P(A)=1-0.02=0.98$

$P(B')=1-P(B)=1-0.73=0.27$

(1) We need to find the probability that B occurs or A does not occur (or both).

$P(B\cup A')+P(A\cap B)=P(B)+0$

$P(B\cup A')+P(A\cap B)=0.73+0$

$P(B\cup A')+P(A\cap B)=0.73$

Therefore the probability that B occurs or A does not occur (or both) is 0.73.

(2) We need to find the probability that either B occurs without A occurring or A and B both occur.

$P(B\cup A')+P(A\cap B)=P(B)+0$

$P(B\cup A')+P(A\cap B)=0.73+0$

$P(B\cup A')+P(A\cap B)=0.73$

Therefore the probability that either B occurs without A occurring or A and B both occur is 0.73.

Final answer:

For mutually exclusive events A and B, the probability that B occurs or A does not occur is approximately 1.45. The probability that either B occurs without A occurring or A and B both occur is 0.73 because A and B are mutually exclusive.

Explanation:

Events A and B are defined as mutually exclusive, which means they cannot occur at the same time. Hence, the probability that A and B both occur (referred to as P(A AND B)) is 0. In this question, for the first scenario, we need to compute the probability that B occurs or A does not occur which is denoted as P(B OR not A). Since events A and B are mutually exclusive, not A occurs with probability 1 - P(A) = 0.98. So, P(B OR not A) = P(B) + P(not A) - P(B AND not A) = 0.73 + 0.98 - (0.73 * 0.98) = 1.45 (approximately).

For the second scenario, we need to calculate the probability that either B occurs without A occurring or A and B both occur which is expressed as P((A and B) OR (B and not A)). But as we know P(A and B) = 0 for mutually exclusive events, there only remains P(B and not A). Again, as A and B are mutually exclusive, we can be sure that if B is happening, A is not, so the answer is P(B) = 0.73.