Answer:
The energy required to remove the the electrons from gaseous atom is called ionization energy.
Explanation:
Ionization energy:
The amount of energy required to remove the electron from gaseous atom is called ionization energy.
Trend of ionization energy in periodic table:
Along period:
The atomic size tend to decrease in same period of periodic table with increase of atomic number because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Along group:
Atomic size increases with increase of atomic number from top to bottom. The nuclear attraction on valance shell became weaker and thus it becomes easy to remove an electron from valance shell and this can be done with less amount of energy. That's why ionization energy decreases from top to bottom.
The energy required to remove an electron from an atom in the gaseous state is called the ionization energy.
Ionization energy, also known as ionization potential, refers to the minimum amount of energy required to remove an electron from an atom or ion in its gaseous state, resulting in the formation of a positively charged ion.
The ionization energy can vary depending on the specific electron being removed (valence electron or inner shell electron) and the atom or ion involved. Generally, it requires more energy to remove electrons from atoms with higher nuclear charges or tighter electron configurations.
Read moter on ionization energy. here brainly.com/question/30831422
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Answer:
Abdid has most likely found a new dwarf planet.
Explanation:
Dwarf planets are too small to be considered planets, but are also two big to be considered something else. A dwarf planet has to have sufficient mass so that the self-gravity is strong enough to create its round shape. Other qualifications of a dwarf planet is that it has not cleared the neighborhood around its orbit and it cannot be a satellite. Based on the location, size, and shape of the object Abdid has discovered, it is likely he discovered a new dwarf planet in the asterioid belt. One of the most famous is Ceres.
Answer:
The correct answer is option (2).
Explanation:
Carbon-12:
Atomic Number = 6
Mass number = 12
Nuclear charge = number of protons = +6
Number of electrons = 6
Carbon-14:
Atomic Number = 6
Mass number = 14
Nuclear charge = number of protons = +6
Number of electrons = 6
An atom of carbon-12 and an atom of carbon-14 only differ in their mass number as C-12 has mass number of 12 and C-14 has mass number of 14.
Answer:
0.9852 moles of CaO
Explanation:
Reaction equation for the decomposition of CaCO₃:
CaCO₃ → CaO + CO₂
The question asks how many moles of CaO form when 98.60g of CaCO₃ decompose.
We can see from the reaction equation that for every mol of CaCO₃, one mol of CaO will be produced (molar ratio 1:1)
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So first we need to calculate how many moles are the 98.60g of CaCO₃:
Molar Mass of CaCO₃ = molar mass Ca + molar mass C + 3 * molar mass O
= 40.078 + 12.011 + 3 * 15.999 = 100.086 g/mol
Moles of CaCO₃ = mass CaCO₃ / molar mass CaCO₃
Moles of CaCO₃ = 98.60 g / 100.086 g/mol = 0.9852 moles CaCO₃
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As we said before for every mol of CaCO₃, one mol of CaO is produced.
So the decomposition of 0.9852 moles of CaCO₃ will produce 0.9852 moles of CaO.
Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 .
no.of moles=mass /relative molecular mass