Mercury has a specific gravity of 13.6. how many milliliters of mercury have a mass of 0.35 kg
Answers
The formula for specific gravity is:
where is the density of the substance and
is the density of water.
The density of water, =
Substituting the values in above formula we get,
The formula of density is:
The density of mercury is
The mass of mercury is
Substituting the values in density formula:
The amount, in milliliters, of mercury that will have a mass of 0.35 kg would be 25.74 mL.
If the specific gravity of mercury is 13.6, the density can be obtained such that:
Density of mercury = specific gravity of mercury/density of water
The density of water is 1 g/mL. Thus:
Density of mercury = 13.6/1
= 13.6 g/mL
Also; density = mass/volume
volume = mass/density
= 350/13.6
= 25.74 mL
Thus, the number of milliliters of mercury that will have a mass of 0.35 kg would be 25.74.
More on density can be found here: brainly.com/question/14940265?referrer=searchResults
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Smoking marijuana can be as unhealthy as smoking cigarettes and ___________a. can cause cancer.b. results in "smokers breath."c. can lead to premature aging.
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an implosion
an endothermic process
a phase change
(please explain! Do not jus give me the answer... I know its not B or
d.
Answers
Answers
Answer is: C. Water can dissociate many ionic compounds through ion-dipole interactions.
For example, dissociation of potassium bromide: KBr(aq) → K⁺(aq) + Br⁻(aq).
Some ionic compounds cannot dissociate in water, for example calcium sulfate (CaSO₄), silver chloride (AgCl), lead(II)-carbonate (PbCO₃).
An ion-dipole is electrostatic interaction between a charged ion (cations and anions) and a molecule that has a dipole (in this example water).
Dipole is a separation of positive and negative charges. In water, hydrogen has positive and oxygen has negative charge.
Answers
Answers
The substrate, enzyme pair from the citric acid cycle that is INCORRECT is E) Citrate, aconitase.
The citric acid cycle, also known as the Krebs cycle, is a crucial metabolic pathway for generating energy in cells. Each step involves specific substrates and enzymes. While all other options (A, B, C, and D) correctly match substrates and enzymes involved in the cycle, option E (Citrate, aconitase) is incorrect.
Aconitase is responsible for catalyzing the interconversion of citrate and isocitrate, not for the conversion of citrate itself. The correct pair for citrate is citrate synthase, which catalyzes the formation of citrate from oxaloacetate and acetyl-CoA.
Understanding these substrate-enzyme pairs is essential in comprehending the citric acid cycle's intricacies. Accurate knowledge of these reactions aids in grasping how cells produce energy through this pathway. This emphasizes the significance of precise knowledge of biochemical pathways for an accurate understanding of cellular processes.
In the context of cellular metabolism, identifying the correct enzyme for each substrate is vital for accurate biochemical analysis and the design of targeted interventions for metabolic disorders. Among the given options, the substrate, enzyme pair that is incorrect in the citric acid cycle is Citrate, aconitase.
To Know more about Enzyme, refer;
Final answer:
The incorrect substrate-enzyme pair from the citric acid cycle is Oxaloacetate, citrate synthase.
Explanation:
The citric acid cycle, also known as the Krebs cycle or tricarboxylic acid cycle, is a series of chemical reactions that occur in the mitochondria of cells. It plays a crucial role in the aerobic respiration process, generating energy-rich molecules such as ATP.
The citric acid cycle involves the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins. Each step of the cycle is catalyzed by a specific enzyme, which acts on a particular substrate.
The correct substrate-enzyme pairs in the citric acid cycle are as follows:
- Isocitrate, isocitrate dehydrogenase
- Succinyl CoA, succinate dehydrogenase
- Fumarate, fumarase
- Oxaloacetate, citrate synthase
- Citrate, aconitase
Therefore, the incorrect substrate-enzyme pair from the given options is D) Oxaloacetate, citrate synthase.
Learn more about substrate-enzyme pairs in the citric acid cycle here:
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Answers
pH = -log[H+]
4.2 = - log [H+]
[H+] = 6.31 x 10^-5 M
Therefore, the correct answer from the choices listed above is option D, 0.00006 M.
[H+] = 10 ^- pH
[H+] = 10 ^- 4.2
[H+] = 0.00006 M
Answer D