The longest side of a triangle is twice as long as the shortest side the remaining side is 25cm find the length of the other two sides if the perimeter is 70 cm

Hello There,

There are 3 aspects x,y,z in a triangle. x = Shortest part z = Longest part y = third part provided that y=25; z=2x; x+y+z = 70 subsequently the respond is derived as follows: x+y+z = 70 x+25+2x = 70 3x+25 = 70 3x = 70-25 3x = 40 5 x = 40 5/3 x = 15 consequently the three aspects are x=15cm, y=25cm, and z=30cm And this could be a Scalene Triangle. desire that enables.

2x + x + 25 = 70

3x = 45

x = 15

Longest = 30

Shortest =15

70cm-25cm= 45cm.

45 divided by 3 = 15cm

longest side=30cm

shortest side=15cm

remaining side=25cm

perimeter=70cm

and then u have: 2x + x + 25 = 70

3x = 45

x = 15

Hope this Helps and Have a Nice Day Bye!

Final answer:

The shortest side of the triangle is 15 cm, the longest side is 30 cm, and the remaining side is 25 cm.

Explanation:

To find the lengths of the other two sides of the triangle, we can set up a system of equations using the given information.

Let the shortest side be x cm.

According to the problem, the longest side is twice as long as the shortest side, so it is 2x cm.

The remaining side is given as 25 cm.

From the perimeter of the triangle, we can write the equation:

x + 2x + 25 = 70

Simplifying the equation, we have:

3x + 25 = 70

Subtracting 25 from both sides, we get:

3x = 45

Dividing by 3, we find that:

x = 15

Therefore, the shortest side is 15 cm. The longest side is twice as long, so it is 2 * 15 = 30 cm. The remaining side is given as 25 cm.

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