MATHEMATICS MIDDLE SCHOOL

Plz show your work. Thx!! 2.8 = b/4

Answers

Answer 1

Answer:

Hey there!

$(b)/(4) = 2.8$

Firstly, we have to multiply by $4$ on each of the sides you are working with

$(b)/(4) = 2.8 \n \n(b)/(4) (4) \n \n 2.8(4) \n \n Cancel: (4)/(4) \n \n Keep:2.8(4)$

Answer:

$2.8 (4) = 11.2 \n \nAnswer: b = 11.2$

Good luck on your assignment and enjoy your day!

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Find the distance between riverside and Milton if they are 12cm apart on a map with a scale of 4cm :21km

Answers

since 4 cm is 21 km
12 cm is 63 km apart

The answer would be 63km.

I got this by saying:

For every 4cm, there are 21km.

There are 3 sets of 4cm in 12cm.

3*4=12
21*3=63

Solve irrational equation pls

Answers

$\hbox{Domain:}\nx^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\nx^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\nx(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\n(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle3,\infty)$

$√(x^2+x-2)+√(x^2-4x+3)=√(x^2-1)\nx^2-1=x^2+x-2+2√((x^2+x-2)(x^2-4x+3))+x^2-4x+3\n2√((x^2+x-2)(x^2-4x+3))=-x^2+3x-2\n√((x^2+x-2)(x^2-4x+3))=(-x^2+3x-2)/(2)\n(x^2+x-2)(x^2-4x+3)=\left((-x^2+3x-2)/(2)\right)^2\n(x+2)(x-1)(x-3)(x-1)=\left((-x^2+x+2x-2)/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-x(x-1)+2(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-(x-2)(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=((x-2)^2(x-1)^2)/(4)\n4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\n$
$4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\n(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\n(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\n(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\n(x-1)^2(3x^2-28)=0\nx-1=0 \vee 3x^2-28=0\nx=1 \vee 3x^2=28\nx=1 \vee x^2=(28)/(3)\nx=1 \vee x=\sqrt{(28)/(3)} \vee x=-\sqrt{(28)/(3)}\n$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\nx\in\langle1,2\rangle\n$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{(28)/(3)}, -\sqrt{(28)/(3)}\}\n\boxed{\boxed{x=1}}$

A video game that normally sells for $80 is on sale for $68. What is the percent of discount for the sale price ?

Answers

the discount is 15% off
80-68=12
12 is 15% of 80

Answer:The discount is 15%

Step-by-step explanation:80-68=12. 12 is 15% of 80

What point on the number line represents sea level?

Answers

Zero because the height of land and depth of places is measured according to sea level which is considered the baseline

the answer here would be 0
.................

Last summer,Karl went to the beach every 2 days. Antonia went to the beach every 3 days.How often did they see each other at the beach?

Answers

I think it would be every six days because if you count by threes and then by twos you get six both times and they would see each other on the sixth day. Hope that helped you :D

They see each other every 6 days. You just need to find the LCM of 2 & 3 which is 6.

Hope I helped:P

Help!Last one I say the answer is D