Is a tree getting struck by lightning a physical or chemical change?

Answers

Answer 1
Answer:

A tree getting struck by lightning, it is an example of a physical change.

It is so because when a tree getting struck by lightning, it encountered a strong force of power but no new substance is formed here. So it is a physical change, if it is a chemical change then a new substance must formed here. So when a tree getting struck by lightning, it is an example of a physical change.

Answer 2
Answer:

Final answer:

A tree getting struck by lightning involves both physical and chemical changes but the most prominent change is physical due to the visible damage and the instant vaporization of the tree's sap.

Explanation:

When a tree is struck by lightning, both physical and chemical changes occur. The lightning's immense heat can cause the sap inside the tree to instantly turn into vapor which results in a physical change. Additionally due to the lightning's high temperature, some of the tree's matter could possibly undergo chemical reactions such as combustion, leading to new matter being produced, which is a chemical change.

However the most prominent change observed is physical, as the visible damage to the tree and the immediate change from solid to vapour state of the sap are the most noticable effects. Thus, in essence a tree getting struck by lightning mainly causes a physical change.

Learn more about Physical and Chemical Changes here:

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2 years ago a 4.00 l flexible container holds a sample of hydrogen gas at 153 kpa. if the pressure increases to 203 kpa and the temperature remains constant, what will the volume be?

Answers

To solve this we assume that the gas is an idealgas. Then, we can use the ideal gas equation which is expressed as PV = nRT. Ata constant temperature and number of moles of the gas the product of PV isequal to some constant. At another set of condition of temperature, theconstant is still the same. Calculations are as follows:

 

P1V1 =P2V2

 V2 = P1 x V1 / P2

 V2 = 153 x 4 / 203

 V2 = 3 L

What kind of reaction occurs when a molecule of glucose reacts with oxygen to give carbon dioxide and water?A. an exothermic reaction

B. an endothermic reaction

C. a synthesis reaction

D. an irreversible reaction

Answers

A) Exothermic reaction. Exothermic reactions occur when energy or a new product is being releases(gas, energy, heat)
it is a i made a 100 on plato

How many moles are in 1.9 x 10^25 molecules of carbon dioxide

Answers

1 mole ----------- 6.02x10²³ molecules
? moles --------- 1.9x10²⁵ molecules

moles = 1.9 x 10²⁵ * 1 / 6.02x10²³

= 1.9 x 10²⁵ / 6.02x10²³

= 31.561 moles

hope this helps!

Which of these laboratory techniques is best to separate from a liquid to recover the liquid

Answers

It depends on what you are separating from the liquid. If it is a solid you can just filter it or put it in a centrifuge. If it is a dissolved solvent you might need to use something like chromatography. I am not very sure though. I hope this helps. Let me know if anything is unclear.

Which of these statements is true? A.
Some molecules may contain no atoms.


B.
Some elements found in nature exist as molecules.


C.
Some compounds include only one type of element.


D.
Some atoms are made of two or more different elements. Which of these statements is true?


A.
Some molecules may contain no atoms.


B.
Some elements found in nature exist as molecules.


C.
Some compounds include only one type of element.


D.
Some atoms are made of two or more different elements.

Answers

Pretty sure it's B. If not, then it's C.

How many moles are in 68.5 liters of oxygen gas at STP?

Answers

We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.

68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2

Explanation:

It is known that at STP, there are 22.4 L present in one mole of a substance.

Therefore, in 68.5 liters there will be 1 mol divided by 22.4 L times 68.5 L.

Mathematically,      68.5 L * (1 mol O_(2))/(22.4 L)

                              = 3.05 mol

Hence, we can conclude that there are 3.05 moles present in 68.5 liters of oxygen gas at STP.