Would anyone be willing to help me with geometry?
Answers
From the second and third steps, we know that m∠TUV = m∠1 + m∠2. We also know that m∠XWV = m∠3 + m∠4. Since ∠TUV and ∠XMV both measure 90°, we can set their measures equal to each other:
m∠TUV = m∠XMV
or equivalently:
m∠1 + m∠2 = m∠3 + m∠4
Next, we can use the fact that ∠1 ≅ ∠3 to say that m∠1 = m∠3, while allows us to replace one with the other. Here, we'll replace m∠3 with m∠1:
m∠1 + m∠2 = m∠1 + m∠4
Subtracting m∠1 from either side:
m∠2 = m∠4, which implies that ∠2 ≅ ∠4, as we wanted to show.
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2)9.
3)10.
4)None of the choices are correct.
Answers
Answer:
We know angle ABD is a right angle due to the marking, therefor 4x + 5x= 90.
9x = 90
x = 10.
Therefor the unknown value of x is 10.
Answer:h
Step-by-step explanation:
Answers
2x7=14
7^2+1=50
=(48,14,50)
2)10^2-6^2=64
2x10x6=120
10^2+6^2=136
=(64,120,136)
Answers
The length of a wrestling mat with an area of 1444 square feet could be approximately 38 feet, if assuming the mat to be a square. However, without more specific information, the exact dimensions could vary while maintaining the same area.
Without additional information, we can't determine the exact length of the wrestling mat. However, if we assume the mat is a perfect square, where the length and width are equal, then we can find the side length by taking the square root of the area.
To find the square root, you can use a calculator and input 1444. You'll find that the square root of 1444 is approximately 38 feet. This would be the length of each side if the wrestling mat is a square.
Keep in mind that this is an approximation. The actual wrestling mat could have different dimensions but still have an area of 1444 square feet. For instance, it could be rectangular rather than square.
Learn more about Square root here:
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(I used a calcultor)
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This is an example of the Associative Property of addition.
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answer- 39
b. For a large family, is it possible that member would join for free? If so, which member would it be? Explain your reasoning.
c. Other than $0, what is the lowest amount that a member would pay to join? Which member would it be? Explain your reasoning.
Answers
a. If we subtract 75 from 550 twice, we get 400, which is the third member to join. Subtract 75 from 400, we get $325, the fourth member to join.
b. It is not possible that a member would join for free if it was a large family. 75 does not fit into 550 evenly. You can prove this by solving the expression 550÷75.
c. The lowest amount that a member would pay to join is $25.00. It would be the 7th member.