Solve the formula for b2. A=1/2h(b1+b2)

Answers

Answer 1
Answer:

The value of  b₂ after simplification is  b₂ =  (2A)/(h) - b_(1).

The given expression is   A = (1)/(2) h (b_(1) + b_(2) ).

To find the value of b₂  which is on the right hand side of the equation.

Reorder all the terms other than b₂ on left hand side.

The steps are as follows,

A = (1)/(2)hb_(1)  + (1)/(2)hb_(2)

Add right  hand side terms using common denominator  as 2.

A = (hb_(1) + hb_(2))/(2)

Multiply 2 on both  side of the expression and take h common from RHS.

2A = h(b_(1) + b_(2) )

Divide by h on both side of the equation,

(2A)/(h) = b_(1) + b_(2)

Solve for b₂.

b_(2) = (2A)/(h) - b_(1)

The correct solution for    b_(2) = (2A)/(h) - b_(1)

Learn more about simplification here:

https://brainly.in/question/25508298

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Answer 2
Answer:

Firstly, multiply both sides by 2: 2A=h(b_1+b_2)

Next, divide both sides by h: (2A)/(h)=b_1+b_2

Next, subtract both sides by b1, and your answer will be (2A)/(h)-b_1=b_2


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Answers

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Please help!! -5 = 7 + 3r

Answers

Hi!

-5 = 7+3r

-5-3r = 7+3r-3r

-5-3r = 7

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-3r = 12

-3r    12
▬ =  ▬
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r= -4
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