How do you make a 10 to find 13-8

Answers

Answer 1
Answer:

You can "make 10" out of either the positive number or the negative one.

13 - 8

= (10 +3) -8 = 10 +(3 -8) = 10 -5 = 5

= 13 -(10 -2) = (13 -10) +2 = 3 +2 = 5

_____

The latter approach would be used for computation using a soroban or abacus.


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How is the formula for the perimeter of a rectangle an application of the distributive property

Answers

The formula for the perimeter of a rectangle is 2l+2w=p, where l the length, w is the width, and p is the perimeter. It is an application of the distributive property because it can be rewitten as 2(l+w)=p, which says that the length times width added together and multiplied by 2 equals the perimeter.

I dont know this will someone help me お願いします AKA Please

Answers

Answer:

i think the answer is A but im not sure so if your grade depends on it i would wait for someone else to answer

( i am not very good with graphing)

the answer is A the person said it worked

lol i had guessed

Step-by-step explanation:

I’m looking forward to working with you

Is 3/8 equivalent to 2/6

Answers

no 3/8 is not equivalent to 2/6
No since if you cross multiply you get 6 and 48.

The height of a tree, y, is related to the length of its shadow, x, by the equation y = kx. If a tree's height is 24 feet and its shadow is 9 feet long, then k =

Answers

What you do is divide x to the other side, 24/9 = k. Then you solve. K = 2.6 repeating, or 8/3.

Answer:

(8)/(3)

Step-by-step explanation:

plug in 24 for y and 9 for x, to get 24 = 9k, so k = 24/9=8/3

hope this helped:)

Simplify please help

Answers

idk what the ! are for but i would thing the answer is 2...
Is there a one by 6 and 3. If not, the answer is 2.

What is 250.6 rounded to the nearest hundredth?

Answers

250.6 is your number

The "6" in .6 right after the decimal is the tenths place

So right after the tenths place is the hundredths place

But as you can see in 250.6, there is no hundredths place you can see so it is 0

250.60 is the same as 250.6

So 250.6 is already rounded to the nearest hundredths