Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2 9 9 8 3 Average rate of change of g for x on the interval [3 , 7 ] = 9 Incorrect Average rate of change of f for x on the interval [3 , 7 ] = Incorrect f ( g ( 4 ) ) = Incorrect g ( f ( 3 ) ) = Incorrect

Answers

Answer 1

Answer:

$\n(i)\n\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\n\nf_(avg)=(f(b)-f(a))/(b-a)\n\n\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\n\ng_(avg)=(g(7)-g(3))/(7-3)\n\n=(4-1)/(4)\n\n=(3)/(4)\n\n\text{so average rate of change of g on interval [3,7] is }(3)/(4)$

$\n(ii)\n \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\n\nf_(avg)=(f(7)-f(3))/(7-3)\n\n=(0-5)/(4)\n\n=(-5)/(4)\n\n\text{so average rate of change of g on interval [3,7] is }(-5)/(4)$

$\n(iii)\n\text{Since g(4)=5, so we have}\n\nf(g(4))=f(5)\n\n\text{since the value of f is 1 at x=5. so }\n\nf(g(4))=f(5)=1\n\n\text{hence we have, }f(g(4))=$ 1

$\n(iv)\n\text{Since f(3)=5, so we have}\n\ng(f(3))=g(5)\n\n\text{since the value of g is 2 at x=5. so }\n\ng(f(3))=g(5)=2\n\n\text{hence we have, }g(f(3))=$ 2

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Solve for x 8/9x= 32

Answers

The solution to the given equation is 36.

The given equation is 8/9 x=32.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Here, 8x=32×9

x=(32×9)/8

x=4×9

x=36

Therefore, the solution to the given equation is 36.

To learn more about an equation visit:

brainly.com/question/14686792.

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8/9x*9=32*9 8/x = 288 8/8x = 288/8 1/x = 35 X=1/35 is the answer

What is the 4th tearm to this?
b(n)=4−6(n−1)

Answers

Answer:

If you wish to find any term (also known as the {n^{th}}n

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Step-by-step explanation:

Where in real life do people use parabolas?
*apart from maths classrooms and mathematicians.

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The mirrors of reflecting telescopes are parabolas.
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Miller School has 2 boys for every 3 girls in the fifth grade. There are 120 students in the fifth grade. How many girls are there? How many boys are there?

Answers

$b-boys\ng-girls\n\n(b)/(g)=(2)/(3)\to b=(2)/(3)g\n\nb+g=120\to(2)/(3)g+g=120\n\n(2)/(3)g+(3)/(3)g=120\n\n(5)/(3)g=120\ \ \ \ \ /\cdot(3)/(5)\n\ng=72\n\nb=(2)/(3)\cdot72=2\cdot24=48\n\nAnswer:48\ boys\ and\ 72\ girls.$

When constructing parallel lines with a compass and straightedge, how should you start the construction?

Answers

that would build a line parallel to and passing through a given point outside the line. Building a straight line passing through the given point perpendicular to the given line. Then build a straight line passing through the given point perpendicular constructed perpendicular. Obtained in this direct and will be required.

Answer:

You should start the construction by creating a line that intersects the given line with your straightedge.

Step-by-step explanation:

You should start the construction by creating a line that intersects the given line with your straightedge.

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Answers

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Answer:

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Step-by-step explanation:

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