MATHEMATICS MIDDLE SCHOOL

DVD cases are sold in packages of 20. Padded mailing envelopes are sold in packets of 12. What is the least number of cases and envelopes you could buy so that there is one case for each envelope with none left over?

Answers

Answer 1
Answer:

Answer: 3 packages of DVD cases and 5 packets of padded mailing envelopes.

Step-by-step explanation:

Hi, to answer this question we have to find the Least Common Multiple (LCM) of 20 (DVD cases) and 12 (envelopes).  

20: 20,40,60,80  

12: 24,36,48,60  

Since DVD cases are sold in packages of 20: to find the number of packages we have to divide the number of DVD cases that we could buy (60) by the number of DVD cases that each package contains (20).

60/20 = 3 packages of DVD cases  

And for the envelopes (12)  

60/12 =5 packets of Padded mailing envelopes  
Answer 2
Answer: You need 3 packages of DVD cases and 5 packets of mailing envelopes.

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How would I do this? Please explain instead of just giving me the answer.

Answers

According to the Pythagorean theorem, the square of the hypotenuse (the longest side) of a right-angled triangle equals to the sum of the squares of the other two sides. In this case, the ladder is the hypotenuse, which equals to the distance between the bottom of the ladder and the tree + the distance we want to find (x):
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the area of a square floor on a scale drawing is 100 square centimeters and the scale of the drawing is cm : 2 ft what is the area of the actual floor what is the ratio of the area in the drawing to the actual area

Answers

The actual floor is 200 square feet and the ratio is 100 square centimeters: 200 square feet
the ratio would be 50:1 because you would have to simplify the ratio 100:2

*********PLEASE I NEED HELP ********
IN 1,2,3

Answers

Not sure if this is your teacher’s preferred format, but I hope this helps.

Rashida bought 3 tickets to a concert for $75.A this rate how much would 5 tickets cost

Answers

Answer: The cost of 5 tickets =  $125

Step-by-step explanation:

We are given that , the cost of 3 tickets = $ 75

Then , By Unitary ,method

The cost of one ticket= (cost of 3 tickets) ÷ (3)

= ($75) ÷ (3)

= $25

Now , if the rate is same , the cost of 5 such tickets will be

5 x (Cost of one ticket)

= 5 x ($25)

= $125

Hence , the cost of 5 tickets =  $125
First divide 75 by 3 to figure out what the cost of 1 ticket is.
75÷3 = 25
so, 1 ticket costs $25
now multiply 25 by 5
25*5= 125
so 5 tickets would cost $125

It's in the picture ?

Answers

Answer:

4

Step-by-step explanation:

From first piece -6 < x ≤ 0.

From second piece 0 < x ≤ 4.

Therefore -6 < x ≤ 4 → x ∈ (-6, 4]

-7 ∉ (-6, 4]

-6 ∉ (-6, 4]

4 ∈ (-6, 4]

5 ∉ (-6, 4]

A plumber charges $110 per hour. If h represents the number of hours that he works, what domain values are relevant on a graph that shows his earnings?

Answers

Given that a plumber charges $110 per hour. Where h represents the number of hours worked by plumber.

Then profit equatio for the plumber is given by P=110h

where P gives total earning of the plumber in h hours.

Now we need to find about what domain values are relevant on a graph that shows his earnings. Graph is not given but that is not the problem.

We know that number of hours can never be negative. It can be 0 or more.

Hence domain for the graph will be "all positive real numbers" which can also be written as:

h≥0.

Maximum hours is not given neither it is specified to use data for how many days so we will not put any upper bound for h.

Answer:

h ≥ 0

Step-by-step explanation:

The equation of his earnings is $110h. He can't work negative hours.
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