The expression (2x2)3 is equivalent to _____.

6x2

6x5

8x6

Answers

Answer 1

Answer: 6x2, because using pemdas, 2x2= 4 then 4x3=12. The answer must equal 12, and 6x2 does.

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Multiply and simplify.

2/3 * 2 1/5 * 3/4=?

Answers

2/3 (2 1/5) (3/4)
=2/3 (11/5) (3/4)
= 2/3 (33/20)
= 11/10
= 1 1/10

2/3*11/5*3/4= 66/60 (divide by 6)= 11/10 or 1 1/10

What is the value of x

Answers

×=8 you're so welcome. :)

A^2+B^2=x^2

6^2+10^2=2x

36+100=2x

136/2=2x/2

68=x

The school is able to buy dozen roses for $9.36.The roses will be sold with a 150% markup. For what price the school sell 1 dozen roses

Answers

$ $9.36$ it is normall price which mean its 100%

$150$ % $*$ $ $9.36$ it price with mark up

And we know that $150$ % $=1.5$

so:

$9.36*1.5=14.04$

Answer:
This school will sell 1 dozen roses for $ $14.04$

Answer:

23.40

Step-by-step explanation:

150/100=1.5

9.36*1.5=14.04

9.36+14.04=23.40 per dozen of roses

suppose 60% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. what's the probability that a kid who goes to the doctor has a fever and a sore throat? rounded to three decimal places as needed.

Answers

Answer:

0.12

Step-by-step explanation:

Suppose there are 100 kids

60% have fever, so what is 60% of 100?

We convert percentage to decimal and multiply:

60/100 = 0.6

0.6 * 100 = 60 have fever

20% of the people having fever (60 of them) have sore throats, so,

What is 20% of 60?

We convert percentage to decimal and multiply:

20/100 = 0.2

0.2 * 60 = 12 have sore throat

So, how many people are there with fever AND sore throat, that is 12. We took initially there to be 100 people. Hence, the probability is:

$(12)/(100)=0.12$

Can some explain me how to find the answers

Answers

(a) r = the weight of Rajesh's package and m = the weight of Mohib's package:

r = 2m + 3
r + m = 15

(b) The easiest way to solve this equation would be to use substitution. The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:

$r+m=15\(2m+3)+m=15\3m+3=15\3m=12\m=4$

Now that we have m, we can plug it into one of the equations to find r:

$r=2m+3\r=2(4)+3\r=8+3\r=11$

So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds. This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.

(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis). The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.

what textbook and pg # is this? I wanna be able to practice

(PLEASE ANSWER AND CHECK YOUR WORK ALSO :) Apply the distributive property and the greatest common factor to write an equivalent expression. 60 x−24=

DOOOOO YOUR BEST!