How many straight lines are needed to divide a regular hexagon into 6 identical triangles

Answers

Answer 1

Answer: you would need 6 straight lines, doing a drawing is essential for this excersise

Related Questions

Escreva no caderno dois exemplos de números reais que obedecem a cada uma das condições A) números irracionais maiores que 2,5 e menores que 3.B) números racionais maiores que -7/8 e menores que -3/4
PLEASE HELP!! EARN 50 POINTS!! WILL MARK BRAINLIEST!!!!Fill in the reason for each stepGiven - 2x-7= 1/3x-2Prove - x = 3statement - 2x-7= 1/3x-2 reason- (Given)statement - 3(2x-7)=3(1/3x-2) Reason -statement - 6x-21=x-6reason -statement - 5x-21=-6reason -statement - 5x=15reason -statement - X=3reason -
If the volume for 3-D polyhedra A is 300 cm3 and the volume for 3-D polyhedral B is 900 cm3. How many times bigger is the volume of pyramid B than pyramid A? Select one: a. 3% b. 30% c. 300% d. 3000%
\dfrac{1}{3}(4\cdot3)+2^3= 31 (4⋅3)+2 3
Can you explain to me in steps how to work this problem4(2x-2)-4=4(x-5)+32

the balance in joans savings account tripled during the year. Joan then withdrew $500, and the resulting balance was $100. what was the balance in the account before ir tripled

Answers

$200 because 200x3 is 600 -500 is 100 aka the remaining balance

Solve each of the following equations for x.a) 3x - 8 =29 b) 3 ( x - 8 ) = 28

c) 3 (x - 8) + 17 =29 d) 7x + 12 = 3x - 8

Answers

$3x - 8 =29 \n \n 3x = 29 + 8 \ / \ add \ 8 \ to \ each \ side \n \n 3x = 37 \ / \ simplify \n \n x = (37)/(3) \ / \ divide \ each \ side \ by \ 3 \n \n Answer: \fbox {x = 37/3} \ or \ \fbox {x = 12.3333}$

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$3 ( x - 8 ) = 28 \n \n x - 8 = (28)/(3) \ / \ divide\ each \ side \ by \ 3 \n \n x = (28)/(3) + 8 \ / \ add \ 8 \ to \ each \ side \n \n x = (52)/(3) \ / \ simplify \n \n Answer: \fbox {x = 52/3} \ or \ \fbox {x = 17.3333}$

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$3 (x - 8) + 17 =29 \n \n 3(x - 8) = 29 - 17 \ / \ subtract \ 17\ from \ each \ side \n \n 3(x - 8) = 12\ / \ simplify \n \n x - 8 = (12)/(3) \ / \ divide \ each \ side \ by \ 3 \n \n x - 8 = 4 \ / \ simplify \n \n x = 4 + 8 \ / \ add \ 8 \ to \ each \ side \n \n x = 12 \ / \ simplify \n \n Answer: \fbox {x = 12}$

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$7x + 12 = 3x - 8 \n \n 7x + 12 - 3x = -8 \ / \ subtract \ 3x \ from \ each \ side \n \n 4x + 12 = -8 \ / \ simplify \n \n 4x = -8 - 12 \ / \ subtract \ 12 \ from \ each \ side \n \n 4x = -20 \ / \ simplify \n \n x = - (20)/(4) \ / \ divide \ each \ side \ by \ 4 \n \n x = -5 \ / \ simplify \n \n Answer: \fbox {x = -5}$

The Kahn's Family lives in a house that has a backyard in the shape of an isosceles trapezoid and a triangle. The area of the backyard can be expressed as the sum of the area of the triangle and the area of the trapezoid, which is 1/2bh+1/2(p+q)L The base and the height of the triangle are represented by b and h, respectively. The bases of the trapezoid are p and q, and the height of the trapezoid is L. 2 Rearrange the formula to find the length of base as a function of the lengths of the other sections of the backyard.

Answers

This is solved the way any 2-step linear equation is solved:

subtract the term not containing the variable of interest, then
divide by the coefficient of that variable.

... A = (1/2)bh + (1/2)(p+q)L

... A - (1/2)(p+q)L = (1/2)bh . . . . . subtract the term on the right

... (A -(1/2)(p+q)L)/(1/2·h) = b . . . .divide by (1/2)h, the coefficient of b

... b = (2A -(p+q)L)/h . . . . . . . . . . simplify

70 oz of dried cranberries costs $5.60 what is the cost per ounce

Answers

The cost per ounce is 12.5.

Given that,

70 oz of dried cranberries cost $5.60

We have to determine,

What is the cost per ounce?

According to the question,

To determine the cost per ounce calculation must be done in a single unit, following all the steps given below.

The cost per ounce is,

70 oz of dried cranberries cost $5.60,

$= (70)/(5.60)\n\n=12.5$

Hence, The cost per ounce is 12.5.

To know more about Fractions click the link given below.

brainly.com/question/14210034

Divide 5.60 by 70 and that's the price per ounce

The hardcover version of a book weighs twice as much as its paperback version. The hardcover book and the paperback together weigh 4.2 pounds. Which system of equations can be used to find h, the weight of the hardcover book, and p, the weight of the paperback?

Answers

If the weight of hardcover version is double the weight of paperback version then weight of hardcover version is 2.8 pounds and the weight of paperback version is 1.4 pounds.

What is equation?

An equation is a relationship between variables in equal to form. It is evaluated to find the values of variables.

How to solve an equation?

The weight of hardcover book is h

The weight of paperback version is p.

According to question:

h=2p (weight of hardcover version is double the weight of paperback version)

h+ p= 4.2 (weight of hardcover version and weight of paperback version is equal to 4.2 pounds)

Put the value of h=2p in h+ p=4.2

2p+p=4.2

3p=4.2

p=1.4

Put the value of p=1.4 in h=2p to get the value of h

h=2p

=2*1.4

=2.8

Hence the weight of hardcover version is 2.8 pounds and the weight of paperback version is 1.4 pounds.

Learn more about equations at brainly.com/question/2972832

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Answer:

Step-by-step explanation:

on edge 2023

The equation of a circle is given below. (x+4)^{2}+(y-6)^{2} = 48(x+4) 2 +(y−6) 2 =48left parenthesis, x, plus, 4, right parenthesis, squared, plus, left parenthesis, y, minus, 6, right parenthesis, squared, equals, 48 What is its center? What is its radius?

Answers

center= (-4,6) radius= 6.93

Step-by-step explanation:

Answer:

(-4,6) 6.93

Step-by-step explanation:

proof

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