6w^3 - 13 the GCF ? or is this a prime?

Answers

Answer 1

Answer: It is a prime because the only other factor of 6w^3-13 is 1.

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Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent stamps as both of the other two kinds combined. How many of each kind did she get if she paid a total of $4.40 for them all? Due today! IM SO CONFUSED

Answers

Write it out as a set of equation:
Let x be number of 8 cent stamps, y be 10 cent stamps, and z be 2 cent stamps.
x=y
z=x+y
8x+10y+2z=440
Lets first solve for x:
from x=y and z=2x(from first equation) the last equation is
8x+10x+4x=440
22x=440
x=20
know that x=20, you also know that y=20 as well, since z=x+y, z=40.
So 20 8-cent stamps, 20 10-cent stamps, and 40 2-cent stamps.

x=number of 8-cent stamp=number of 10-cent stamp
y=number of 2-cent stamp.
$4.40=400 cents

She bought the same number of 8.cent stamp and 10 -cent stamps, she also bought as many 2-cent stamps as both, therefore:
x+x=y ⇒2x=y
We can suggest this system of equations:

2x=y
8x+10x+2y=440

We can solve this system of equation by substitution method.

8x+10x+2(2x)=440
8x+10x+4x=440
22x=440
x=440/22
x=20

y=2x
y=2(20)=40

Answer: She bought 20 stamps of 8 cents, 20 stamps of 10 cents, and 40 stamps of 2 cents

Does anyone know how to Graph f(x)=51(2)^x

Answers

This is an exponential function.

If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.

Make a table and graph the points:

x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.

The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.

f(x) = 102^x

Start with x=0.
f(0) = 102^(0) which is 1. Your y intercept (the line in the middle) is 0.

Your first point is (0,1).
For the second point, try x=1.

f(1) = 102^1 which is 102.
You second point is (1,102). Rinse and repeat. ;)

Find sin(α+β) if cosα=35 , sinβ=−45 , α is in quadrant I and β is in quadrant III

Answers

Sin is about 4,.002 ........

Evaluate 2b^2 − 4a + 4a^2 for a = 3 and b = −8.

Answers

(2*(-8)^2)-(4*3)+(4*3^2)

128-12+36

152

A circle with radius of 1 cm sits inside a 11 cm x 12 cm rectangle.What is the area of the shaded region?
Round your final answer to the nearest hundredth.

Answers

Answer:

128.86 square centimetres

Step-by-step explanation:

I will assume that the shaded region is the area in between the circle and the rectangle.

All we have to do is find the area of the circle and subtract it from the area of the rectangle.

Area of a circle is given as:

$A = \pi r^2$

where r = radius

The radius of the circle is 1 cm, so, the area of the circle is therefore:

$A = \pi * 1^2$ = 3.14 square centimetres

The area of a rectangle is given as:

A = L * B

The dimensions of the rectangle are 11 cm by 12 cm. The area of the rectangle is:

A = 11 * 12 = 132 square centimetres

The area of the shaded part is therefore:

A = 132 - 3.14 = 128.86 square centimetres

Let s = 13. What is the value of 3s?

A.
10

B.
16

C.
39

D.
313

Answers

it's c, because
s=13
3s=3*13↪39

Answer:

$\left[\begin{array}{ccc}2&90&10\n4&3&6\n1\left \{ {{y=32\int\limits^8_4 {x} \, dx } \atop {x=50}} \right. &8&6\end{array}\right] \n\n\n\n\n x_(123) (x)/(y) \n\n=(C.39)$

hope i helped

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