When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.

Answers

Answer 1
Answer: Yes yes ! How right you are ! Truer words were never spoken.
Answer 2
Answer:

Answer:

There you go

Explanation:

When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.


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The motion graph shown below was created by a toy train which starts out moving north. The train starts from a position of 2.0m north.

Answers

Answer:

The motion graph provided represents the displacement of a toy train over time. The graph consists of two distinct segments: an initial period of constant velocity followed by a period of rest.

From the given information, we can determine that the train starts from a position of 2.0m north. This means that at t=0 (the beginning of the graph), the train is located 2.0m north of its starting point.

The first segment of the graph shows a straight line with a positive slope, indicating constant velocity. Since the train is moving north, the positive slope suggests that it is moving in the positive direction along the y-axis. The steeper the slope, the greater the velocity.

The second segment of the graph shows a horizontal line, indicating that the train is at rest. During this period, the train does not undergo any displacement and remains stationary.

To determine the total displacement of the train, we need to calculate the area under the graph. In this case, we have two separate areas to consider: one for each segment.

For the first segment, which represents motion, we can calculate the area by finding the area of a triangle. The formula for calculating the area of a triangle is A = 1/2 * base * height. In this case, the base corresponds to the time interval and the height corresponds to the displacement.

Let's assume that each unit on both axes represents 1 second and 1 meter, respectively. From the graph, we can estimate that the time interval for the first segment is approximately 4 seconds and that the displacement is approximately 8 meters (from t=0 to t=4). Therefore, using our formula, we can calculate:

A = 1/2 * 4s * 8m = 16m²

So, during this period of motion, the train has a displacement of 16 meters.

For the second segment, which represents rest, the train does not undergo any displacement. Therefore, the area under the graph is zero.

To calculate the total displacement of the train, we sum up the areas from both segments:

Total displacement = 16m² + 0m² = 16m²

Hence, the total displacement of the toy train is 16 meters.

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A 1.0 µC test charge travels along an equipotential line a distance of 0.20 cm between two parallel charged plates with a field strength of 500.0 N/C. What is the change in voltage? (µC = 1.0 × 10^-6 C)

Answers


This question is written by a master of deception and distraction.
It's full of so many red herrings that it's tough to walk past it too closely.

In order to answer this question correctly, you don't need to know
the magnitude of the test charge, the distance it travels, or the field
strength between the plates.  The whole question lies in that magic
word "equipotential".

An 'equipotential' line is a path along which the electrical potential
is the same at every point.  It's analogous to a 'contour line' on a
topographic map, or an isobar on a weather map.

A charge moving along such a line uses no energy to travel that path,
and it encounters no change in voltage anywhere in its travels.

At which point on this electric field will a test charge show the maximum strength?A
B
C
D

Answers

Answer:

A

Explanation:

The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:

E\propto (1)/(r^2)

More precisely, the strength of the field at a distance r from the centre of the sphere is

E=k(Q)/(r^2)

where k is the Coulomb's constant and Q is the charge on the sphere.

From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.

This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.

The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Answers

Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

g_(1)= GM/r²                   (i)

g_(1) = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

g_(2)= GM/(2r)²

g_(2)= GM/4r²

g_(2)=  GM/r² *1/4

from (i)

g_(2)=  g_(1) *1/4

g_(2) = 15/4

g_(2) = 3.75m/s²

Which statements describe the principles of the big bang theory? Select two options. The universe is continuing to expand. The universe stretched from a single point. The universe resulted from the collision of light and dark energy. The universe expanded, but its size is now remaining constant. The universe is slowly collapsing and getting smaller.

Answers

The statements which describe the principles of the big bang theory include:

  • The universe is continuing to expand
  • The universe stretched from a single point.

Big bang theory was postulated by Georges Lemaître and he is regarded as

the father of this principle. This principle talks about how the universe was

formed.

He proposed that the universe was formed from a single point which then

began expanding and stretching to accommodate more components.

Read more on brainly.com/question/6841128

Answer:

A and B

Explanation:

edge 2023

Johannes Kepler is best known for his work on planetary motion.
a. True
b. False

Answers

Answer: True.

Kepler was an astronomer, astrologer and mathematician. He was an apprentice of Tycho Brahe, other big (maybe the biggest) astronomer of their time.

Kepler is best known for his 3 laws of planetary motion.

1) the orbit of a planet is an ellipse with the Sun at one of the two foci

2) A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time

3) The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

Truer words are seldom if ever written.