how far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10m/s ?
Answers
Answer:
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
Explanation:
We have equation of motion, , where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
In this case we have final velocity = 10 m/s, initial velocity = 0 m/s, and acceleration = 9.8 .
Substituting
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
Final answer:
When an object, starting from rest, achieves an instantaneous speed of 10 m/s while freely falling under gravity, it will have fallen approximately 5.10 meters.
Explanation:
Using the physics concept of motion under gravity, where the first equation of motion can apply (v = u + gt), your question involves finding the displacement of a freely falling object starting from rest until it reaches a speed of 10 m/s.
In this case, initial velocity (u) is zero because the object was at rest, the final velocity (v) is 10 m/s, and g is the acceleration due to gravity which is approximately 9.81 m/s².
We could rearrange the equation to find time: t = v/g = 10 / 9.81 ≈ 1.02 s. Then, we employ the second equation of motion to find the distance fallen, s = ut + 0.5gt². Since u=0, the formula simplifies to s = 0.5gt². Substituting g = 9.81 m/s² and t = 1.02 s into the equation yields s = 0.5 * 9.81 * (1.02)² ≈ 5.10 m.
Therefore, a freely falling object will have fallen approximately 5.10 meters when its instantaneous speed is 10 m/s.
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