wyatt can husk at least 12 dozen ears of corn per hour and at most 18 dozen ears of corn per hour. Based on this information. what is a possible amount of time, in hours, that it could take wyatt to husk 72 dozen ears of corn?

Answers

Answer 1

Answer: If Wyatt can husk at least 12 an hour, then to work out how much 72 takes, we do 72 ÷ 12 to find out the time. The answer is 6.

If Wyatt can husk 18 at most, then we do 72 ÷ 18 = 4 hours.

Wyatt can husk 72 dozen ears in anywhere between 4 and 6 hours, but if you were to average it, you would get 5 hours. ((4 + 6) ÷ 2 = 5).

Answer 2

Answer: so a possible amount of time
find the range of highest and lowest
equation is
(number of corns per hour) times (number of hours)=72
so
12 times x=72 would be longest and
18 times y=72 would be shortest

solve
12 times x=72
divid 12
x=6
6 hours at most

18 times x=72
divide 18
x=4

at most 6 hours an at least 4 hours so
6>hours>4
any number of hours from 4 to 6 including 4 and 6

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A music festival offers one-day and three-day passes. A one day pass costs $100 and a three-day pass costs $250. write an expression for the total ticket sales if (n) one day passes and (t) three day passes are sold.

Answers

The expression for the total ticket sales if (n) one day passes and (t) three day passes are sold is n + t = $350.

What is an expression?

An expression is a number, or a variable, or a combination of numbers and variables and operation symbols.

Now it is given that,

Cost of one-day passes, n = $100

Cost of three-day passes, t = $250

So, Total ticketssold = Cost of one-day passes + Cost of three-day passes

⇒ Total ticketssold = n + t

⇒ n + t = $100 + $250

⇒ n + t = $350

which is the required expression for total tickets sold.

Thus, the expression for the total ticket sales if (n) one day passes and (t) three day passes are sold is n + t = $350.

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Answer:

100n+250t

Step-by-step explanation:

cost of the1 one day pass=100

cost of n one day passes=100n

cost of the 1 three day pass=250

cost of t three day passes=250t

Total sale= 100n+250t

A bucking bull eats 0.025 times his body weight per day. Hotfoot eats 45 pounds of food a day. Hotfoots weight is?

Answers

Step-by-step explanation:

Because to find the food it’s the weight x 0.025 = food all you would have to do is take the food and divide it by 0.025

45/0.025=1800 pounds

Solve the problem.If a lawn sprinkler sprays 15 feet in every direction, what is the area of the yard that gets watered?

Answers

The area of yard gets watered is 707.142 ft²

What is area?

The portion between any closed figure, and the extent of region of any plane is area.

Given that sprinkler sprays 15 feet in every direction

so it will form a circle with radius of 15ft

and area of circle is πr²

where r is radius of circle

value of π is 22/7

area = π x (15)²

area = 707.142 ft²

Hence area of sprinkled region is 707.142 ft²

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Hello,

A=πR²=3.141592...*15²=706,8583470...( ft²)
===================================

Please explain how to do this and one answer.

Answers

Answer:

In counting to a base, when we get to the point where the base integer comes up, we replace by 10, on the first time and by 10 at every other time the integer is about to come up

We now this in base 10 as when we get to 10 we input 10 and so and so till we get to 99 where since we are in base 10 the next number is 100 because that is the highest we can go while in base 11 100 in base is equivalent to 91

So we have for base 5

1, 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 100, 101, 102, 103, 104, 110, 111, 112, 113, 114, 120, 121, 122, 123, 124, 130, 131, 132, 133, 134, 140, 141, 142, 143, 144, 200

We see that on getting to 4 instead of the next digit to be 5 we replace it with 10 because 5 cannot be displayed in base 5

Similarly after 14 is 20 because 5 cannot be displayed at 24 the next number is 30 because 5 cannot be displayed

at 34 the next 40, while at 44 the next is (we could have written 50 but 5 is 10 in base 5 so we write 100) 100

At 144, we note that 44 = 100 + 44, therefore, the next number will be 100 + 44+ 1 = 100 + (45 but 45 = 100 in base 5) 100 so that the next number is 200

Base 2

In base 2 we have;

1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 10000, 10001, 10010, 10011, 10100, 10101, 10110, 10111, 11000, 11001, 11010, 11011, 11100, 11101, 11110, 11111, 100000, 100001, 100010, 100011, 100100, 100101, 100110, 100111, 101000, 101001, 101010, 101011, 101100, 101101, 101110, 101111, 110000, 110001, 110010

We see that there are no 2s and after 11 we get 100 just like after 99 we get 100 in base 10 and after 44 we get 100 in base 5

So we need to still have an idea of the number system just as we did for base 10

Step-by-step explanation:

Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 6

Answers

The given function is

f(x)= log 10 x

Taking base as 10

$y=\log_(10)10 +\log_(10)x$ →→Using the property of, log a b= log a + log b

→y = 1 + $\log_(10)x$ as, $\log_(10)10=1$

we have to approximate the value of y in the equation

→10 y = 6

→y= $(6)/(10)$

$(6)/(10)$ = 1 + $\log_(10)x$

$\log_(10)x$ = $(-4)/(10)$

x= $(10)^{(-4)/(10)}$ = $(10)^(-0.4)$ =0.398

Solving graphically,

we get , x= 0.398 for , y= $(6)/(10)$ =.6

f(x) = ㏒(10x)
f(x) = ㏒₁₀(10x)

10y = 6
10 10
y = 0.6

f(x) = ㏒₁₀(10x)
0.6 = ㏒₁₀(10x)
$10^(0.6) = 10x$
$10^{(3)/(5)} = 10x$
$\sqrt[5]{10^(3)} = 10x$
$\sqrt[5]{1000} = 10x$
$\frac{\sqrt[5]{1000}}{10} = x$
$(3.98)/(10) \approx x$
$0.398 \approx x$

What s the equation of a line that passes through points (-1,3) and (0,1) what is the equation of the line that passes through the points (-1,3) and (o,1)
what is the equation of the line that passes through the points (-1,3) and (0,1)?