A zoo has 2 male lions one sixth oh the lions are male lions how many lions are there at the zoo ?

Answers

Answer 1
Answer:

There are 12 lions in the zoo.

What is a fraction?

A fraction is written in the form of a numerator and a denominator where the denominator is greater that the numerator.

We have two types of fractions.

Proper fraction and improper fraction.

A proper fraction is a fraction whose numerator is less than the denominator.

An improper fraction is a fraction where the numerator is greater than the denominator.

Example:

1/2, 1/3 is a fraction.

3/6, 99/999 is a fraction.

1/4 is a fraction.

We have,

If one-sixth of the lions in the zoo are male lions, then we can set up the following equation:

2 = (1/6)x

where x represents the total number of lions in the zoo.

To solve for x, we can multiply both sides of the equation by 6:

12 = x

x = 12

Thus,

There are 12 lions in the zoo.

Learn more about fractions here:

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Answer 2
Answer: Let x be the number of animals in the zoo
Number of male lions in the zoo = 2
1/6(x) = 2
x/6 = 2
x = 12
There are 12 lions in the zoo in total.

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Which of the following expresses the ratio of 3 inches to 2 yards?(A) 3 : 12
(B) 3 : 72
(C) 3 : 9
(D) 3 : 24
(E) 3 : 2

Answers

1\ yard=36\ inches\n ratio:3\ inches:2\ yards\n 2\ yards=72\ inches\n \n ratio: 3:72[inches]\n The\ correct\ answer\ is\ B.

Answer:

E

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if inhes

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Answers

Answer:

5/6

Step-by-step explanation:

first form numerator you will multiply by π it means 3.14 multiply 11

the answer equals 34.54 ..and then you will use √ it means square root....so the answer is 5

the annwer is

5/6

Answer:

Step-by-step explanation:

(11\pi )/(6) =  11 × (\pi )/(6) = (12 - 1) × (\pi )/(6)

The terminal point located in IV quarter ⇒ x-coordinate is positive and y-coordinate is negative.

(x, y) = ( (√(3) )/(2) , - (1)/(2) )

Is 1/2(2p+9)=-p+5 a one solution or infinite solution or no solution​

Answers

Your inequality has one solution which is p = 1/4

What's A(-2,-4),B(2,4)

Answers

AB = \sqrt{( 2 + 2 ) ^(2) +  (4 + 4)^(2) } =  √(16 + 256) =  √(272) = 16.49

A pork roast was taken out of a hardwood smoker when its internal temperature had reached 180°F and it was allowed to rest in a 75°F house for 20 minutes after which its internal temperature had dropped to 170°F. Assuming that the temperature of the roast follows Newton’s Law of Cooling, a) Express the temperature of the roast, T as a function of time t.b) Find the amount of time that has passed when the roast would have dropped to 140°F had it not been carved and eaten. 

Answers

The roast was 82.2degrees Celsius when it was taken out of the hardwood smoker

It would of taken 80 mins for it to cool from 180 to 140
As every 20 mins it would decrease it's temperature by 10degrees C so it would be
80mins for it to reach 140 from 180

By Newton's law of cooling
T-S=Ce^(-kt)
S=75
at t=0
180-75=C=105
at t=20
170-75=105e^(-20k)=95 \n e^(-20k)= (95)/(105)
k=- (2.303)/(20) log_(10)( (95)/(105)=0.00500507463889254879012536550336
at T=140
140-75=65=105e^(-kt)
t= -(2.303)/(0.00500507463889254879012536550336)log_(10)( (65)/(105)==
t=96 minutes

Can someone help me in probability?Amanda wrote a computer program that generates two random numbers between one and eleven.When she runs it,what is the probability that both values will be more than three?

Answers

the probability is a fraction. all possible outcomes / number of items
so 8/11 is the probablity of finding a number higher than 3 out of 11
could also be written as:
8/11
8:11 
.73
73 percent