How to divide 11 by 110

Answers

Answer 1
Answer: We want to simplify this as much as possible. 11/110=1/10 since 110=11*10. Therefore, the answer is 0.1
Answer 2
Answer: 11/10 is 1.1. I hope it helped you


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Please help me ASAP!! Will give Brainliest!!

Answers

Answer:

A and B are correct AKA C

Step-by-step explanation:

The total of the two shorter lengths should be more than the longest

a)20+21>22

b)8+80>80

c)4+40<50

d)3+3=6

Therefore a and b are correct

First one is the answer

Whats the answer of -5/8 6/10 its greater than and less than or equal

Answers

Answer:

6/10 is greater

Step-by-step explanation:

It is  

Evaluate, 2 x {[5 x (60-14 divided by 7)] + 25} x 5=?

Answers

2 * \left \{ [5 * (60-(14 )/(7) )] + 25 \right \} * 5=2 * \left \{ [5 * (60-2)] + 25 \right \} * 5= 2 * \left \{ (5 * 58) + 25 \right \} * 5=\n\n= 2 * \left \{ 290 + 25 \right \} * 5=2*315*5=3150


The circumference of a circle of diameter 10 cm is _____.A
3.14 cm
B
0.314 cm
C
314 cm
D
31.4 cm

Answers

For a circle with a diameter of 10 cm, the circumference would be C = π(10) = 31.4 cm. The correct option is (D) 31.4 cm.


The circumference of a circle can be calculated using the formula           C = πd, where C represents the circumference and d represents the diameter of the circle.

We have the diameter of the circle is 10 cm, we can substitute this value into the formula:

C = π * 10 cm

Calculating the circumference using an approximate value of π as 3.14:

C ≈ 3.14 * 10 cm

C ≈ 31.4 cm

Therefore, the circumference of a circle with a diameter of 10 cm is approximately 31.4 cm.

The correct answer is D) 31.4 cm.

To know more about circumference refer here :

brainly.com/question/28757341#

#SPJ11

Can anyone do question 25 part c? :)

Answers

\begin{cases}x^3\qquad\qquad\ \ \  when\ x\geq3\n5\qquad\qquad\quad \ when\  0\ \textless \ x\ \textless \ 3\nx^2-x+2\quad\ when\ x\leq0 \end{cases}\n\n\n (a)\n f(0)\iff x=0\implies f(x)=x^2-x+2\n\nf(0)=0^2-0+2=2\n\n(b)\n \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\n\n f(2)=5\quad\wedge\quad f(1)=5\n\n f(2)-f(1)=5-5=0

(c)\n \big\forall \limits_( n\in R)\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_( n\in R)\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \  f(x)=x^2-x+2\n\nf(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2

A car rental charges $175 per week plus $0.10 per mile to rent a car. How many miles can you travel in one week for $195?(NEED ANSWER ASAP+ EXPLANATION)

Answers

Answer:

200 miles

Step-by-step explanation:

To solve this problem, we can set up an equation to represent the total cost of renting the car.

Total cost = Weekly fee + Mileage fee

The weekly fee is $175, and the mileage fee is $0.10 per mile.

Let distance be x.

We want to know how many miles we can travel in one week for $195, so we can set up the equation as follows:

195 = 175 + 0.10x

Subtracting 175 from both sides of the equation, we get:

195 - 175 = 175 + 0.10x - 175

20 = 0.10x

Dividing both sides of the equation by 0.10, we get:

\sf (20)/(0.10) = (0.10x)/(0.10)

x = 200

Therefore, we can travel 200 miles in one week for $195.