Which temperature change would cause the volume of a sample of an ideal gas to double when the pressure of the sample remains the same?

Answers

Answer 1
Answer:

Following the ideal gas law PV = nRT, and changing it in terms of temperature, we get T = PV/nR. When volume of a sample of an ideal gas to double when the pressure of the sample remains the same, the temperature doubles because temperature is directly proportional with pressure and volume.


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The material you should use in the windshield washer container is? usually a special windshield washing solution

Answers

The material you should use in the windshield washer container is a special windshield washing solution.

Using the wrong material in the windshield washer container can cause damage to the windshield and the washer system itself. A special windshield washing solution is specifically designed to clean the windshield effectively and safely, without leaving streaks or residue.

There are several types of special windshield washing solutions available in the market, each with its own set of benefits and features. Some of the most common types include:

1. Deionized water: This type of solution is distilled and purified to remove impurities and minerals that can leave streaks on the windshield. Deionized water is gentle on the windshield and the washer system, and it is effective in removing dirt and grime.

2. Isopropyl alcohol: This type of solution is a mixture of isopropyl alcohol and water. It is effective in removing dirt and grime, and it also helps to dry the windshield quickly. However, it can be too harsh on some types of windshields, so it is important to use it with caution.

3. Glycerin-based solution: This type of solution is made with glycerin, which is a natural humectant that helps to prevent the windshield from drying out. It is also effective in removing dirt and grime, and it leaves the windshield streak-free.

When choosing a special windshield washing solution, it is important to consider the type of windshield you have, as well as the climate and weather conditions in your area. For example, if you live in an area with high humidity, a glycerin-based solution may be the best choice, as it helps to prevent the windshield from fogging up.

It is also important to note that some special windshield washing solutions may not be compatible with certain types of windshields, such as those made of polycarbonate or acrylic. It is always a good idea to consult the manufacturer's instructions before using any solution in your windshield washer container.

In summary, the material you should use in the windshield washer container is a special windshield washing solution that is specifically designed for the type of windshield you have and the climate and weather conditions in your area. It is important to choose a solution that is gentle on the windshield and the washer system, and that is effective in removing dirt and grime.

At -18.6 °C, a common temperature for household freezers, what is the maximum mass of sucralose (C₁₂H₁₉Cl₃O₈) in grams you can add to 2.00 kg of pure water and still have the solution freeze? Assume that sucralose is a molecular solid and does not ionize when it dissolves in water.
K_f = 1.86 °C/m.

Answers

Answer : The maximum mass of sucralose is, 7952.8 grams.

Explanation :  Given,

Molal-freezing-point-depression constant (K_f) for water = 1.86^oC/m

Mass of water (solvent) = 2.00 kg

Molar mass of sucralose = 397.64 g/mole

Formula used :  

\Delta T_f=i* K_f* m\n\nT^o-T_s=i* K_f*\frac{\text{Mass of sucralose}}{\text{Molar mass of sucralose}* \text{Mass of water in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -18.6^oC

\Delta T^o = freezing point of water = 0^oC

i = Van't Hoff factor = 1 (for sucralose non-electrolyte)

K_f = freezing point constant for water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0-(-18.6)^oC)=1* (1.86^oC/m)* \frac{\text{Mass of sucralose}}{397.64g/mol* 2.00kg}

\text{Mass of sucralose}=7952.8g

Therefore, the maximum mass of sucralose is, 7952.8 grams.

The atomic mass of an element can be approximated by adding the number of _______ plus the average number of _______.A. protons; electrons

B. protons; neutrons

C. neutrons; electrons

Answers

Answer: Option (B) is the correct answer.

Explanation:

Atomic mass is defined as the summation of total number of protons and neutrons present in an element.

On the other hand, atomic number means the total number of protons present in an element.

For example, atomic number of sodium is 11 and number of neutrons present in it are 12.

Hence, atomic mass of sodium = no. of protons + no. of neutrons

                                                    = (11 + 12) amu

                                                    = 23 amu

Therefore, we can conclude that the atomic mass of an element can be approximated by adding the number of protons plus the average number of neutrons.

by adding number of protons and neutrons

In comparison with liquids and gases, solids area. more dense.
b. more easily compressed.
c. less organized.
d. more likely to flow.

Answers

In comparison with liquids and gases, solids are more dense. The answer is letter B. The solid has a more definite shape and volume. The particles are locked into place. It cannot be further compressed due to the bond that exists between the molecules. The kinetic energy of the molecules is close to none because the molecules are so close and so compact with each other. 

If 6.49 mol of ethane (C2H6) undergo combustion according to the unbalanced equationC2H6 + O2 −→ CO2 + H2O ,
how many moles of O2 is required?
1. 27.79
2. 7.63
3. 8.4
4. 25.48
5. 12.635
6. 21.035
7. 23.8
8. 19.04
9. 22.715
10. 26.775
Answer in units of mol.

Answers

Answer:

22.715 moles of oxygen are used

Explanation:

Given data:

Number of moles of ethane = 6.49 mol

Number of moles of O₂ required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂       →     4CO₂ + 6H₂O

Now we will compare the moles of oxygen with ethane.

                    C₂H₆           :           O₂  

                       2              :             7

                     6.49           :           7/2×6.49 = 22.715 mol

Thus, 22.715 moles of oxygen are used.

The only way to seperate a compound into its elements is by a

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