The first table was arranged by atomic mass, but later Mosely improved it by arranging by _______________.

Answers

Answer 1
Answer:

Order of increasing atomic mass!

hope this helps :)

Answer 2
Answer: The first table, created by Mendeleev, was arranged by increasing atomic mass. However, it was later changed by Mosley, who arranged it the way it is today. He organized it by atomic number.

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Can someone how to do these problems!!

A gas absorbs 3.4 kJ of heat and does 1.9 kJ of work. Calculate ΔE

Answers

Answer:

Answer is given below:

Explanation:

Given Data:

heat = 3.4kJ

work done is = 1.9 kJ

To Find:

ΔE=?

Formula:

ΔE = q + w

Solution:

ΔE = q + w

ΔE = 3.4 kJ + 1.9kJ

ΔE =  5.3 kJ

Ethene is the first member of the a. Alkane series
b. Alkyne series
c. Saturated hydrocarbons
d. Unsaturated hydrocarbons
e. Aromatic hydrocarbons

Answers

It will be:

b. Alkyne* series

* You have done a spelling mistake here. It will be "Alkene" not  "Alkyne".

The bacteria that causes a disease is called a(n)A. Pathogen
B. Pandemic
C. Epidemiology
D. Toxicology

Answers

The answer is A


The bacteria that cause disease are known as pathogens. The term pathogen is used to refer to all types of disease causing microorganisms. These include  bacteria, fungi, protozoa and fungi.

Bacteria. Microscopic organisms that come in many shapes and sizes. Some bacteria that cause disease in man are Salmonella typhi which causes typhoid and Streptococcus pyogens which causes sore throat.

Virus. A virus is a microscopic entity much smaller than even bacteria and can only exist inside a host such as a cell. It cannot live on its own. Some viruses that cause disease are HIV which causes AIDS and  Rhino virus which causes colds.

Fungi.  These are a group of unicellular or multicellular microscopic organisms that live by feeding on organic matter. A type of fungus that causes disease  is Trichophyton mentagrophyte which is responsible for athlete's foot.

Protozoa. A group of one celled organisms which live in water. Entamoeba histolytica is a protozoa, an amoeba which causes amoebic dysentery in man.

Which ion was formed by providing the second ionization energy to remove an electron? Ca2+ N3– Fe3+ S2–

Answers

Answer:

                    Ca²⁺

Explanation:

                           Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom in its gaseous state. While, second Ionization energy is defined as the amount of energy required to knock out the second electron from an ion containing +1 charge in gaseous state.

                            Among given options Ca²⁺ is the correct choice because the calcium has lost two electrons i.e. first electron was removed by providing first ionization energy i.e.

                                       Ca  +  1st IE    →    Ca¹⁺  +  1 e⁻

and second electron is was removed by providing second ionization energy i.e.

                                     Ca ¹⁺  +  2nd IE    →    Ca²⁺  +  1 e⁻

\boxed{{\text{C}}{{\text{a}}^{{\text{2 + }}}}} is formed by providing the second ionization energy to remove an electron.

Further Explanation:

The energy that is needed to remove the most loosely bound valenceelectrons from the isolated neutral gaseous atom is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as {\text{I}}{{\text{E}}_{\text{1}}}. Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy \left( {{\text{I}}{{\text{E}}_{\text{2}}}} \right) and so on.

The neutral atom corresponding to {\text{C}}{{\text{a}}^(2 + )} is calcium. If second ionization energy is supplied to calcium atom, it results in the removal of two electrons and thus{\text{C}}{{\text{a}}^(2 + )}  is formed. So {\text{C}}{{\text{a}}^(2 + )} can be formed by providing second ionization energy. to the neutral atom.

The neutral atom corresponding to {{\text{N}}^(3 - )} is nitrogen. If second ionization energy is supplied to nitrogen, it results in the formation of{{\text{N}}^(2 + )}, not {{\text{N}}^(3 - )}. So {{\text{N}}^(3 - )} cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to {\text{F}}{{\text{e}}^(3 + )} is iron. If second ionization energy is supplied to the iron atom, it results in the formation of {\text{F}}{{\text{e}}^(2 + )}, not {\text{F}}{{\text{e}}^(3 + )}. So  {\text{F}}{{\text{e}}^(3 + )} cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to {{\text{S}}^(2 - )} is sulfur. If second ionization energy is supplied to the sulfur atom, it results in the formation of {{\text{S}}^(2 + )}, not {{\text{S}}^(2 - )}. So {{\text{S}}^(2 - )} cannot be formed by providing the second ionization energy to the neutral atom.

Therefore, the only ion that can be formed by supplying the second ionization energy is {\text{C}}{{\text{a}}^(2 + )}.

Learn more:

1. Which is the oxidation-reduction reaction:

brainly.com/question/2973661

2. What is the mass of 1 mole of viruses: brainly.com/question/8353774

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Periodic classification of elements

Keywords: second ionization energy, Ca2+, N3-, Fe3+, S2-, IE1, IE2, first electron, second electron, neutral atom., nitrogen, calcium, iron, sulfur.

Calculate ℰ° values for the galvanic cells described below. (a) cr3+(aq) + cl2(g) equilibrium reaction arrow cr2o72-(aq) + cl -(aq) v (b) io3-(aq) + fe2+(aq) equilibrium reaction arrow fe3+(aq) + i2(aq)

Answers

Answer:

\boxed{\text{(a) 0.00 V; (b) 0.424 V}}

Explanation:

We must look up the standard reduction potentials for the half-reactions.

                                                                    ℰ°    

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O     1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻                                       1.35827

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O             1.195

Fe³⁺ + e⁻ ⇌ Fe²⁺                                      0.771

(a) Cr³⁺/Cl₂

We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.

                                                                                  ℰ°/V    

2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻                  -1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻                                                     1.358 27

2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻  + 6Cl⁻ + 14H⁺     0.00

(b) Fe²⁺/IO₃⁻

                                                                            ℰ°/V

Fe²⁺ ⇌ Fe³⁺ + e⁻                                                -0.771

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O                      1.195

10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O     0.424

The ℰ° values for the cells are \boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}

Answer:

Answer:

\boxed{\text{(a) 0.00 V; (b) 0.424 V}}

Explanation:

We must look up the standard reduction potentials for the half-reactions.

                                                                   ℰ°    

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O     1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻                                       1.35827

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O             1.195

Fe³⁺ + e⁻ ⇌ Fe²⁺                                      0.771

(a) Cr³⁺/Cl₂

We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.

                                                                                 ℰ°/V    

2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻                  -1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻                                                     1.358 27

2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻  + 6Cl⁻ + 14H⁺     0.00

(b) Fe²⁺/IO₃⁻

                                                                           ℰ°/V

Fe²⁺ ⇌ Fe³⁺ + e⁻                                                -0.771

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O                      1.195

10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O     0.424

The ℰ° values for the cells are \boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}

Explanation:

its right trust

How does the hydrogen atom produce light

Answers

when energy is put into an atom, the electrons can use the energy to go to a higher energy state (n value) which is called an exited state.  when the electron goes back down to where it started (called the ground state) it releases the energy it gained in the form of a photon which is why it produces light.  
A common way to get hydrogen gas to produce light is by passing an electric current through the sample.