A ball rolls horizontally off a table of height 0.6 m with a speed of 9 m/s .How long does it take the ball to reach the ground?

Answers

Answer 1
Answer: The distance an object falls from rest is

                     D  =  (1/2) (gravity) (time)² .

If the ball falls 0.9 meter, then

                               0.9 m  =  (1/2) (9.8 m/s²) (time)²

Divide each side
by 4.9 m/s² :           0.9 m / 4.9 m/s² = time²

Take the square root
of each side:                time = √(0.9/4.9) sec²

                                              =        0.43 second .

The horizontal motion of the ball makes no difference.
It doesn't matter whether the ball rolls off of a table,
gets dropped from a hand, or shot horizontally from
a gun. It still hits the floor or the ground 0.43 sec later. 
Answer 2
Answer:

Answer:

.35 s

Explanation:

x = v(i)t + 1/2at^2

gravity = 9.81 m/s^2 = a

.6 m = 1/2at^2

(.6 m) * 2 = (1/2at^2)*2

1.2 m = at^2

(1.2 m)/a = (at^2)/a

0.12 s^2 = t^2

sqrt(.12 s^2) = sqrt(t^2)

.35 s = t


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Which type of radio waves have the highest frequency and are used in radar detection? microwaves x-rays waves infrared waves gamma waves

Answers

Answer: Microwaves

Explanation:

RADAR stands for radio detection and ranging.  Radio waves range from 300 GHz to 30 Hz. Modern radar uses higher frequency of waves for detection. These waves are microwaves (300 MHz-300 GHz). Microwaves are types of radio waves and are used in the radar detection.

The electromagnetic wave which has highest frequency is gamma wave but it is not used for radar detection.

Hence, the correct answer is microwaves are the type pf radio waves which have the highest frequency and are used in radar detection.

microwaves are a type of radio waves used in radar detection and they have the highest frequency.

Which spectral class does the sun belongs to

Answers

it belongs to a group named G-type stars 

I am one of the most dynamic processes of Earth. I help recycle Earth's materials. I move Earth's crustal plates, creating many different geological surface features. I am also the cause of natural disasters, such as earthquakes and volcanoes. What am I?

Answers


I Can only think of tectonic plates or gravity

Continental Drift.. ✌

A body with a mass of 2,000 kg is lifted to a height of 15 m within a time of 15 s. Which one of the following statements concerning the action is true?a. The gravity force on the body is 294,000 N.
b. The potential energy of the body is 30,000 J.
c. The amount of work is 450,000 J.
d. The power exerted is 19,600 W.

Answers

So we want to know which statement is true for the body of mass m=2000kg that is lifted to a height of h=15m in t=15 s. Lets calculate each of the following: Gravity force on the body is F=m*g=2000*9.81=19620 N so a is FALSE. Potential energy of the body when it is lifted to the height of 15 m is Ep=m*g*h=2000*9.81*15=294300 J so b is FALSE. Work to lift the body is: W=Fg*h=2000*9.81*15= Ep=294300 J so c is FALSE. Power P=W/t=294300/15=19620 W So d is TRUE.

Terminal velocity and Inicial velocity they are related???

Answers

Well the only relation they have is that they are both velocities.

The initial velocity of an object is the velocity it begins moving with. i. e if a ball is thrown its initial velocity is the velocity it has once it leaves the hand.

Terminal velocity is the maximum velocity an object can achieve when it is in free fall. i.e if a bowling ball is dropped from a plane, its velocity will increase until it reaches terminal velocity.

A body mass 30 kg is traveling in space at a speed of 10 m/s. Given that the formula for kinetic energyis KE = 0.5 * m * v^2, and m is mass, v is speed

Answers

The kinetic energy of a body with a mass of 30 kg and a speed of 10 m/s is  1500 kg m²/s².

In physics, the kinetic energy of аn object is the form of energy thаt it possesses due to its motion. In the case above, we are given the formula for kinetic energy:

KE = 0.5 * m * v²

where m is mass and v is speed. And we are given m = 30 kg and v = 10 m/s.

To calculate the kinetic energy, we simply plug in the values of m and v into the formula:

KE = 0.5 * 30 kg * (10 m/s)²

Simplifying the equation gives:

KE = 0.5 * 30 kg * 100 m²/s²

KE = 15 kg * 100 m²/s²

KE = 1500 kg m²/s²



Therefore, the kinetic energy of the body is 1500 kg m²/s².

For more information about kinetic energy refers to the link: brainly.com/question/26472013

#SPJ11

Answer:

The kinetic energy of a body mass of 30 kg traveling in space at a speed of 10 m/s can be calculated with the formula KE = 0.5 * m * v^2, where m is the mass of the body and v is the speed. In this case, the kinetic energy would be equal to 0.5 * 30 * 10^2 = 1500 Joules.