Witch expression is equivalent to 5x-30

Answers

Answer 1

Answer: 5(x-6) is because if you factor 5x-30, you can take out the number 5 from the two terms as a common factor and put it out of the parentheses.

Answer: 5(x-6)

Hope this helps :)

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Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

Answers

For this case we have the following expression:

$\frac {3} {\sqrt {17} - \sqrt {2}}$

We must rationalize the expression, so we multiply by:

$\frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}}$

So, we have:

$\frac {3} {\sqrt {17} - \sqrt {2}} * \frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}} =\n\frac {3 (\sqrt {17} + \sqrt {2}} {17- \sqrt {17} * \sqrt {2} + \sqrt {17} * \sqrt {2} -2} =\n\frac {3 (\sqrt {17} + \sqrt {2}} {15}$

Thus, the correct option is option B.

Answer:

OPTION B

Answer:

Step-by-step explanation:

To simplify something that looks like $\frac{\text{whatever}}{√(a)-√(b)}$ you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

$√(a)+√(b)$ .

If you had $\frac{\text{whatever}}{√(a)+√(b)}$ , then you would multiply top and bottom the conjugate of $√(a)+√(b)$ which is $√(a)-√(b)$ .

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens. The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First: a(a)=a^2

Outer: a(-b)=-ab

Inner: b(a)=ab

Last: b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of $√(17)-√(2)$ is

$√(17)+√(2)$ .

This is the thing we are multiplying and top and bottom.

Miles has a train collection with 36 engines 72 boxcars and 18 cabooses he wants to arranged the train cars in equal rows with only one type of train car in each row How many can he put in each row.

Answers

In order to find how many trains can be put in each row while having only one type of car in each row, you must find the GCF of all the numbers of cars.

First factor all three numbers
36 Engines= 2*2*3*3
72 boxcars = 2*2*2*3*3
18 cabooses= 2*3*3

Since each number contains at least 2*3*3, or 18, each row can be up to 18 train cars in length.
In this case, there will be 1 row of cabooses,
18 ÷18=1
2 rows of engines,
36÷18=2
and 4 rows of boxcars
72÷18=4

Steve had $2.50 in dimes in the pocket of his jacket. After walking for a half hour, he discovered he had a small hole in his pocket. Two dimes dropped through that small hole every 5 minutes. How much money did Steve have then?

Answers

there are 25 dimes in $2.50. And there are 60 minutes in and hour. if he dropped 2 dime every 5 minutes. And 60 divided by 5 is 12. so he would have dropped 2 dimes 6 times. So then you have to take 2x6 which is 12. then you would take 10x12=120. then 250-120=130 and then insert the decimal giving you $1.30. So he had $1.30 left. Hope this helped

the earth rotates about its axis once every 23 h 56 min 4 s, and the radius of the earth is 3960 mile. find the linear speed of a point on the equator in mi/h

Answers

$23h\ 56min\ 4s=\left(23+(56)/(60)+(4)/(3600)\right)h=\left((82800)/(3600)+(3360)/(3600)+(4)/(3600)\right)h\n\n=(86164)/(3600)h\approx23.93h\n\nL=2\pi R;\ R=3960mi\to L=2\pi\cdot3960mi=7920\pi mi\approx7920\cdot3.14mi\n\n=24868.8mi\n\nv=(24868.8)/(23.93)\ mi/h\approx1039.231\ mi/h\leftarrow answer$

Kacey is making a necklace that is 16 inches long. She uses 5 beads for every inch. How many beads will she need. How can i explain how to solve it ?

Answers

16 inches x 5 beads per inch is 80 beads total you would need to make a 16 inch necklace.

kacey is making a neklace long= 16
she uses bead for 1 inch= 5
she uses beads for 16 inches=16*5= 80

Solve −4 = −(−k − 86)+10

Answers

K= 100

You use distributive property

Step 1: −(−k)−1(−86)+10=−4

Step 2: k−1(−86)+10=−4

Step 3: k+86+10=−4

Step 4: k+96=−4

Step 5: k=−96−4

Step 6: Subtract 4 from −96 to get −100.

The first step -4=k-86-10 second- k-76=-4 third step 76-4= 72 substitute 72 in for k 72-76= -4 this is true

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