The function A(r)=πr^2 may be used to find the area of a circle with radius r. Find the area of a circle whose radius is 11 centimeters. Please help me ASAP!!!!!!! :(
Answers
Just evaluate the function: A(r) = πr² by substituting 11 in for 'r'
so A(11) = π(11)²
or Area = 121π
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PLZ HELP ASAP!! WILL MARK BRAINLIEST!If the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is completely simplified to 2xayb + 4xcyd, where a, b, c, and d represent integer exponents, what is the value of a? _______Numerical Answers Expected!
Answers
The word phrase "sixteen times the sum of 10p and seventeen" can be translated into the following algebraic expression 16(10p + 17)
The word "sum" means that we add 10p and 17. The word "times" means that we multiply the sum by 16.
Therefore, the algebraic expression 16(10p + 17) represents the phrase "sixteen times the sum of 10p and seventeen".
Here is a step-by-step translation:
Break the phrase "sixteen times the sum of 10p and seventeen" into smaller parts.
Translate each part into an algebraic expression.
Combine the algebraic expressions into a single expression.
The translated expression is 16(10p + 17).
To learn more about expression here:
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Answers
9514 1404 393
Explanation:
a) The velocity curve is linearly increasing from 0 to 6 m/s over a period of 2 seconds, then linearly decreasing from 6 m/s to 0 over the same period. The acceleration is the rate of change of velocity, so for the first half of the motion the acceleration is a constant (6 m/s)/(2 s) = 3 m/s². Similarly, over the second half of the motion, the acceleration is a constant (-6 m/s)/(2 s) = -3 m/s².
The distance traveled is the integral of the velocity, so the linearly increasing velocity will cause the distance vs. time curve to have a parabolic shape. The shape will likewise be parabolic, but with decreasing slope, as the velocity ramps down to zero. Overall, the distance versus time curve will have an "S" shape.
The motion (position and velocity) will be continuous, but the acceleration will not be. There will be a significant "j.erk" at the 2-second mark where acceleration abruptly changes from increasing the velocity to braking (decreasing the velocity).
__
b) The attachment shows the (given) velocity curve in meters per second and its integral, the position curve, in meters.
The integral in the attached works nicely for machine evaluation. For hand evaluation, it is perhaps best written piecewise:
Answers
Answer:
12 pieces
Step-by-step explanation:
80 pieces of candy
1/4 is 25% or 20 pieces of candy
10% would be 8 pieces of candy
subtract the two. Your answer is 12
Answer:
He had 14 more pieces
Step-by-step explanation:
So 80/4 is 20 pieces. So we know John has 20. Now she has 60 left since 80-20 is 60. Now 10 percent of 60 would be 6 pieces. We can subtract 6 from 20 to find out how many more pieces John had. 20-6 is 14. So John had 14 more than Lisa
END OF THE IPOD ERA
players are replacing the iPod, along with the category of device it helped to create. Sales of the iPod worldwide from 2007
through 2011 (in millions) were
approximately
N(0= -165t2 + 13.13t+ 39.9 (0 < t< 4)
in year t, where t= 0 corresponds to 2007. Show that the worldwide sales of the iPod peaked sometime in 2009. What was the approximate largest number of iPods sold worldwide from 2007 through 2011?
Answers
Answer:
a. t = 2.48 will be a period within 2009.
b. 56.16 million
Step-by-step explanation:
Here is the complete question
Apple introduced the first iPod in October 2001. Sales of the portable music player grew slowly in the early years but began to grow rapidly after 2005. But the iPod era is coming to a close. Smartphones with music and video
Apple introduced the first iPod in October 2001. Sales of the portable music player grew slowly in the
END OF THE IPOD ERA
players are replacing the iPod, along with the category of device it helped to create. Sales of the iPod worldwide from 2007
through 2011 (in millions) were
approximately
N(0= -2.65t2 + 13.13t+ 39.9 (0 < t< 4)
in year t, where t= 0 corresponds to 2007. Show that the worldwide sales of the iPod peaked sometime in 2009. What was the approximate largest number of iPods sold worldwide from 2007 through 2011?
a. Show that the worldwide sales of the iPod peaked sometime in 2009
N(t) = -2.65t² + 13.13t + 39.9
To find the maximum value of N(t), we find dN(t)/dt and equate it to zero
dN(t)/dt = d[-2.65t² + 13.13t + 39.9]/dt
dN(t)/dt = -5.3t + 13.13 = 0
-5.3t = - 13.13
t = -13.13/(-5.3)
t = 2.477
t ≅ 2.48
d²N(t)/dt² =d[-5.3t + 13.13]/dt = -5.3 < 0. So, t = 2.48 is a maximum point
Since t = 2 is 2009 and t = 3 is 2010, t = 2.48 will be a period within 2009.
b. What was the approximate largest number of iPods sold worldwide from 2007 through 2011?
The approximate largest number of ipods sold is when t = 2.48
N(2.48) = -2.65(2.48)² + 13.13(2.48) + 39.9
N(2.48) = -16.29856 + 32.5624 + 39.9
N(2.48) = 56.16384
N(2.48) ≅ 56.16 million
Answers
Answer:
The smallest possible whole-number length of the unknown side is
Step-by-step explanation:
we know that
The triangle inequality theorem, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side
Let
x-----> the length of longest side
Applying the triangle inequality theorem
case A)
Rewrite
case B)
The solution of the third side is the interval------->
but remember that
In an obtuse triangle
Round to a whole number
10^2 (10 squared) + 15^2 = C^2
100+225=c^2
325=c^2
√325
√25⋅13
√ 25 ⋅√13
5√ 13√325≈18.027756377319946
The whole number would be 5√ 13
It's the converse of the Pythagorean theorem.
Answers
Answer:
15 or -23
Step-by-step explanation:
I think you probably already turned this in but in case you haven't:
ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?
So there's two directions we could go.
Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)
But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)
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