What is the frequency of a sound wave commonly called?

Answers

Answer 1

Answer: Frequency of a sound wave is commonly referred to as pitch. That is the specialized name for frequency of a sound wave.

Just remember it as pitch.

Related Questions

A car slams on its brakes, coming to a complete stop in 4.0 seconds. The car was traveling south at 60.0 mph. Calculate the acceleration.
A large sphere has a mass of 175 kg and is suspended by a chain from the ceiling. The mass of the chain is 12.0 kg. What is the tension in the chain?1830, N1610, N1720, N1940 N.
The process by which water diffuses from a region of greater concentration to a region of lesser concentration is called
What would be the effect of doubling the rate of star formation, R*, on the results of the Drake equation?Drake equation: N = R* × ƒp × ne × ƒl × ƒi × ƒc × L A. There would be no difference in the results. B. There would be half as many extraterrestrial civilizations. C. There would be twice as many extraterrestrial civilizations. D. There would be four times as many extraterrestrial civilizations.
show how you would connect three resistors each of resistance 6 ohm so that the combination has a resistance of first 9 ohm second 4 ohm

Which type of bond occurs between water moleculesnonpolar covalent

metallic

hydrogen

ionic

Answers

$\textsf{O-H bond is covalent}\n\textsf{but H-H bond occurs between water molecules.}\n\textsf{answer is hydrogen bond}$

Answer:

This is the answer ˋ( ° ▽、° ) (☞ﾟヮﾟ)☞ Hope it helps. :)

Explanation:

After landing from your skydiving experience, you are so excited that you throw your helmet upward. The helmet rises 5.8 m above your hands. What was the initial speed of the helmet when it left your hands? Express your answer to three significant figures and include the appropriate units How long was it moving from the time it left your hands until it returned? Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

Initial velocity: approximately $10.7\; {\rm m\cdot s^(-1)}$ .

Time taken before return to initial height: approximately $2.17\; {\rm s}$ .

(Assumptions: $g = 9.81\; {\rm m\cdot s^(-2)}$ ; air resistance is negligible.)

Explanation:

Under the assumption, acceleration of the helmet would be constantly $a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)}$ .

During the interval between being thrown upward and reaching maximum height:

Initial velocity immediately after the person threw the helmet upward, $u$ , needs to be found.
Final velocity when the helmet reached maximum height is $v = 0\; {\rm m\cdot s^(-1)}$ .
Change in position over this interval is $x = 5.8\; {\rm m}$ .
Acceleration is $a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)}$ .

Apply the following SUVAT equation to find initial velocity $u$ :

$\begin{aligned} u &= \sqrt{v^(2) - 2\, a\, x} \n &= \sqrt{(0)^(2) - 2\, (-9.81)\, (5.8)} \; {\rm m\cdot s^(-1)}\n &\approx 10.668\; {\rm m\cdot s^(-1)} \n &\approx 10.7\; {\rm m\cdot s^(-1)}\end{aligned}$ .

(Round to three significant figures for the final result, but keep more significant figures for intermediary values.)

In other words, the velocity of the helmet was approximately $10.7\; {\rm m\cdot s^(-1)}$ immediately after the person threw the helmet upward.

Right before returning to the initial height, the velocity of the helmet would be the opposite of its initial velocity: $(-u) \approx (-10.7)\; {\rm m\cdot s^(-1)}$ .

The change in velocity would be:

$\begin{aligned}((-u) - u)/(a) &\approx ((-10.668) - 10.668)/((-9.81))\; {\rm s} \n &\approx 2.17\; {\rm m\cdot s^(-1)}\end{aligned}$ .

(Rounded to three significant figures.)

Final answer:

The initial speed of the helmet was 10.7 m/s and it was in the air for a total of 2.18 s.

Explanation:

This problem involves concept from physics specifically kinematics. Kinematics helps us study the motion of objects. To solve this problem, we need to use the second equation of motion: v²=u²+2as. In this case, the final speed (v) is 0 (when the helmet reaches the highest point, its velocity becomes 0), acceleration (a) is -9.8 m/s² (gravity acts downwards), and the distance (s) is 5.8 m.

Plugging in these values we get: 0 = u² - (2 * 9.8 * 5.8). Solving for u (initial velocity), we get u = √(2 * 9.8 * 5.8) = 10.7 m/s. This is the initial speed of the helmet when it left your hands.

To find out how long the helmet was in the air, we can use the first equation of motion: v = u + at. Solving for t (time), we get: t = (v - u) / a = (0 - 10.7) / -9.8 = 1.09 s going up. Because the time going up and coming down is the same, the total time the helmet was moving is 2 * 1.09 = 2.18 s.

Learn more about Kinematics here:

brainly.com/question/35140938

#SPJ2

When demonstrating the interference of light waves, the dark fringes that appear represent where the waves interfere _________________. A. Constructively
B. Not at all
C. Destructively
D. A little bit

Answers

The dark fringes that appear represent where the waves interfere

C. Destructively

Explanation:

Interference is a phenomenon typical of waves, that occurs when two waves meet at a certain point in space. The amplitude of the resultant wave can be found by using the principle of superposition, which states that the displacement of the resultant wave is the sum of the displacements of each wave. In particular, there are two extreme cases that can occur:

- Constructive interference: this occurs when the two waves meet in phase - i.e., the crest of one wave meets with the crest of the other wave. In this case, the amplitude of the resultant wave is twice the amplitude of each wave.

- Destructive interference: this occurs when two waves meet in anti-phase - i.e, the crest of one wave meets with the trough of the other wave. In this case, the amplitude of the resultant wave is equal to the difference between the two amplitues (and if the two waves have same amplitude, the resultant amplitude will be zero).

This phenomenon can occur also with light wave (which is a type of wave), and it leads to:

- The presence of bright fringes in case of constructive interference

- The presence of dark fringes in case of destructive interference

Therefore, the correct answer is

C. Destructively

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

Answer:

When demonstrating the interference of light waves, the dark fringes that appear represent where the waves are destructively interfere destructively.

Explanation:

The bright lines symbolize constructive interference and some dark lines symbolize destructive interference.

Interference does a phenomenon typical of waves, that occurs during two waves meet at a particular point in space. The amplitude of the resultant wave can do determined by using the system of superposition, which states that the displacement of the resultant wave equals the sum of the displacements of each wave. Inappropriate, two extreme cases can occur:

Constructive interference: that happens when the two waves participate in the state - i.e., the peak of individual waves agrees with each peak of each and every other wave. For this situation, the adequacy of this resultant wave infers double the abundancy from all waves.
Destructive interference: that occurs when two waves joins in anti-phase - i.e, the crest of one wave joins with the through of the other waves. In this case, the amplitude of the resultant wave is equal to the difference between the two amplitudes (and if the two waves have the same amplitude, the resultant amplitude will be zero).
This phenomenon can occur also with lightwave (which is a type of wave), and it leads to:
The presence of bright fringes in case of constructive interference
The presence of dark fringes in case of destructive interference

Therefore the correct answer is option C

To learn more about interface waves, refer:

brainly.com/question/16612684

a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at the bottom is 15 m/s. what is the lenght of the incline? how long does it take him to reach the bottom?

Answers

... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s

Is adding sugar to lemonade a chemical or physical change

Answers

physical.. think of it as a person putting on weight.. adding weight, but still a person. adding sugar, but still lemonade.

That's a physical change since nothing's really happening except for the flavor. Only the flavor changed cause you added something, but it's not a chemical

What is an electronegativities?

Answers

- is a measure of the tendency of an atom to attract a bonding pair of electrons.The Pauling scale is the most commonly used. Florine, is the assigned value of 4.0, and range down to cesium and francium which are least electronegative at 0.7 .

Hope this helped bro . COMMENT IF NOT THE RIGHT ANSWER ND ILL FIX IT .

Other Questions

The blood pressure in human body is greater at the feet than the brain

What is the importance of the ozone layer?

*PLEASE HURRY ITS FOR A QUIZ*A motorcycle and rider, having a total mass of 875 kg, are moving with a velocity of 15 m/s due east. What is the total momentum of the rider and cycle?A. 58 kg.m/s eastB. 60 kg.m/s eastC. 13.3 kg.m/s eastD. 13,125 kg.m/s east

Our solar system formed from a huge cloud of dust and gas called a _____.a. disk b. protostar c. solar nebula d. planetesimal