Competitive inhibitor affects the initial rate but do not affect the maximal rate.
Competitive inhibition is interruption of a chemical pathway owing to one chemical substance inhibiting the effect of another by competing with it for binding or bonding.
A competitive inhibitor is any molecule that can bind to the active site of an enzyme with sufficient affinity such that it can compete with the enzyme's natural substrate and reduce enzyme activity as a result.
Competitive enzyme inhibitors possess a similar shape to that of the substrate molecule and compete with the substrate for the active site of the enzyme. This prevents the formation of enzyme-substrate complexes.
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Answer:
competitive
Explanation:
Answer:
The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.
Explanation:
From the given information:
For food source A; we have:
3P₁ + P₂ + 2P₃ = 58 units of food A ---- (1)
For food source B; we have:
2P₁ + 4P₂ + 2P₃ = 70 units of food B ---- (2)
For food source C; we have:
P₁ + P₂ = 20 units of food C ----- (3)
From equation (1) and (2); we have:
3P₁ + P₂ + 2P₃ = 58
2P₁ + 4P₂ + 2P₃ = 70
By elimination method
3P₁ + P₂ + 2P₃ = 58
-
2P₁ + 4P₂ + 2P₃ = 70
P₁ - 3P₂ + 0 = - 12
P₁ = -12 + 3P₂ ---- (4)
Replace, the value of P₁ in (4) into equation (3)
P₁ + P₂ = 20
-12 + 3P₂ + P₂ = 20
4P₂ = 20 + 12
4P₂ = 32
P₂ = 32/4
P₂ = 8
From equation (3) again;
P₁ + P₂ = 20
P₁ + 8 = 20
P₁ = 20 - 8
P₁ = 12
To find P₃; replace the value of P₁ and P₂ into (1)
3P₁ + P₂ + 2P₃ = 58
3(12) + 8 + 2P₃ = 58
36 + 8 + 2P₃ = 58
2P₃ = 58 - 36 -8
2P₃ = 14
P₃ = 14/2
P₃ = 7
Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.
anterior
posterior
Superior
Distal
Inferior
The anatomical terms are used to define the anatomical positions. The LLQ (Left lower quadrant) is located inferior to the LUQ (left upper quadrant). Thus, option e is correct.
Anatomical terms are used to define the exact position and location of the organs and the structures of the body in reference to each other. They are the directional terms that provide the details of the direction an organ is situated at.
The directional anatomical terms include superior, inferior, posterior, anterior, distal, proximal, caudal, occipital, peripheral, central, etc. The LLQ (Left lower quadrant) is the abdominal section that is located below the LUQ (left upper quadrant).
The anatomical term inferior is used to show the structure that lies below the reference organ. On the other hand, the superior shows above, the posterior shows behind, the anterior shows the front area, and the distal shows structures located further away from the origin.
Therefore, option e. the left lower quadrant is inferior to the left upper quadrant.
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In terms of human anatomy, the Left Lower Quadrant (LLQ) is considered to be inferior to the Left Upper Quadrant (LUQ). This refers to the LLQ's position being lower or below the LUQ.
In anatomical terminology, the Left Lower Quadrant (LLQ) is inferior to the Left Upper Quadrant (LUQ). The human abdomen is divided into four quadrants by two imaginary lines crossing each other at the naval: one vertical and one horizontal. The LUQ is the area on the left side above this intersection, whereas the LLQ is the area below. So in the context of positions and directional terms in human anatomy, 'inferior' means 'below' or 'lower than'.
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It produces genetically identical cells.
0 It provides a means of asexual reproduction.
O It allows for cell and tissue repair
Bacterial Population
Time
Which of these most likely explains why the bacterial population stopped growing?
The bacteria mutated from photosynthetic to carnivorous organisms and consumed one another until all the individuals were dead.
The bacteria reproduced in the system but eventually died due to limited resources
The bacteria became diseased and were unable to survive in the closed system
The bacteria competed for nutrients and died after all the nutrients were consumed
The statement that most likely explains the stop of bacterial populations to grow is the bacteria competed for nutrients and died after all the nutrients were consumed.
Bacterial growth may be defined as the proliferation of bacterium into two daughter cells, in a process called binary fission.
When there are enough nutrients in the petri dish, a rapid increase is shown in the graph, but during the course of time when nutrients become limited, it affects the growth of the bacterial population.
Therefore, the statement that most likely explains the stop of bacterial populations to grow is the bacteria competed for nutrients and died after all the nutrients were consumed.
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B - The bacteria competed for nutrients and died after all the nutrients were consumed
Answer:
The correct answer is option C.
Explanation:
The human gastrointestinal microbiota or the gut microbiota or the gut flora refers to the microbes, which thrive in the digestive tracts of humans. The human gastrointestinal tract comprises the gathering of all the genomes of gut microbiota. It is the niche where the human microbiota is found.
The microbial composition of the gut microbiota differs across the digestive tract. In the small intestine and stomach, very small species of bacteria are found, while the colon comprises the densely populated microbial ecosystem. Of these over 99 percent of the bacteria found in the gut are anaerobes, as the space within the intestines is highly anaerobic.
These microbes are confined deep within the body where oxygen cannot reach as it is not supplied with the help of blood vessels. Thus, a highly anaerobic environment is witnessed deep within the intestinal regions.
Example:
DNA : G T A C G C G T A T A C C G A C A T T C
mRNA: C A U G C G C A U A U G G C U G U A A G
Codons: AUG-CGC-AUA-UGG-CUG-UAA
Anticodons: UAC-GCG-UAU-ACC-GAC-AUU
Amino Acids: Methionone-Arginine-Isoleucine-Tryphtophan-Leucine
Using the example above, transcribe the following DNA strand into mRNA and translate that strand into a polypeptide chain, identifying the codons, anticodons, and amino acid sequence.
1. DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G
mRNA:
Codon:
Anticodon:
Amino Acids:
2. DNA: T T T A C G G C C A T C A G G C A A T A C T G G
mRNA:
Codon:
Anitcodon:
Amino Acids:
3. DNA: T A C G G G C C T A T A C G C T A C T A C T CA T G G A T C G G
mRNA:
Codon:
Anitcodon:
Amino Acids:
4. DNA: G T A C G C G T A T A C C G A C A T T C
mRNA:
Codon:
Anitcodon:
Amino Acids:
Transcribe the following DNA strand into mRNA and translate that strand into a polypeptide chain, identifying the codons, anticodons, and amino acid sequence.
DNA: C G A T A C A A T G G A C C C G G T A T G C G A T A T C C
Transcription occurs in the nucleus and translation occurs in the cytosol. Proteins are AUG-CUU-UAG / MET-PRO-VAL-VAL-ARG-ILE-LEU / MET-PRO GLY-TYR-ALA-MET-MET-SER-THR / MET-ALA-TYR-THR-LEU
----------------------------------
Transcription
→ adenine pairs uracil,
→ thymine pairs adenine, and
→ guanine pairs cytosine.
Translation
1.
DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G
mRNA: U A U G C U U U A G C G C U A G C G C C G C U A A G C C
Codon: AUG CUU UAG
here we recognize the start codon and a stop codon very close.
Anticodon: UAC GAA AUC GCG AUC GCG GCG AUU CGG
Amino Acids: MET - LEU
2.
DNA: T T T A C G G C C A T C A G G C A A T A C T G G
mRNA: A A A U G C C G G U A G U C C G U U A U G A C C
Codon: AUG CCG GUA GUC CGU UAU GAC
here we ONLY recognize the start codon but no stop codon.
Anitcodon: UAC GGC CAU CAG GCA AUA CUG
Amino Acids: MET - PRO - VAL - VAL - ARG - ILE - LEU
3.
DNA: T A C G G G C C T A T A C G C T A C T A C T C A T G G A T C G G
mRNA:A U G C C C G G A U A U G C G A U G A U G A G U A C C U A G C C
Codon: AUG CCC GGA UAU GCG AUG AUG AGU ACC UAG
here we recognize the start codon and one stop codon.
Anticodon: UAC GGG CCU AUA CGC UAC UAC UCA UGG AUC
Amino Acids: MET - PRO - GLY - TYR - ALA - MET - MET - SER - THR
4.
DNA: G T A C G C G T A T A C C G A C A T T C
mRNA: C A U G C G C A U A U G G C U G U A A G
Codon: AUG CGC AUA UGG CUG UAA
here we recognize the start codon and one stop codon.
Anticodon: UAC GCG UAU ACC GAC AUU
Amino Acids: MET - ALA - TYR - THR - LEU
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Related link: brainly.com/question/9598940?referrer=searchResults
Answer:
Explanation:
1. DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G
mRNA: U A U G C U U U A G C G C U A G C G C C G C U A A G C C
Codon: AUG-CUU-UAG-CGC-UAG-CGC-CGC-CGC-UAA- GCC
Anticodon: UAC-GAA-AUC-GCG-UAC-GCG-GCG-GCG-AUU-CGG
Amino Acids: Methionine-Leucine-Stop.
2. DNA: T T T A C G G C C A T C A G G C A A T A C T G G
mRNA: A A A U G C C G G U A G U C C G U U A U G A C C
Codon: AUG-CCG-GUA-GUC-CGU-UAU-GAC
Anitcodon: UAC-GGC-CAU-CAG-GCA-AUA-CUG
Amino Acids: methionine-glycine-histidine-glutamine-alanine-isleucine-leucine
3. DNA: T A C G G G C C T A T A C G C T A C T A C T CA T G G A T C G G
mRNA: A U G C C C G G A U A U G C G A U G A U G A G U A CC U A G C C
Codon: AUG-CCC-GGA-UAU-GCG-AUG-AUG-AGU-ACC-UAG
Anitcodon: UAC-GGG-CCU-AUA-CGC-UAC-UAC-UCA-UGG-AUC
Amino acids: Methionine-glycine-proline-tyrosine-alanine-methionine-methionine-serine-threonine.
4. DNA: G T A C G C G T A T A C C G A C A T T C
mRNA: C A U G C G C A U A U G G C U G U A A G
Codon: AUG-CGC-AUA-UGG-CUG-UAA
Anitcodon: UAC-GCG-UAU-ACC-GAC-AUU
Amino Acids: Methionine-arginine-isoleucine-tryptophan-leucine
5. DNA: C G A T A C A A T G G A C C C G G T A T G C G A T A T C C
mRNA: G C U A U G U U A C C U G G G C C A U A C G C U A U A G G
CODON: AUG-UUA-CCU-GGG-CCA-UAC-GCU-AUA
Anticodons- UAC-AAU-GGA-CCC-GGU-AUG-CGA-UAU
Amino acids: Methionine-leucine-proline-glycine-proline-tyrosine-alanine-isoleucine.